You can always put playback speed to 2x . I have had feedback asking to explain things slowly . Not every one is quick in grasping language and concept . I hope you understand 😊
It is given that the number is divisible by 7. ie 99*(x-z) is divisible by 7. Since 99 is 9*11 . x-z should have 7 as a factor (i.e x-z is divisible by 7) Since x and z are single digits, x-z is divisible by 7 means x-z is 7.
Will help, if you ask your doubts. Did you understand , given the statements , difference between the digit in the unit place and 100s place ( x - y ) will also be divisible by 7 ? You can only find two such x and y . (9,2) : since 9-2=7 is divisible by 7 (8,1) : since 8-1=7 is divisible by 7 Now, we have to find how many digits starting with 9 and ending with 2 are divisible by 7 . Similarly we have to find how many numbers starting with 8 and ending with 1 is divisible by 7 . Did you understand upto this ? If you ask doubts, I will try to clear your doubts.
Will try to improve when making new videos. I'm not a teacher by profession. I'm sorry that it's not clear enough. but if you need help and ask doubts, I will try to answer them. Did you understand, given the statements, difference between the digit in the unit place and 100s place (x y) will also be divisible by 7? You can only find two such x and y (9,2): since 9-2=7 is divisible by 7 (8,1): since 8-1=7 is divisible by 7 Now, we have to find how many digits starting with 9 and ending with 2 are divisible by 7. Similarly we have to find how many numbers starting with 8 and ending with 1 is divisible by 7. Did you understand upto this ? If you ask doubts, I will try to clear your doubts.
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Good explanation , thank you
thank you
Yes, i understood
Thnq...🙂
Oh my god u r lagging behind in saying... Tested my patience 🤯🤯🤯
You can always put playback speed to 2x . I have had feedback asking to explain things slowly . Not every one is quick in grasping language and concept . I hope you understand 😊
99(x-z)
(x-z) is multiple of 7.. how to consider this..?
It is given that the number is divisible by 7. ie
99*(x-z) is divisible by 7. Since 99 is 9*11 . x-z should have 7 as a factor (i.e x-z is divisible by 7)
Since x and z are single digits, x-z is divisible by 7 means x-z is 7.
Didn't understand 😢
Will help, if you ask your doubts.
Did you understand , given the statements , difference between the digit in the unit place and 100s place ( x - y ) will also be divisible by 7 ?
You can only find two such x and y .
(9,2) : since 9-2=7 is divisible by 7
(8,1) : since 8-1=7 is divisible by 7
Now, we have to find how many digits starting with 9 and ending with 2 are divisible by 7 . Similarly we have to find how many numbers starting with 8 and ending with 1 is divisible by 7 .
Did you understand upto this ? If you ask doubts, I will try to clear your doubts.
Sorry to say but u need a bit of practice how to make the students understand of the particular concept...
Will try to improve when making new videos. I'm not a teacher by profession. I'm sorry that it's not clear enough.
but if you need help and ask doubts, I will try to answer them.
Did you understand, given the statements, difference between the digit in the unit place and 100s place (x y) will also be divisible by 7? You can only find two such x and y (9,2): since 9-2=7 is divisible by 7 (8,1): since 8-1=7 is divisible by 7
Now, we have to find how many digits starting with 9 and ending with 2 are divisible by 7. Similarly we have to find how many numbers starting with 8 and ending with 1 is divisible by 7.
Did you understand upto this ? If you ask doubts, I will try to clear your doubts.
Samjah nhi aaya 😤
I will try to help, if you explain where you had doubt ?