Translating English Sentences to Logical Expressions
ฝัง
- เผยแพร่เมื่อ 7 ก.พ. 2025
- Discrete Mathematics: Translating English Sentences to Logical Expressions.
Topics discussed:
1) Solved questions about translating the English sentences into logical expressions.
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H/W prob. ans:
Domain : All students
P(x) : x students has taken more than 21 credit hours in a semester.
Q(x) : x received all A's
So,
∃x[P(x)^Q(x)]
I also got this...
Thoda doubt tha.about selecting the domain
Domain : All Students in the world.
P(x) : x student has taken more than 21 credit hours in a semester and received all A's.
Therefore, ∃x P(x)
What about this ?
so for exactly one student ( a student) it holds ? i thought it would need negation
Domain: All people
P(x): x is a student
s(x): x has taken more than 21 credits
q(x): x has received all "A"'
Ex(p(x)^s(x)^q(x))
is it correct?
plz reply I've an exam tomorrow
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Domain-all student
P(x):x >21 credits in semester
Q(x):x has recieved 'A' in all subjects
-】(p(x)^q(x))
i have a doubt a11:03 .if s(x) is =>x is richly coloured ,i think we can't say that not of x means x is dull in color .because not of x will mean not richly cololoured .it can also mean that the bird is "okay" coloured.
Really helpful, thanks!
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"no large bird live on honey"... is it wrong to negate the Q(x) instead of negating the R(x)?
Going to cross 1 million soon
Sorry very soon.
birds that do not live on honey are dullin color
can also be written as there exist some bird that does not live on honey and are dullin color
Domain: all people on the planet earth.
P(x): x is a student.
Q(x): x has taken more than 21 credit hours in a semester.
R(x): x has received all A's.
Ans: ∃ x [P(x) ∧ Q(x) ∧ R(x)]
"There exists x such that x is a student and x has taken more than 21 credit hours in a semester exam and x has received all A's."
Make videos on the computer organization & architecture
Ss .
You are a legend.
"isn't that so?"
Sir please complete discreet mathematics
7:30 (personal timestamp)
Thank you so much
Hello Sir Afaq.
Domain: All people.
S(x): x is a student.
P(x): x has taken more than 21 credit hrs in a sem.
Q(x): x has received all A's.
then
∃x (S(x) ^ P(x) ^ Q(x))
My answer is same. Is it correct? plz reply I've midterm exam tomorrow
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@@nesoacademy how much time it will take?
Thanks
Domain: Set of all the people on the planet
S(x) : x is a student
C(x): x has taken more than 21 credit hours in a semester
A(x): x has received all A's
∃x[S(x)^C(x)^A(x)]
Is this correct?
If not, please point out the error.
do dont have to take s(x) because x is already a student as you mentioned for C(x)..only take C(x) and A(x)...
@@codewithsankyy5738 Okay, thanks.
Domain : All students
Let P(x) = x has taken 21 credits
Q(x) = x has received all A's
Answer to 5:45 = ∃x [ P(x) ^ Q(x) ]
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sir pls provide us you are ppt notes.
Sir, can we write it as this way too? Hope you reply sir :)
Domain: All students
P(x) : "x has taken more than 21 credit hours in a semester."
S(x, y) : "x received y"
∃x[ P(x) ^ ∀y( S(x, y)) ]
You must define y,
Keep y as all A's not simple y
1st view..
Apti videos are awesome
Thank you :)
Koi he Chirst se??
Can we write like this : £ x p(x)
Where p(x): x has taken more than 21 credit hours in a semester and received all A's
Why are you talking so fast?
Watch in 0.75x
Asians have mastered the English language better than the English themselves!
You are slow
Lol I'm watching this in 2x 😂, having exam in 2 days.
I have tomorrow
Did bracket matters
yes ofcos
S(x) : is a student
M(x) : taken more than 21 credit hours
A(x) : received all As
∃x(S(x) ∧ M(x) ∧ A(x))
Thanks a lot