Sir why do you treat F(s) as constant , while solving the equations? It's varying with time '[f(t)]'......and with frequency [F(s)] If it is a variable then there will be three variables right sir?
Very good morning sir.I am very glad to see your videos. Sir a kind help.I beg up please recommend the text book in which these problems are available. Many of us are suffering without good books.Please suggest the book sir.Thank you
would please explain to me why you cross-multiplied but you ddnt bring[BS+K]^2 to the denominator? and even so we would be having the same value at the numerator and denominator therefore they'd cancel each other out
hey thanks buddy...l great explanation failed 4 times this subject but got confidence
i appreciate ur work
Perfect explanation. Saved me hours.😊
TO PASS IN JNTU UR VIDEOS IS MANDATORY ❤
Hi bro miku exams unnaya
HOO LAST YEAR E PASS AYA BRO CS@@ShaikFaizan-ht4ge
Superb explanation sir.. Thank you so much
Welcome🤗 and do share to your class group
Perfect Explanation keepitup
Well explained thank you so much♥️
Well explained thankyou sir 🍀
Thanku so much sir..that was very helpful
Thanks Bhai appreciate your work I like it
Sir want immediately reply, transfer function is output/input na sir. Then in problem it is f(S)/X1(S).
Watch this 20:14
Super explanation tqqq brother
Sir why do you treat F(s) as constant , while solving the equations? It's varying with time '[f(t)]'......and with frequency [F(s)]
If it is a variable then there will be three variables right sir?
Sir, please reply to this.....
Sir can you please answer this....
Superb!!!
this is gem!!!!!
Thank you brother. Learned it.
What do you mean by opposing force due to mass? Do you mean friction?
Very good morning sir.I am very glad to see your videos. Sir a kind help.I beg up please recommend the text book in which these problems are available. Many of us are suffering without good books.Please suggest the book sir.Thank you
Control system engineering by Nagoor kani
would please explain to me why you cross-multiplied but you ddnt bring[BS+K]^2 to the denominator?
and even so we would be having the same value at the numerator and denominator therefore they'd cancel each other out
you can find the LCM instead of cross-multiplying for better understanding. I hope this helps.
Thank you sir ❤
Very good
Can we solve the equations using Cramer's?
Tq sir ❤❤
Output will be force na sir ?
No cos we apply force....so force is given as input...and the displacement is the result of input...so displacement is the output
Exlent
Thank you so much sir
Thank you
hadsiiiiiii magna bere marker togo 💦......mansilayo💦
well
❤
20:13 TranSfErFuNcTIoN
Uyindoda nkabi, waishaya lento
Are kitna short diagram nhi chaiye modelling k 👎
Thank you
thank you so much sir