HW1. 1. Distance=170 m 2. Distance=125 m Maximum value of acceleration=2.5m/s^2 (Retardation = -5 m/s^2 ). HW2. Displacement = 8 m Distance travelled = 16 m.
Q1:ans... i. 80+10+40+20=150m. (calculated by velocity time graph area gives distance) ii. 75+10+20=105m. Max Accl... 2.5m/s2 Q2.:ans Distance.. 8+8+4=20m Displacement... 8-8+4=4m
Sir aap padha to achha rhe hai lekin kafi topic escape krke jaise motion of equation ka graph nhi btaya us pr v question aate hai 2-alp me numerical question to jyda tough nhi aata lekin momentum force newton law of motion pr theoartical question aa skte hai aap aise objective question v apne content me krate to achha rhta ye question v time taking nhi jaldi se ho jata
In Time 30.00 why you take "g" as "-negative g" there the body falling downwards so gravity is in the direction of motion , so ;g is positive, Am I right???
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hffh,,,,,,,,,,,,,,,,,mmmmmmmmmbn
Sir meri to 1st question ki distance. 170 meter.
Acceleration. -2.5m/sec2. Aa rhi h
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Home work ans, question 1 (I) 170 m, (ii) acc: 0.5 m/s2, Question 2. Displacement 16 m
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Homework questions
1- time 0to 18 -distance 170mt
Time 0 to 12 distance -115mt
Max acceleration at 8 sec
2-distance -16
Displacement -8mt
In last ques. Displacement 12 ni aaygi
I think 2 se 12sec tak 125m hoga
1ques..170m &125 m (t=2 to12) 2.5m/sec sq
2ans ..displacement =8m
Distance=16
HW1
A
1-distance 170m
2-acceleration-0m/sec²
B
1-distance 125m
2-acceleration .5m/sec²
HW2
Distance 8m
Acceleration kaise Aya h bro...plz tell me
Correct
Ye wala ques. Smjha do bro
Neeraj sir you r the amongst wifi study team....
Answers
1 a) 190m
1b) 125m
1 c) max acceleration 2.5 m/s^2
2 a) 8m
2 b) 16m
Super pakkaou ho sir aap... Apne diya h exam railway ka koi khabi apni life mein?
Ans 1.a)170mtr
b) 125mtr
c)2.5m/s2
Ans2 distqnce=16mtr
Displacement=8mtr
HW1 -> (1)- 170m , (2)- 125m, Max. Acceleration = 5 m/s2 HW2 -> Displacement = 8m , Distance = 16m
Hw1
(i)Distance=170 m from t=0 to 18 sec
(ii)Distance=125 m from t=2 sec to 12 sec
acceleration= +2.5 m/sec^2
HW2:
Displacement=8 m Distance = 16 m
Engg drawing ap hi karate to better hota....u r the most valuable teacher in WiFi study team....thnk you sir.
Hw1 ans 130 m, 75 m , maximum acceleration 2.5 m/sec^2
Hw2 ans displacement 4 m
Katai zaher pdate hoo🔥🔥🔥🔥🔥🔥🔥🔥🔥
HW1.
1. Distance=170 m
2. Distance=125 m
Maximum value of acceleration=2.5m/s^2
(Retardation = -5 m/s^2 ).
HW2.
Displacement = 8 m
Distance travelled = 16 m.
Q1:ans...
