For taking out the homozygous dominant allele frequency why in the book they have taken the total number of heterozygote genotype number instead of taking half..
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The frequency of aa individuals must be equal to the square of the frequency of the recessive allele q. Let us suppose q = 0.5, then q2 - (0.5)2 = 0.25. In other words when aa phenotype is 0.25 in the population, then it follows that the frequency of the recessive allele a is √0.25 - 0.5. The frequency of the dominant allele A would be 1 - q or 1 - 0.25 = 0.75. How is this correct plz explain
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For taking out the homozygous dominant allele frequency why in the book they have taken the total number of heterozygote genotype number instead of taking half..
*Video paused* :- (3) answer
A= 0.6785 or 0.68
a = 0.32
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The frequency of aa individuals must be equal to the square of the frequency of the recessive allele q. Let us suppose q = 0.5, then q2 - (0.5)2 = 0.25. In other words when aa phenotype is 0.25 in the population, then it follows that the frequency of the recessive allele a is √0.25 - 0.5. The frequency of the dominant allele A would be 1 - q or 1 - 0.25 = 0.75.
How is this correct plz explain
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Last question????
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In the first question for bb genotype there should be 2 X 15, right?
Same for second question, 2 X 600, for MM genotype???
Nope
No one can understand what is number of individual and geno typic frequency,If any one know this concept then Last problem also easy
Is Calculator allowed in net
plz tell me the application date for csir net exam 2021
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first question wrong hai bcz if we 15/110 as q^2 then q is coming different
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Is this question help in neet??
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Thank u very much mam mughe pehli baar allele or geno freq me diff samagh aaya h ,Mam june 2020 wala que bhi solve karane pls
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