When a beam of white light strikes a triangular prism it is separated into its various components (ROYGBIV). This is known as a spectrum. The optical system which allows production and viewing of the spectrum is called a spectroscope. There are many other forms of light which are not visible to the human eye and spectroscopy is extended to cover all these.
Sir, you have a gift for teaching! As a former teacher and homeschooling mom of budding future scientists, I've spent the last few weeks scouring books and TH-cam trying to teach myself about spectroscopy. Hands down, this video is by far the best. I'd like to thank you! I am just confused about one section. At the 8:29 mark you introduce a spectrum of the sun with (what I believe are Fraunhofer lines) but I don't understand how the sun can be both a continuous spectrum (gives all visible light) and the pictures at 8:29 and you say our sun "is an absorption spectrum." Internet searches seem to say "In summary, the spectrum of the sun is both continuous and absorption. The source itself is continuous, but as it passes through the outer layers of the sun, it becomes partially absorbed, resulting in an absorption spectrum." Would you agree with this?
Thanks for your feedback. I’m glad my videos are useful. Yes I agree with that statement. I was referring to the sunlight that we received which is definitely an absorption spectrum, but as the text noted, the energy from the son’s core has to pass through the atmosphere come. God bless.
Thank you so much for the reply! Next, I'm going to try and understand the difference between spontaneous and stimulated emission and was delighted to learn you have a video on lasers. @@PhysicsHigh
Спасибо за доступное объяснение материала! Я из России. Жаль, что на русскоговорящей площадке мне не удалось найти стоящего контента, связанного с этой темой.
Do glass of hydrogen emission tube not interfere with lines because glass itself made of something so it should also absorbs or emit some wavelength of light ?
how do we dare feign to accurately assign colors to wavelengths within the "visible spectrum" we can't directly perceive??? 10:20 is there some inference or extrapolation or Fourier transform of sorts to prove our assignment is remotely correct? is it proven by wave interference theory?
5:59 gross concept error: our eyes are limited to activation by only three different wavelength intensities, i.e. red, blue, and green. the "visible" spectrum is just a trick, and we don't actually know which color corresponds to various wavelengths. we painted a false picture on a black and white mystery, until chemical sensors, aka photographic film, was made. even then, the colored rays corresponding to pure orange, yellow, purple, etc. will only appear as grey tones on the film.
Great video tnx! Is there a chance to get a hold of your amazing slides? I'd like to cite them in a workshop for some friends. Full credits would be given of course.
@4:20 I can't find any support that diffraction is what's behind the rainbow colors of soap bubbles. It's rather thin-film interference. It's not a matter of a small obstacle deviating light slightly from its straight path but rather a combination of reflection off two surfaces and constructive/destructive interference--leading to our preferentially seeing some frequencies over others. wired dot com/story/the-secret-to-soap-bubbles-iridescent-rainbows/ explainthatstuff dot com/thin-film-interference.html
This video doesn't explain WHY you are measure angle of the table spectrometer. I've played that part multiple times. d sin(theta)=m* Lamdi. So I conclude it is to measure the angle theta to solve for lamda and get the exact wavelength. But as a teaching video you should not have stipped that explaination.
I’m interested in your question. I don’t see a problem with it being organized in either direction. If you look at it from a wavelength point of view, it’s flipped from if you look at it from a frequency point of view. Typically when you’re dealing with radio waves, we talk about frequencies. I.e., 27 MHz is in the 11 m band. If we talk about light, we usually use wavelength because the numbers are easier to handle. This seems to me to be a place where convention works reasonably well, and that’s probably why he stuck around for so long. Comment?
If this level of introduction and explanation is typical of current high school practice, then it is no wonder that the students are lost. You tried to pack too much info into 21 minutes and wound up with a waste of time.
best video in the topic of SPECTROSCOPY
When a beam of white light strikes a triangular prism it is separated into its various components (ROYGBIV). This is known as a spectrum.
The optical system which allows production and viewing of the spectrum is called a spectroscope. There are many other forms of light which are not visible to the human eye and spectroscopy is extended to cover all these.
Thank you
Thanks for the video, I may have graduated from Highschool, but these videos are certainly good for revision.
That is a pretty clear explanation of spectroscopy. I remember many physics notions.
The fact developed countries have these machines in high schools is mind blowing for me.
Your videos are first class, thank you!!!
You're very welcome!
