The clearest explanation of why you need cranck bars at the point of where the beam meets the column is the best explanation I have seen thus far even doing a structural engineering diploma course which is pretty good, but they never explained it where I got it instantly like this.
Clearly you fully understand the topic as the visual drawings are great. Although, I struggled to understand a few names at key points. I appreciate that teaching in a second language is no easy thing. Would love to have understood more (Y)
1)When do we provide cranked bars??? 2)do we need to cranked the steel bars which we r going to provide or we need to put an extra bar ??? 3)do every beams have cranked bar ? 4)In design steps of beam , is there any step for cranked bar ????
Sorry to as a question that might be silly....I don't have any background in civil engineering but I am getting a house constructed. So I have been watching some of your videos. As the position of the crank bar is where overlaps are not allowed, does it mean that no overlaps are allowed in a crank bar?
@@letslearntv2692 you're wrong mn. Common sense how can you connect the the top ang bottom bars if you only use .42 of the depth? It should be more than 100% the length of the depth
The diagonal distance (hypD) is 1.42D not 0.42D. D = Beam Depth - 2 x Cover - Tie Diameter [10mm or 0.394] D = 24in - 2x1.5in - 0.394in D = 20.606in NOTE: 45°, horizontal length = vertical length = D hypD² = D² + D² hypD = sqrt( D²+ D²) hypD = 29.141in k x D = hypD k = hypD / D k = 29.141 / 20.606 k = 1.42
Please review the length of cranked bar.. Its not actually the length of inclined bar.. 0.42D is the combine length along the base of complete base.. Review using basic Pythagoras theorem.. U have 45degree and perpendicular D. Soo inclination length comes to be D÷sin45 ... 0.42 comes after substitution of base length.. Because when you calculate bar length you already include base length taking length of span
@@sanjaykumar-dk8uw its wrong man. Think about this. If it is .42 of the Depth so .42×24=10.8, the distance of top and bottom bars is 21. So how will you connect that with only having 10.8 inches of length
I think you meant 1.41 and not 0.42? The hypotenuse of a right triangle can't be less in length than one of the sides of a triangle. You also did not explain why you need to crank the bar. Why not just have steel at the ends on the top and on the bottom for the middle. Why add the additional cost of cracking the bar?
If it's 45degree angle , then the length of Crank must be equal to Diagonal length , can be derived by Pithagorus theorem (Right angle triangle), i.e 1.42*d or 1.42*21". I Dnt think ur formula is right as per geometry atleast.
Sir would you please upload a video on how we decide the position on slabs as well as on beams to crank the bars.i mean thumb rules to find the location on beams and slabs where bars will be cranked
basically, it is the same. this method is prospected to be more economical than without cranks. however, some standard doesn't allow cranking more than 1:6. Also the bending skill on producing cranks like this is a bit hard (especially > 25 mm bars).
Yes....i have a similar confusion. If the angle is maintained at 45°, then the length of the cranked bar will automatically be determined..... but still 0.42 doesnot work...1.42 is correct
This is an outdated design . According to the design codes in the past more than 30 years , there is the requirement for certain amount of positive moment reinforcement to be anchored past the face of support . The anchorage past the face the support should be able to develop a force of 1.5x shear force at the support
الععمود مفروض سيحمل نصف حمل ال( beam) والوفية اجهاد من الاعلى على الكميرة وفية ردالفعل من العمود عزم المقاومة بنحسب الطو الخاص بالكمرة واسمة بحر الكمرة والخمل الواقى عليها ونحكسح الحديدفى الخمس والسبع ... ولو زادالارتفاع عن 60cm بنضع براندات لشد عوم الكانات باختصار خلص الكلام
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The clearest explanation of why you need cranck bars at the point of where the beam meets the column is the best explanation I have seen thus far even doing a structural engineering diploma course which is pretty good, but they never explained it where I got it instantly like this.
Again for the million time i came to a conclusion that youtube is better than all my professors !
:D
I never get this much information from my college. Thank you so much Sir. Thanks a lot. You are a very good teacher .
Thanks #Sasal
But, how am I supposed to 'earn' an honorary engineering degree if you don't upload the entire textbook?
Clearly you fully understand the topic as the visual drawings are great. Although, I struggled to understand a few names at key points. I appreciate that teaching in a second language is no easy thing. Would love to have understood more (Y)
Expertise in civil engineering here
The best explanation l have got on positive and negative bending moment of beam l clearly understood it now thanks
good
Absolutely dear
Thank you very much it helps a lot...there's a lot of confusions in rebars but you explained it so clear Godbless you
Glad it was helpful!
Great presentation of concept. Best explanation that i ever seen about actual concepts of reinforcement provision at beam and reason for that.
Engr Imam
Most of us learn the things from you tuber like u sir ..what's the role of colleges?
