Vernier reading is in upper main plate and micrometer is in lower main plate L.C of upper Vernier scale =20'' L.C of lower micrometer scale=360°/1080 divisions =360×60×60 seconds/1080 divisions =20'
This method will fail for closed traverse, then how we find correction in closed traverse problem(in numerical you did) Pls clarify that when we find error by angles method or when we find by FB-BB=180° method.
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Please do numerical class on surveying plzzz sir
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Structural analysis sir
Least count of micro threodilite 2"
Least count of Vernier theodolite is 20" not 20'
Vernier reading is in upper main plate and micrometer is in lower main plate
L.C of upper Vernier scale =20''
L.C of lower micrometer scale=360°/1080 divisions =360×60×60 seconds/1080 divisions =20'
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This method will fail for closed traverse, then how we find correction in closed traverse problem(in numerical you did)
Pls clarify that when we find error by angles method or when we find by FB-BB=180° method.
Aap ke pas es lecture ka pdf notes h kya please 🙏🙏🙏
Mera bhi same doubt hai.😕
sir ne galat kiya hai
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48:11
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If it is less than 180 then
Air ye correction per angle m 5 se divide kr k 30 kese ??? Smjh nhi aaya sir yaha
2 bj k 30 min ko 5 hissa mai divide kroge to 30 bachta hai
Hi
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