Bro your work is outstanding. It is so easy to understand keep the good work up and please improve the video quality a little bit more because some times it starts focusing the board due to which the whole screen remains blurred.
If u check carefully . The summation was from -infinity to 0 . Then I have put n=-n and the limit changed from 0 to infinity . So when you are talking abt GP the summation should be from 0 to infinity . Now when I put n=-n the term 2^n wil become 2^-n . Which is equal to (1/2)^n . And 1/2 is
In problem 1 how do you figure that DTFT will be real valued over entire period. For Omega equal to 0, pi, -pi sin(Omega) is zero, but for other values of Omega wouldn't it make the DTFT value complex ?
Hi Brother! I'm having an doubt. That is in 6 th problem according to frequency differentiation -jomega should be multiplied with x(n) know. But to find n u(n) you have multiplied -j with nu(n). Is this correct.
You have done a mistake while computing the DTFT of u[n]. The GP relation for summation over all n values , for a^n = 1/(1-a) does not hold for |a| = 1, it only holds for |a| < 1. Refer some good books before making videos. But good effort though.
You are the BEST on Signals and Systems... definitely
thank you :)
Your tutorials are so helpful in signal processing. Thank you.
Life saver really... Thank you so much please continue to share your knowledge!! Bless you!!
Thanks
Thank you
i can hear the Adhan in the background :D 7:50
I too
The answer for unit step function is wrong because the summation diverges. An extra term is to be added in the solution. The video was really helpful.
MAMIDIPALLI KRISHNA yeah constant term has to be added
what bro full onnnnn
really the concepts are explained in a very good manner ... easy to understand
Really you are the best in what i really want superb Excellent
thank you for making these videos, without them i would be lost ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Welcome
Hola! Muchas gracias por tu tiempo y compartir tus conocimientos. Saludos desde México.
De nada. Compártelo con las personas necesitadas. :)
Its really good sir ...i was so much confused with lots of tiny doubts...which is almost done....here ....thank u sir...👍👍👍
Welcome !
Bro thank you😍😍😍.. Ur explanation is more simpler than the lectures in our clg.. We want more videos like this from you...
I have uploaded all the videos . Check my playlist bro 😎
Good one . Keep doing good work 😎
you teach better than my uni teachers
Thanks 👍
this was so helpful. thank you very much. please continue this good work
Sure . Share it with ur friends in need .
Thank you sir.... It was very helpful
who bunked online classes and came to study here for exam😁
Ha ha . All the best
fell the same bro
Very nice and helpful
nyc one sir
Thats very good ....,and try to explain things physically that will make sense.... great
I heard Adhan inthis lecture
Excellent sir
Thanks
Sir thank u so much.. Superb lecture👌😊
plz explain why the interval is from -pi to pi ( 4:04)
Vỹ Nguyễn Hoàng Quốc DTFT is periodic with period 2pi !
It is very helpful sir. thankyou
Bro your work is outstanding. It is so easy to understand keep the good work up and please improve the video quality a little bit more because some times it starts focusing the board due to which the whole screen remains blurred.
Got you 🙂 thanks for the compliments.
@@techjunkiejdb5476 Wellcome
Great efforts! but a suggestion, please lock the focus and expo. while recording any video and see the magic.
Thanks . I have sorted it out in my other videos 👍
@@techjunkiejdb5476 Cool
Sir, I think the differentiation frequency property used in last question is wrong. Please confirm.
Bk Singh sahi hai bhai
Can you tell me which reference you are using
Internet
i dont know how to thank you for such a greayt work sir!!!
Naman Jain welcome
I need videos on dsp can u pls teach that?