Masterclass
Thanks engineer👍
Welcome 👍
very important vedio, even it decrease wastage of Re-bares, for lapping and splice . 10Q a lot
Yes dear
Explicación super detallada MAESTRO. Felicitaciones
It is good explanation dear
Thanks for this video
Great sir
Excelent explanation, I was asking for it. Thank you.
Glad it was helpful!
Well done.!
Super, Wonderful
Thanks
Good information sir
Thanks
What as amazing teaching skills god has bestowed on u sir l have grasped the concept immaculately thank u gentleman
Wow, thank you
Thanks for the excellent webinar.Dr.V.Selvan,KCT,Coimbatore-49
Thank you so much.. very nice lecture sir
All the best
Thanks For Teaching Sir
It's my pleasure
Interesting! I am an avid fan of yours. I was learning everytime you uploaded new content. Thank you.
Happy to hear that!
very clear explanation.Thank you very much sir.best of luck for you...amal from - sri lanka
Thanks AMAL
Ur explanation can easily understand thnks sir
Thank you
Thanks sir
Clearly understood concept in beam section
Super Sir really want this analysis sir♥️
Great
Nice
Thanks
well done virora..deer kha.. if you are pakhtoon then I hope you will must be like it :-)
Thank you Sir.
🙏🙏🙏
Most welcome
Wow thanku you I understand well
I like it
Excellent ,
Thanks
Nice explanation video sir thank you for this video sir
1)When do we provide cranked bars???
2)do we need to cranked the steel bars which we r going to provide or we need to put an extra bar ???
3)do every beams have cranked bar ?
4)In design steps of beam , is there any step for cranked bar ????
Excellent Effort! Keep Rocking
good
Thanks
superb explanation...thank u sir
Good explanation!
Pl.ae
Share all your videos
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You're welcome!
Thanks bro
Nice content this is usefull for us
Thanks #Sibil
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Welcome
Can you upload how to calculate a concrete slab on piles straight with no culmbs like a bridg in water or a ro ro platform please 🙏
Oky
Sorry to as a question that might be silly....I don't have any background in civil engineering but I am getting a house constructed. So I have been watching some of your videos. As the position of the crank bar is where overlaps are not allowed, does it mean that no overlaps are allowed in a crank bar?
Good
Thanks #Rose
Fantastic
Thnks alot sir
How did you calculate L = 0.42 *D ? which code did you follow?
Vert good, i didn't know that. i know pre constraint tensioning rebar beam.
Sir , please do some videos about how to calculate the total length of a bend up bars with hook and tell some interview questions too....
I will #Sasal
Thank u sir
Excellent
Thanks
It's √2D i.e. 1.42D not 0.42D because cranked bars are bent at 45 degree.. It's simple trigonometry
Sital Joy he is correct man. It’s is 0.42D only not 1.42.D.. D indicates depth of the beam
@@letslearntv2692 you're wrong mn. Common sense how can you connect the the top ang bottom bars if you only use .42 of the depth? It should be more than 100% the length of the depth
You are correct. His formula has the bend shorter than the depth of the beam.
If i had learned this before at the University...
Where provide crank bar in plint beam
Sir nice video but I have doubt how can 8.8 inch bar can reach bottom of 1.5 inch in slanting conditions please explain me
I am agree with gopal and think the same.
La respuesta correcta es 21"x0.7071=29.7". Creo que esto fué a ver si ponen atención.
The diagonal distance (hypD) is 1.42D not 0.42D.
D = Beam Depth - 2 x Cover - Tie Diameter [10mm or 0.394]
D = 24in - 2x1.5in - 0.394in
D = 20.606in
NOTE: 45°, horizontal length = vertical length = D
hypD² = D² + D²
hypD = sqrt( D²+ D²)
hypD = 29.141in
k x D = hypD
k = hypD / D
k = 29.141 / 20.606
k = 1.42
Exactly
Please review the length of cranked bar..
Its not actually the length of inclined bar..
0.42D is the combine length along the base of complete base..
Review using basic Pythagoras theorem..
U have 45degree and perpendicular D.
Soo inclination length comes to be D÷sin45
...
0.42 comes after substitution of base length..
Because when you calculate bar length you already include base length taking length of span
Bro there is no problem with length of span...use D only and find length of crank bar and I think D is depth of beam
@@sanjaykumar-dk8uw its wrong man. Think about this. If it is .42 of the Depth so .42×24=10.8, the distance of top and bottom bars is 21. So how will you connect that with only having 10.8 inches of length
Sir, how to place his crank bar for a rcc beam which is upstanding (above slab) 13" (with slab 5" = 18").
Beam Length is 20'
Whether we should provide single crank or double crank bar in a beam??
depends on designer
Distance of column is 4m each
how to know at what distance the crank should be made?
