Frequently Asked Java Program 27: How To Count Words in a String
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- เผยแพร่เมื่อ 14 ต.ค. 2024
- Topic : How To Count Words in a String
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Easiest way to solve :
class Test{
public static void main(String [] args) {
String str = "hello walcome to java programming";
String []tokens=str.split(" ");
System.out.println(tokens.length);
} }
There is one more easy approach.
String str = “Welcome to the Java tutorials”;
String strArray[]=str.split(“ “);
System.out.println(“The number of words in a string is “ + strArray.length);
Good
@ it will work. Array declaration and initialisation have been done in one line.
This will not give a proper result if there is more than one space.
@@gautamkumarjha2686 String sentence = "Java easy peasy when we practise and explore";
String[] words = sentence.split("\\W+");
System.out.println(words.length);
The above regex will work.
Sir could you Pleasee guide me how to sort number of frequent words used in pdf document. because i want to learn the most important major words for exam would be very helpful 🙏🏽🙏🏽.
public static void main(String[] args) {
int count=1;
Scanner sc=new Scanner(System.in);
String s=sc.nextLine();
for(int i=0;i
correct
Well 👍👍 done bro thank you bhai
@@jansuraajpatnarohtashbuxarBiha Thanks
One more easy approach. String sentence = "Java easy peasy when we practise and explore";
String[] words = sentence.split("\\W+");
System.out.println(words.length);
In this case do we need to add loops also as above program
can we use this ?
String s1 ="This is a java program to find the words in the string";
String [] s2 =s1.split(" ");
System.out.println("Number of words are " +s2.length);
You can actually use the Scanner class for counting letters:
private static int cntWords(String phrase) {
Scanner in = new Scanner(phrase);
int cnt = 0;
while (in.hasNext()) {
cnt++;
in.next();
}
in.close();
return cnt;
}
@edbubble17 , you are awesome!!! never thought can do this using scanner class
int count = s.replaceAll(" ", "").length();
System.out.println(count);
i think this looks pretty easy
love you Sir for ur dedication to videos
Yes..I did same
String S = "Hidndustan India Ganga";
String [] words = S.split(" ");
System.out.println(words.length);
Hello Pavan sir,
This program fails if we haven't entered any string as input, the count is showing 1, bcoz by default count is 1. Another thing if the user entered multiple spaces as input then what logic needs to add to find the total count?
have u fount an answer for this?
Answer:
String st = "java programming java opps";
String a[] = st.split("\\W+");
for(int i=0; i
I think this can be an answer .
int count=0;
for (int i = 0; i < s.trim().length(); i++) {
if (s.trim().charAt(i)==' '&& s.trim().charAt(i+1)!=' ')
count++;
}
System.out.println((count != 0 ? (count + 1) : 0));
yes trim will help when we give space
import java.util.Scanner;
public class CountwordsinaString {
public static void main (String args []) {
Scanner in = new Scanner(System.in);
System.out.println(" Enter a String");
String str=in.nextLine();
int count=1;
for(int i=0; i
It's very easy solution...
Thanks brother...
You are most welcome
Awesome solution 👏🏾👌🏾👍🏽!!! Thanks for this!!!!
Welcome
Thank you sir ! Really Helped allot ❤❤
Welcome
i
For loop should be i
That's what i was thinking...
Here int is starting from 1....so s.length has taken
why its isn't mattering bro? if I am trying so it is giving error
@@haribol3383because it will not go the last letter of the string. It will find the space character always 2 or 3 characters before the last character. And the goal will be achieved.
some days earleir, Mr. Pavan had shared a link for a new youtuber for learning java and other stuffs.Do anyone know what is the name of the channel?
Teckstack9
@@sdetpavan thanks , but i cannot access in search button..can u share any video link plz?tia
there are one test case fail in your code ex." atue auah iaajja " output require=3 but your code output is 4
I have one doubt,If we have space in starting of the sentence,we need to keep cunt as 0,but t wont work for count 1.Please suggest!
Thanks ❤❤❤ sir
Welcome
why the count variable is intialized with 1 not zero?
one confusion : in if you used compare "==" for first condition and for 2nd "=" only assignment could you please explain
It's not a single"=" operator there. It's actually "!=" which means not equal to. hope this helps
Scanner sc=new Scanner(System.in);
System.out. println("enter string");
String s=sc.nextLine();
String a[ ] = s. split(" ");
System.out. Println(a. Length);
What if string is like "naman-singh"
It will count them single word i think
there are many test cases where it will fail not only this one.
