At 57:05 { predicting reaction feasibility 3 } , why is the E cell value negative ? As to the theory explained prior isn't (E cell = E reduced - E oxidised )
Great tutorial! Thx! But I have one question. In predicting reaction feasibility 3, E cell = 0.80 -2.00. But 0.80 is the potential of the "oxidised" half equation, right? How come it is not the other way round?
Same question because the cell potential is obtained by subtracting the reduced value from oxidised value. Here the reduced value is +2.00 and oxidised one is +0.80 if we subtract them both answer we get is +1.20
54:34 just clarifying that the Eo value for Fe2+ would not be doubled, right? Coz in the balancing of the equations they're being doubled but in the calculation of Eo cell it's not.
Depends on what they ask for. You are expected to balance a half equation using protons, water and electrons however sometimes they will provide you with a list of them if they want you to calculate E° values etc...
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Thank you soo much :) its so rare to find good videos for CIE
You're welcome 😊
In predicting reaction feasibility 3, i didn't understand how the E cell came to be negative
This came out at the perfect time. Thank you
Love from a A-Level international school in China❣
how is it oxidized - reduced for the e cell at 57:00
At 57:05 { predicting reaction feasibility 3 } , why is the E cell value negative ?
As to the theory explained prior isn't (E cell = E reduced - E oxidised )
Awesome explanation, really appreciate your effort! ❤
Thanks a lot 😊
Woah.This was a crazy topic, understood nothing in the first half and everything started making sense in the next half of video.😅
Great tutorial! Thx! But I have one question. In predicting reaction feasibility 3, E cell = 0.80 -2.00. But 0.80 is the potential of the "oxidised" half equation, right? How come it is not the other way round?
Same question because the cell potential is obtained by subtracting the reduced value from oxidised value. Here the reduced value is +2.00 and oxidised one is +0.80 if we subtract them both answer we get is +1.20
Hope you reach 100k subs asap. You deserve it! Best wishes.
Thanks! We did hit 100,000 on Sunday 😃
@@AlleryChemistry Congrats!! Wish you the very best, sir.
A brilliant video it is🙏
Thank you sir
what about ion ion half cells, metal metal half cells and non metal non metal half cells?
Thank you so much !!!
You're welcome!
sir can u make a video on what happens when concentration of substances in half cell changes related to the E value
54:34 just clarifying that the Eo value for Fe2+ would not be doubled, right? Coz in the balancing of the equations they're being doubled but in the calculation of Eo cell it's not.
no they wont be. Balancing never effects Eo Values
A marathon indeed but a very informative one
Glad it was helpful!
Sir, will the half-equations be always provided? Or do we sometimes need to construct it by ourselves? :')
Depends on what they ask for. You are expected to balance a half equation using protons, water and electrons however sometimes they will provide you with a list of them if they want you to calculate E° values etc...
@@AlleryChemistry Thank you so much sir! Words are not enough to describe how much you are helping me with Chemistry. God bless you!!! 😭😭💜💜
This topic is such a trouble for students who don’t take physics😢but your explanation is so helpful!!!
You're welcome 😊
Thankss
You're welcome! 😊
great video thanks g
No worries
mistake at 56:41 reaction is feasible + sign
My least favourite topic, but thank you for explaining it so well