khanacademy, patrickJMT and now with TheIntegralCALC a triumvirate of online calculus knowledge is official, as far as I'm concerned. Thanks for this video, highly informative. This format kicks ass btw.
@behemothinferno I agree. There are almost always multiple ways to solve a calculus problem. Since I'm specifically trying to illustrate interval of convergence here, I use that method, but this example lends itself to the root test as well. If you know both, use whichever is easier for you! :)
@futuretronics OMG best news ever!! Not about the test, just about the videos being helpful. :) Well good luck on your final tomorrow. I'll keep my fingers crossed for you!! :D
I think you should revisit transition from step 3 to step 4 of the workout. Assuming that infinity divided by infinity is 1 is a wrong assumption. infinity divided by infinity is not defined. I think we could have used L'Hopital's rule to dodge that awkward step.
at 5:27 you said infinity over infinity will always simply to one. That is wrong because two infinity values could be different and therefore not equal to one. In this case, it is one because of L'hospital's rule on the indefinite form of infinity over infinity.
Please fix this video, infinity over infinity is Indeterminate form and instead of plugging in infinity, you could have just divide through with N and get 1 which is the best explanations. Thanks
hot girl teaching calculus? yes please. haha, seriously, thanks for the help. My professor is garbage and more concerned with his research than teach remedial math.
Thanks to this channel I got my BSc in Mathematics and Applied Mathematics from UCT the best university Africa and I got 96% for general relativity!!!!!thanks krista
L’hospitals rule isn’t needed for everyone talking about infinity over infinity. when taking a limit at infinity, there are rules. you take the highest power of the numerator and denominator, disregarding all other terms. if the highest powers are equal, you can divide the coefficients to get your limit. for example the limit at infinity for 5n^2+3/3n^2 would be equal to 5/3. however, if the power in the numerator is higher than the power in the denominator , the fraction is considered top heavy and the limit is infinity/DNE. for example, 3x^2/5x. if the power in the denominator is higher than the power in the numerator, then the fraction is considered bottom heavy and the limit will be 0. for example x^2/x^3.
Furthermore, if you want to avoid using L'Hospital's rule, though it's something every calculus student absolutely must know, you could divide the quotient n/(n+1) by (1/n)/(1/n), making it 1/(1+1/n). The limit of that is simply 1/(1+1/infinity) or 1/1, which is, of course, one.
I've never heard anyone explain this as eloquently as you did. You explained the exact reasoning behind each step and did a spectacular job. You are super amazing!
khanacademy, patrickJMT and now with TheIntegralCALC a triumvirate of online calculus knowledge is official, as far as I'm concerned. Thanks for this video, highly informative. This format kicks ass btw.
@behemothinferno I agree. There are almost always multiple ways to solve a calculus problem. Since I'm specifically trying to illustrate interval of convergence here, I use that method, but this example lends itself to the root test as well. If you know both, use whichever is easier for you! :)
@ohhhtravis You're welcome! :)
@Karmakameleeon I'm so glad! Good luck with those tests!! :)
@futuretronics OMG best news ever!! Not about the test, just about the videos being helpful. :) Well good luck on your final tomorrow. I'll keep my fingers crossed for you!! :D
Glad I could help!
I think you should revisit transition from step 3 to step 4 of the workout. Assuming that infinity divided by infinity is 1 is a wrong assumption. infinity divided by infinity is not defined. I think we could have used L'Hopital's rule to dodge that awkward step.
at 5:27 you said infinity over infinity will always simply to one. That is wrong because two infinity values could be different and therefore not equal to one. In this case, it is one because of L'hospital's rule on the indefinite form of infinity over infinity.
You're so welcome!! :D
Glad I can help! :)
infinity over infinity is an indertermined form, you cannot conclude that it is 1..
Htang Uvong If you applied l'hospital's rule with respect to n, you would end up with 1.
Thank you so very much
@thame2010 So glad I could help :)
Please fix this video, infinity over infinity is Indeterminate form and instead of plugging in infinity, you could have just divide through with N and get 1 which is the best explanations. Thanks
thank you for the help beautiful. God bless you.
Do you always start with ratio test for the first step?
yes! :)
@phardwick21 Haha yeah! I'm definitely workin on it... hope you like it! :)
Using the root test on this specific example is much quicker and simpler by the way
yes! :)
Yeah I agree, L'Hospitals is the best option
just only use alternating and p seris fir solution not other ths expain is very suprb thanksss
great slides!
@hickey23 Hey thanks! lol
hot girl teaching calculus? yes please. haha, seriously, thanks for the help. My professor is garbage and more concerned with his research than teach remedial math.
@InfiniteEP WOW!!! Thank you so much!!! :D
You're welcome! :)
thanks!
Thanks to this channel I got my BSc in Mathematics and Applied Mathematics from UCT the best university Africa and I got 96% for general relativity!!!!!thanks krista
L’hospitals rule isn’t needed for everyone talking about infinity over infinity. when taking a limit at infinity, there are rules. you take the highest power of the numerator and denominator, disregarding all other terms. if the highest powers are equal, you can divide the coefficients to get your limit. for example the limit at infinity for 5n^2+3/3n^2 would be equal to 5/3. however, if the power in the numerator is higher than the power in the denominator , the fraction is considered top heavy and the limit is infinity/DNE. for example, 3x^2/5x. if the power in the denominator is higher than the power in the numerator, then the fraction is considered bottom heavy and the limit will be 0. for example x^2/x^3.
@speedl3 Thank you so much!! Huge compliment, and I really appreciate it! :D
How would you find a power series when given specific intervals of convergence? Its pissing me off I don't really get how to do it without guessing.
wait ! isn't infinity over infinity inderminate form??
Yes, you can use L'Hospital's Rule within the cube root if you like.
being a perv saved me, that litteraly my assessment
@TheIntegralCALC Your most welcome ... I have my calc final tomorrow and you saved my life ;-)
Thank you very much, you're welcome!! :D
Thanks! I'm just so happy I can help. :)
@futuretronics Aww thank you!!! :D
what would the radius of convergence be? is it half of the interval of convergence?
It is for me, as it means so much!! :D
A billion gilllion thanks for your maths help. They are really first class.
@StSwift01 Glad you like it! :)
Big Thanks to you Krista King. You really help me a lot
You saved me!
Thanks ;)
I see you made quite an upgrade from the whiteboard.
the word (THANKs) is not enough for your efforts
Good going girl....i really liked ur video...
Thanks!
Furthermore, if you want to avoid using L'Hospital's rule, though it's something every calculus student absolutely must know, you could divide the quotient n/(n+1) by (1/n)/(1/n), making it 1/(1+1/n). The limit of that is simply 1/(1+1/infinity) or 1/1, which is, of course, one.
I've never heard anyone explain this as eloquently as you did. You explained the exact reasoning behind each step and did a spectacular job. You are super amazing!
I passed my Analysis II exam so I wanted to thank you for your lectures, they helped me a lot
Congrats! That's so awesome!
end point we cant cheked so to seen ths lecture now is so simple thanx maam so so i was worry
What are all the tests? Alternating, p-series, anything else?
nth term, geometric, p-series, integral, comparison, limit comparison, alternating, telescoping, ratio, and root! :D
that's a lot, but thanks!
infinity/infinity is not 1, this is indeterminate form
Great video! Thanks for all the help=)
what if you have two variables?
Those are power series ?
Thanks a lot for this vid. helped a lot. Nice teaching method (the software) its awesome!!! Thanks again!