Can it work....
Int a = s .replaceAll(" ", " ").length();
S.O.Pln("a");
If I want to count unique words in a string then what should be done
We can also use String tokeniser.
if more than one spaces occurs consequetively in between string like = "Welcome to java world" , then how to count words?
String str ="Welcome to java world"; just remove the space of string by str.replaceAll (\\s," ") ; method and then it will be like this Welcometojavaworld then use length method to get the count simple
public static void main(String[] args) {
String input = "today is a beautiful day";
String words[] = input.split(" ");
int count = 0;
for (String w : words) {
count++;
}
System.out.println(count);
}
The program fails if you give an empty string like this " "and also if you start the string with a space. How do you handle this scenario? Cuz count is initialized to 1.
For the second issue...We can add a trim() function.
If(i==0 &&charAt(I)! =' ') ||(str.charAt(i) ==' ' && str. charAt(i+1) ! =' '))
Use this condition u will get solution to your problem
Can we use string.replaceAll(); and count the sentence without spaces and then difference the original length
I was thinking so.. not sure of all scenarios
List companies = Arrays.asList("HCL","HCL","HCL","HCL","TCS","TCS","TCS","ZINNIA");
Write a program that returns the name of the company that has the maximum occurennce. for e.g. above list should print HCL
can i get ans. of this?👆
I'll give tomorrow
@@subhojitbiswas3876 you never came back bro...
Why length -1 pls explain simply
Nice 👍 explanation
Thanks
how can we put count =1; eg user doesn't want to put any word then still it will show 1 words which is not possible
Can any one find 2 letter words 3 letter words upto n letter words in given string using java
Sir could you Pleasee guide me how to sort number of frequent words used in pdf document. because i want to learn the most important major words for exam would be very helpful 🙏🏽🙏🏽.
How to get words not number of words ?
After getting words indicate their index values
thank you so much
Welcome
ONE MORE EASY APPRORACH JUST REMOVE THE SPACE BY REPLACE ALL METHOD AND THEN COUNT THE LENGTH OF STRING SIMPLE
Why should give two spaces s.charat (I)== ' '
Can somebody explain me how to count the number of "and" and "an" in a sentence with working
why count is kept as 1 instead of 0?
@Isha yadav vii b Ad no. 4679 if i make .length() not -1 and count is 0, its correct?
why count=1 ? sir
Nice video
Thanks
What if there is space at end
Make use of trim first
invalid charecter constant showing in first conditions ==' ' ,how to solve this sir anybody knows this
What if I start blank space before string.
Then you need to give int count= 0 instead of 1.
Why did you take count is 1 what will happen if we take 0 ? please answer my question... thank you
if we are taking count as zero(0) then it should return the number of words must be one less. because it should not count the first word.( we didn't consider the space before the first word)
Commenting for better reach
import java.util.*;;
public class Count_Word
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
String s = sc.nextLine();
String[] arr = s.split(" ");
int count=0;
System.out.println(Arrays.toString(arr));
for (int i = 0; i < arr.length; i++) {
if(arr[i]!="")
{
count++;
}
}
System.out.println("Number of word : "+count);
}
}
You can also try it ☺
well dooooooe
Thanks
Wow it's like a 🍰
import java.util.HashMap;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
System.out.print("
Enter a statement: ");
Scanner scan = new Scanner(System.in);
String statement = scan.nextLine();
scan.close();
String[] words = statement.split("\\s+");
HashMap wordHashMap = new HashMap();
HashMap letterHashMap = new HashMap();
for (int i = 0; i < statement.length(); i++){
char currentChar = statement.charAt(i);
if (letterHashMap.containsKey(currentChar)){
letterHashMap.put(currentChar, letterHashMap.get(currentChar) + 1);
} else {
letterHashMap.put(currentChar, 1);
}
}
for (Character letter : letterHashMap.keySet()){
int count = letterHashMap.get(letter);
System.out.println("Letter: " + letter + " appears " + count + " times.");
}
for (String word : words){
if (wordHashMap.containsKey(word)){
wordHashMap.put(word, wordHashMap.get(word) + 1);
} else {
wordHashMap.put(word, 1);
}
}
for (String item : wordHashMap.keySet()){
int count = wordHashMap.get(item);
System.out.println("Word: " + item + " appears: " + count + " times.");
}
}
}
import java.util.Scanner;
public class CountTheWords2 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a String");
String str = sc.nextLine();
int count = 1;
for(int i=0;i