Sir can I please say how to find the dtft for the signal u(n-2)
swathi pradeep use shifting property . I have done similar problem in the same video . It will be e^-2omega * dtft of u(n)
@@techjunkiejdb5476 thank you sir
i had a doubt, in the 2^n * u(-n), you applied the formula of infinite GP sum. But isn't that only valid when |ratio| < 1 but here |ratio| is 2
If u check carefully . The summation was from -infinity to 0 . Then I have put n=-n and the limit changed from 0 to infinity . So when you are talking abt GP the summation should be from 0 to infinity . Now when I put n=-n the term 2^n wil become 2^-n . Which is equal to (1/2)^n . And 1/2 is
@@techjunkiejdb5476 Oh yes! Thank you so much for clearing my doubt ♡♡
@@akshettrj no problem 👍
In problem 1 how do you figure that DTFT will be real valued over entire period. For Omega equal to 0, pi, -pi sin(Omega) is zero, but for other values of Omega wouldn't it make the DTFT value complex ?
Sanjay R it will never be complex. Put the values in the interval of zero to pi . U will get the answer for ur question.
Thanks...so much sir
sir,please solve question number 6 by using the actual formula of DTFT ...please...
Thanks for it sir ☺️🙂
Welcome
thanks
Hi Brother! I'm having an doubt. That is in 6 th problem according to frequency differentiation -jomega should be multiplied with x(n) know. But to find n u(n) you have multiplied -j with nu(n). Is this correct.
No it’s right . Frequency differentiation property is -j n x(n) is differentiation of DTFT of x(n)
Q1 alpha can be negative. I think the question must have mod of alpha?
Sanyam Sharma true . There should be a correction .
How to do this problem (0.6)^|n| *(u(n+10)-u(n-11)) .
Burakkk Y it’s straight forward . I have done similar problems . Just the addition of three signals
@@techjunkiejdb5476 Thank you :)
At 15:00 you said lower limit of summation is 3 actually it is -3
It's 3 man.
How to do this problem ( 6(2)^n)u[n]?
It's a growing exponential so DFTF doesn't exist ✌️ basic necessary and sufficient condition of DTFT is not satisfied 😊
Lecture was pretty good undoubtedly but you should shoot videos with a better camera.
Sourav Roy I'll take care in future videos :)
u(n) ka wrong hai derivation. Jab apne Infinte GP ka sum karte hai alpha < 1 ke liye to , aap 1 kaise le sakte ho baad me alpha ka value
Devanshu haan galat hua hai . Change kardunga
Sir could u please do DSP lecture As I am not understanding in online class . Please I am requesting u to do DSP lecture 🙏🙏🙏🙏
Ok sure
Thank u
Sir . While you found DTFT of u(n) you made a mistake. You forgot Dc term of u(n)
Sir. ı have a question .For tihs reason ,how do ı do last quesiton because ı dont take dırac functıon of derivative
how to solve cosw0n
Convert cos in terms of exponential function.
thanks bro
muatur suwun ,,,..
Meaning ?
@@techjunkiejdb5476 thanks...
Really appreciate your lecture but please check the DTFT of u(n) . Reply me soon
MAsti Madness is it wrong by any chance ?
DTFT OF U(n) is πdel(w)+1÷1-exp(-jw)
the GOD
😊 khushi ke aansoo 😊
Sir please solve this question
x(n) =sin(pie/4 n)(1/4)n u(n-1) find x(e^jw)
Using properties
Please sir
Mail me the question . techjunkiejdb@gmail.com
alpha=1/2 .... how
Which problem
@@techjunkiejdb5476 First problem.
alpha
@@rajuu_t that’s cos if alpha is greater than 1 then there is no DTFT .
wotrasi rash aayini sir :)
sir ji appne half jaypee students ko pass karaya hai ...
It's like same to z transform
Almost !
DTFT of x(n)=n(0.5)^2n u(n)
Need Answer ?☝️
You have done a mistake while computing the DTFT of u[n]. The GP relation for summation over all n values , for a^n = 1/(1-a) does not hold for |a| = 1, it only holds for |a| < 1. Refer some good books before making videos. But good effort though.