I hope you might already have found out why. Anyway, it's because of the nature of the bisection method,; we always reduce the gap between x_n-1 and x_n by half, and replace either x_n-1 or x_n with the new mid value x_n+1 = (x_n + x_n-1)/2. To be more precise, if f(x_n)f(x_n+1)0 then we replace x_n with x_n+1 and repeat. If we f(x_n)f(x_n+1) = 0, we have arrived at the root.
thanks for this, my num methods professor makes it needless complex. thanks for the simple explanations and lecture notes.
Same! I was so lost in his class and frustrated badly.
Best introduction so far of this concept. Clearly explained and recapped
Thank you for this. I hope you can do some examples of numerical analysis.
We divide the intervals into halves but not the error. How come error in an iteration is half of the error in the previous iteration ??
2:45 why is xn not between xn-1 and xn+1
I hope you might already have found out why. Anyway, it's because of the nature of the bisection method,; we always reduce the gap between x_n-1 and x_n by half, and replace either x_n-1 or x_n with the new mid value x_n+1 = (x_n + x_n-1)/2. To be more precise, if f(x_n)f(x_n+1)0 then we replace x_n with x_n+1 and repeat. If we f(x_n)f(x_n+1) = 0, we have arrived at the root.
@ProfJeffreyChasnov thank you
God bless you!
how do i found p?
Thank you so much
Beautiful..
Plz help me
❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