sir at 50:14 you mention that we can also take the value -1,-2,-3 and -4 so to make the value of y more than 0, but sir if we take the value -1 then we also have to take the value of x as -6 which will make the lhs side equal to zero, so isn't it wrong?
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sir at 50:14 you mention that we can also take the value -1,-2,-3 and -4 so to make the value of y more than 0, but sir if we take the value -1 then we also have to take the value of x as -6 which will make the lhs side equal to zero, so isn't it wrong?
same doubt
hi, can you explain pls for y>0 condition why cant we take y-6 = 1,2,3.. it will also give y = 7,8 ...which is also y>0 . why only negative integers
@@poojamahajan6744 This y =7,8 have already been considered in positive integral solutions, why do you want to consider that again.
If you equate y-6 = -1 , you get y value as 5, (x-6)(5-6)=36, in this case x value is -30
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why we are taking x as -ve values for x>0, please explain
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in the last question, what would be the total integral soln for (y>0)?
For that, factor should be greater than 44, which I got as 5. So total (y>0) m getting 25. What did you got ?
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1:04:40.... N.o of intergral solution for Y will be 38 and not 37, Sir, you forgot to consider 20 as a factor
hi tanisha, integral solution will be 37 only, sir has considered the factor 20, he also has written on the board
Thankyou sir