Olympiad Maths - 18 වැඩ්ඩන්ට I Combined Maths I Ajantha Dissanayake

We warmly welcome you all to the GCE AL COMBINED MATHS series conducted by the well known combined maths senior lecturer Ajantha Dissanayake.
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[@Combinedmathswithpraveen]

මමත් සංයුක්ත ගණිත ගුරැවරයෙක් විදිහට ආදර්ශයට ගන්න විශිෂ්ට ගුරැ තුමෙක් ❤

[@engjayah]

Another approach as follows
t(t-1) = 3; hence t^2-t = 3
Now numerator N = t^3+1 = (t+1)(t^2-t+1) = 4(t+1); from which t^3 = 4t+3
Denominator D = t5-t4-t3-t2+2t+6 = t^3(t2-t-1)-(t2-t)+t+6; back substituting
D= 2(4t+3)-3+t+6 = 9(t+1)
Hence the result y = N/D = 4(t+1)/9(t+1) = 9/4

[@manjulathilakumara]

බොහොම පිං සර්

[@DulnithX]

Where do u find these questions. I am a o/l student and I really want to try more of these.
Thank you for these videos really helped me.. I love maths ;)

[@menukafernandopulle8228]

4/9

[@padminijayarathne30]

Sir හොදට තේරෙනව මම 9 වසරේ ❤️🔥🔥

[@wishwachamod7487]

Ane sir ol lesson tikakuth danna

[@kevinvideo8158]

dala thiyenne...godk video sir

[@WanMi_Sub]

Sir ol videos 57l dala thjiyenw blnn..

[@jayaweerasamantha5688]

Balapan gihin oya dala tiyenne 10:54

[@mystudio4467]

t ^ poduvata aran hadannath puluvanneda

[@maheshsushantha4783]

🔥

[@user-hw4lp7xk4v]

සුපිරි

[@anulakumari7131]

❤❤

[@ciiccci]

Sir hama sathiyema 1k danna plz .Patta asavak ava ganan Tika hadedi .mul evata vada passe Eva lassnata hadenava vade ahu unama .thank u sir
Mn oka haduve yata sadaka kadala
(T+1)(T^2-t+1)/T^3(t^2-1)-t^2(t^2-1)-2(t^2-t-3)
4/t^2(t-1)^2
T-1 =3/t nisa
4/9 kiyala enava

[@sameeradissanayake9773]

If "t" is not equal to 1

[@user-bx8mo8lh3y]

yoshitha uba beluwada meka??

[@sunilperera2643]

Pbbperera

T වලට අගයන් දෙකක් ගන්න පුලුවන්(ද?)

[@Nimeshasewmini974]

4/9

[@tharindukodikara8493]

4/9

[@NikeshiMiyulakshi]

4/9

[@Nppcj7wl]

4/9

[@CharithMadhushan-cb7qm]

4/9

[@prasannadevthilina4723]

4/9

[@sheshanadithya4051]

4/9