Frequently Asked Java Program 16: How To Check The Equality Of Two Arrays
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- เผยแพร่เมื่อ 13 ต.ค. 2019
- Topic : How To Check The Equality Of Two Arrays
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I like your tutorials. thank you very much!!
You are welcome!
if(a1[i] != a2[i]){
status = false;
break; // very important !!
}
sir, i think this is very easy logic ,,, just once check plzz...
//WAP to check if 2 arrays are equal or not using HashSet:
import java.util.HashSet;
class Check2ArraysEqual1
{
public static void main(String[] args)
{
int[] arr1={1,2,3,4,5};
int[] arr2={1,6,2,4,5};
HashSet hs1=new HashSet();
HashSet hs2=new HashSet();
for(int i=0;i
If one of your array size is not equal the where you put the else statement for that?
Commenting for better reach
public class HowToCheckArrayisequal {
public static void main(String args[]) {
int a [] = {1,2,3,4,5,6,7};
int a1 [] = {1,2,3,4,5,6,7,5};
boolean flag = true;
if(a.length==a1.length) {
for(int i =0;i
Nice sir..
Thanks
Another approach:
int[] arr01 = {2, 3, 5, 7, 11, 13, 17, 19, 23};
int[] arr02 = {7, 3, 5, 2, 11, 13, 17, 19, 23};
if (arr01.length == arr02.length) {
int counter = 0;
for (int element : arr01) {
for (int element2 : arr02) {
if (element == element2) {
counter++;
break;
}
}
}
if (counter == arr01.length) {
System.out.println("The two arrays are equal");
} else {
System.out.println("The two arrays are not equal");
}
} else {
System.out.println("The two arrays are not equal");
}
What are the pros and cons of using each strategy?
sometimes interviewer says that buddy dont use built in methods I want to see your logic building so............
@@atifasadkhan I am literally graduating school now lol
Missing break
🇮🇳🇮🇳🙏🙏👍👍
This logic shall work only when last value that is a[4] is not matching we get false, but if a1[0 to 3] not equal to a2[0 to 3] and a1[4]=a2[4] this logic should not work.
Hope this helps.
int[] arr = {1,2,3,4,5};
int[] arr2 = {1,2,7,4,5};
boolean flag = true;
if(arr.length == arr2.length)
{
for(int i = 0; i
No if once if statement will exicuted then it never becomes as true because after if statement there nothing to represent as true so for any index if if is executed once it is not equal if if is not executed then boolean value is remains as true
This logic works. as the if statement only executed if array value is not equal. the only thing i would suggest is we can add break after assigning status = false, when array size increase it would be to get results earlier:
int a1[] = { 1, 2, 3, 4, 6, 6 };
int a2[] = { 1, 4, 3, 4, 5, 6 };
boolean status = true;
if (a1.length == a2.length) {
for (int i = 0; i < a1.length; i++) {
if (a1[i] != a2[i]) {
status = false;
System.out.println("i: "+ i+ " status : "+status);
break;
}
}
} else {
status = false;
}
if (!status)
System.out.println("Arrays are not equal");
else
System.out.println("Arrays are equal");
public static void main(String[] args) {
int a[] = {1,2,3,4,5};
int b[] = {1,2,3,4,5};
int len=a.length;
int count=0;
if(a.length==b.length)
{
for(int i=0;i
public static void main(String[] args) {
int[] a1 = { 1, 2, 3, 4 };
int[] a2 = { 1, 1, 1, 4 };
int found = 0;
if (a1.length == a2.length) {
for (int i = 0; i < a1.length; i++) {
int no = a1[i];
System.out.println("====a1["+i+"]="+no);
for (int j = 0; j < a2.length; j++) {
System.out.println("====a2["+j+"]="+a2[j]);
if (no == a2[j]) {
found++;
}
System.out.println("found:"+found);
}
if (found > 1 || found == 0) {
System.out.println("no matching found.11.F:"+found);
break;
}
found = 0;
}
} else {
System.out.println("no match found.22...");
}
Your program is weird, This is easy example :-
int[] arr = {1, 2, 3, 6, 10, 9};
int[] arr2 = {1, 22, 3, 6, 10, 9};
boolean isArrayEqual = true;
for (int i = 0; i < arr.length; i++) {
for (int j = i; j < arr2.length; j++) {
if (arr[i] == arr2[j]) {
break;
} else {
isArrayEqual = false;
}
}
}
if (isArrayEqual) {
System.out.println("EQUAL ARRAY");
} else {
System.out.println("NOT EQUAL ARRAY");
}