Sir, you have a gift for teaching! As a former teacher and homeschooling mom of budding future scientists, I've spent the last few weeks scouring books and TH-cam trying to teach myself about spectroscopy. Hands down, this video is by far the best. I'd like to thank you! I am just confused about one section. At the 8:29 mark you introduce a spectrum of the sun with (what I believe are Fraunhofer lines) but I don't understand how the sun can be both a continuous spectrum (gives all visible light) and the pictures at 8:29 and you say our sun "is an absorption spectrum." Internet searches seem to say "In summary, the spectrum of the sun is both continuous and absorption. The source itself is continuous, but as it passes through the outer layers of the sun, it becomes partially absorbed, resulting in an absorption spectrum." Would you agree with this?
Thanks for your feedback. I’m glad my videos are useful. Yes I agree with that statement. I was referring to the sunlight that we received which is definitely an absorption spectrum, but as the text noted, the energy from the son’s core has to pass through the atmosphere come.
God bless.
Thank you so much for the reply! Next, I'm going to try and understand the difference between spontaneous and stimulated emission and was delighted to learn you have a video on lasers. @@PhysicsHigh
Спасибо за доступное объяснение материала!
Я из России. Жаль, что на русскоговорящей площадке мне не удалось найти стоящего контента, связанного с этой темой.
Brilliant. Thank you for this.
Thank you for making this video!
Great job guys.
Excellent. I'm going to try some of these experiments with m camera.
very good, thank you! I think i used the same spectroscope in high school in 1984...that one ain't new :-)
Do glass of hydrogen emission tube not interfere with lines because glass itself made of something so it should also absorbs or emit some wavelength of light ?
Excellent job, thank you!
Thanks
well done! not sure if you take questions but i was just wondering why glass absorbs UVB light but allows visible light to be passed through it?
how do we dare feign to accurately assign colors to wavelengths within the "visible spectrum" we can't directly perceive??? 10:20 is there some inference or extrapolation or Fourier transform of sorts to prove our assignment is remotely correct? is it proven by wave interference theory?
How is such a coherent white light source shown in this video is produced for long distance gas identification spectroscopy?
5:59 gross concept error: our eyes are limited to activation by only three different wavelength intensities, i.e. red, blue, and green. the "visible" spectrum is just a trick, and we don't actually know which color corresponds to various wavelengths. we painted a false picture on a black and white mystery, until chemical sensors, aka photographic film, was made. even then, the colored rays corresponding to pure orange, yellow, purple, etc. will only appear as grey tones on the film.
"There ain't no rainbows shining on me, Shades of grey are the colors I see" - Billy Joel "Shades of Grey" (1994)
Great video tnx! Is there a chance to get a hold of your amazing slides? I'd like to cite them in a workshop for some friends. Full credits would be given of course.
Sure. Just email me.
@@PhysicsHigh tnx a lot, i used the form on your site :) greetings from austria!
@4:20 I can't find any support that diffraction is what's behind the rainbow colors of soap bubbles. It's rather thin-film interference. It's not a matter of a small obstacle deviating light slightly from its straight path but rather a combination of reflection off two surfaces and constructive/destructive interference--leading to our preferentially seeing some frequencies over others.
wired dot com/story/the-secret-to-soap-bubbles-iridescent-rainbows/
explainthatstuff dot com/thin-film-interference.html
I stand corrected. Thanks. I plan to make a video on soap bubbles and will ensure correct language.
10:44 is Eagle Nebula not the Helix Nebula lol
Oops. Misspoke. You are right.
This video doesn't explain WHY you are measure angle of the table spectrometer. I've played that part multiple times. d sin(theta)=m* Lamdi. So I conclude it is to measure the angle theta to solve for lamda and get the exact wavelength. But as a teaching video you should not have stipped that explaination.
ممكن ترجمة المقطع للغة العربية
anyone here from mr gengiah's physics class?
Johnson Michelle Clark Patricia Williams John
so why is the electromagnetic spectrum displayed Hi to Low? As far as I can tell is tradition and academic pride. Both are poor answers.
I’m interested in your question. I don’t see a problem with it being organized in either direction. If you look at it from a wavelength point of view, it’s flipped from if you look at it from a frequency point of view. Typically when you’re dealing with radio waves, we talk about frequencies. I.e., 27 MHz is in the 11 m band. If we talk about light, we usually use wavelength because the numbers are easier to handle. This seems to me to be a place where convention works reasonably well, and that’s probably why he stuck around for so long. Comment?
If this level of introduction and explanation is typical of current high school practice, then it is no wonder that the students are lost. You tried to pack too much info into 21 minutes and wound up with a waste of time.