I think you meant 1.41 and not 0.42? The hypotenuse of a right triangle can't be less in length than one of the sides of a triangle.
You also did not explain why you need to crank the bar. Why not just have steel at the ends on the top and on the bottom for the middle. Why add the additional cost of cracking the bar?
You are right sir
If it's 45degree angle , then the length of Crank must be equal to Diagonal length , can be derived by Pithagorus theorem (Right angle triangle), i.e 1.42*d or 1.42*21".
I Dnt think ur formula is right as per geometry atleast.
Where u put lapping in the slabs
Show me your video ok i am looking
Sir would you please upload a video on how we decide the position on slabs as well as on beams to crank the bars.i mean thumb rules to find the location on beams and slabs where bars will be cranked
Yes well said
Are cranked bars required if the beam is laid on earth soil?
Not necessary
What’s the name of music played in the start of video??
Formula for bend length is incorrect. Should be 1.42 x D
What are effect if used two tops over two pillars instead of CRANKS!
DOES IT SAME EFFECT OR NOT?
PLEASE RESPONSE
basically, it is the same. this method is prospected to be more economical than without cranks. however, some standard doesn't allow cranking more than 1:6. Also the bending skill on producing cranks like this is a bit hard (especially > 25 mm bars).
Perdón es 21/0.7071=29.7, o sea 21/sen45°=29.7. Tambien puede ser 1.414x21=29.7.
What should be the angle made for crank bars?
Ravi Shankar 30 or 45
Depend on shallow and deep slab
Length of cracked bar is 29.68" Is fit
@@shobanbabuketavathu5783 how?
45°
Clear cover: 3", Overall Depth of the beam: 6', D= 6'-3"=29.69"
D=0.525mm, Angel=45°
√(.525^2+.525^2) =0.742
Crank length is.0.742mtrs is equal to
29.69"
I am curious why not three bars with the top two over lapping the bottom?
0.42D may not be correct
Diagonal length will be more than D
so what about using 3-4" galvanized nails mixed in the cement batch for the cost savings in time one could add 100% more steel in mass ..
👍👍
My question is "if its placed in whatever angle i.e 45° in this case, then the length of the cranked will automatically be determined...right??
Distance is offset of the crank but what is that point from midspan? 1/3rd?
Is it possible to remove the diagonal beam i. e which is put at 45°
Or is it a different type of crank bar design. Can you differentiate their function.
How inclined length of crank bar is less than half( 0.42) of straight depth. I think there is some correction.
It's √2D or 1.42D not 0.42D.
Simple trigonometry calculation
@@sitaljoy307 √2d only for 45° right angle triangle.
@@sitaljoy307 video thumbnail itself showing length is 0.42D.
@@jagadishk639 for whatever angle provided cranked bar length is always greater than D.. Any value less than D is impractical
@@sitaljoy307 I am asking for that correction 😁
❤❤❤❤❤❤
👍👍👍👍
Sound is very low n not clear...
What about columns bending movement? Can crank transfer directly from a column to another? Today lifted bars...
Yes determined by advanced moment frame analysis as Finite element analysis method etc.
Is there any anchor bars in the upper side
2 compression bars must be there, other bars depends on your design
Youre placing your crank bar at the opposite. A crank bar is just the same design as a lift spring of a vehicle or the arc of an old bridge.
Crank bends,
8.8 " does not fit within your (24' -3") = 21" height beam.
Yes
Gopal Va'er 59
Yes....i have a similar confusion. If the angle is maintained at 45°, then the length of the cranked bar will automatically be determined..... but still 0.42 doesnot work...1.42 is correct
@@anieschaudhary7684 comon guyz create a square at 21 inch x 21 inch find the length between 2 points
there u go
0.42 x D = Hypotenuse.
How come that D is longer than the hypotenuse. I think you miss + D sir.
This is an outdated design . According to the design codes in the past more than 30 years , there is the requirement for certain amount of positive moment reinforcement to be anchored past the face of support . The anchorage past the face the support should be able to develop a force of 1.5x shear force at the support
Sir ji crank length must be 1.42D not 0.42D.
YOU ARE WRONG SIR... Length of Cranked bar should be greater than D. So Length of Cranked bar = 1.42 D
The length of the crank bar should be 1.42 D not 0.42 D
الععمود مفروض سيحمل نصف حمل ال( beam) والوفية اجهاد من الاعلى على الكميرة وفية ردالفعل من العمود عزم المقاومة بنحسب الطو الخاص بالكمرة واسمة بحر الكمرة والخمل الواقى عليها ونحكسح الحديدفى الخمس والسبع ... ولو زادالارتفاع عن 60cm بنضع براندات لشد عوم الكانات باختصار خلص الكلام
the measure is not diagonal but horizontal , sorry
I guess the cranked bar is phasing out.
Use either 45 degree or 0.42d.not logical to use both lol