i. 80+10+40+20=150m. (calculated by velocity time graph area gives distance)
ii. 75+10+20=105m. Max Accl... 2.5m/s2
Q2.:ans
Distance.. 8+8+4=20m
Displacement... 8-8+4=4m
H.w 1
t=4sec. , First case distance 78.4m and 2nd case distance is 21.6m
Stone is left from the bridge in the river mean gravity supporting the stone a =+g
Upword mean a=-g
1. I. distance = 170m
ii. Distance = 125m
2.distance =8m , displacement = 16m
Can you explain hw1 question
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thanks sir ji 18 sec per distense 170m and 2se to12sec mai 110m ,next answer 6sec mai distense 16m
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Jhuthi ho aap
Sir aap padha to achha rhe hai lekin kafi topic escape krke jaise motion of equation ka graph nhi btaya us pr v question aate hai
2-alp me numerical question to jyda tough nhi aata lekin momentum force newton law of motion pr theoartical question aa skte hai aap aise objective question v apne content me krate to achha rhta ye question v time taking nhi jaldi se ho jata
Love you guruji 😀👌
HW1
Distance=170m and max acceleration at time 8sec = 2.5m2/s
HW1
Displacement = 8m
Distance=16m
Last question ans. Displacement =8m and distance=16m
very helpfull for cbt2 sir
nice explanation....theory and question..
Thanks sir, you help of students
Time 4sec distance 78.4m👍👍👍👍👍👍👍
1. i)- 150m, 2)- 125 m, 3)- 0.92 m/ss
Dhanyabad guru ji
In Time 30.00 why you take "g" as "-negative g" there the body falling downwards so gravity is in the direction of motion , so ;g is positive, Am I right???
1---170m
2---120m & acceleration=2.5m/s2
Second question homework total distance=16 km
s=2√13....
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law of conservation momentum kaun hota hy 2nd or 3rd ??
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Hw2
Displacement= 8unit
Distance=16unit
aaj ka class must hai
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Bahut acha sir, kya all questions ke pdf mil skte hai
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Homework question answer
Question 1=distance
(i) = 170 m
(ii) = 125 m acceleration =2.5
Question 2 = distance = 16 m
Displacement =8 m
Acceleration should be - 5m/s^2
Hw1
(i)=170m
(ii)= 125m
Acc.= 5m/s^2
Hw2
Dist.=16m
Disp.=8m.
Bhai aaplog acceleration kese nikale ho plzzz explain
Akshay bhai
Rigt answer
U r gd
Time 4 sec and distance-78.4 from top
78.4 kaise aya
Bhai solution bhej sakte ho kya...I hv doubt
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Hw 1
1- 220m
2- 140
3-5m/s^2
Hw 2
16m
Par vo to -5m/s^2 to maximum kaise hua
Very nice sir
Explain last que distance and displacement how 16 and 8
1-170m
2-125m
a-2.5m/s.s
Please explain clearly madam
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Sir aap sab se sir bahut kuch sikhne ko milta hai but kuch log pata nahi kya chahte hai jo apne teachers ki ijjat nahi karte wo kabhi success nahi ho sakte sir question thoda jada kara diya karo pliz
1) 170 m and 4.5 m/ S2
2)125 m and 1.5 m/ s2
Q1 (1)=150m, (2)=2.5m/s2
Q2 (1)=10m , (2)=20m
Thanks a lot sir
sir aap ek class isometric view ki le lo.. pls
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Hw1
1) 170m
2) 125m
3) 2.5m/s^2
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@@saketsen774 sorry sahi ho bhai app. Qstn thk se nhi dekha maine. Mujhe lga maxm hai
Plz solu show
Plz explain
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Sir (g) ki value earth ki surface se neeche jane par negative hoti hai.but Pul wale question me aapne g pahle hi negative le lia.why ???
T=4s
h=78.4 from top of bridge
Law of inertia
Law of force
Action =reaction
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I used your app sir plz update this app and forward and another optional is where sir ?
1. 170 mtr
2. 125 mtr
3. -5 m/s^2
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Sir ye 100m tower wale k liye mere pas ek short trick h..jisse que lennghty nai hoga
Osm class
vary vary good sir
Thanks sir
nice class
Thanks
Time 4 sec and 78.4 m
Kaise aaya...can u send me d solution
Basic science and engineering book only Rs 20/- with chapter wise mcq.... Contact @ whatsapp 9710036376
anamika de yh
Displacement =12m
Distance in 6s =16m
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Lecture 13 video not uploaded on youtube.
Hw2----disp=8m,,,,,,, distance=16m
2. i) distance - 16m, 2) - 0
2) - 16m
tq sir
Sir, kindly give the solution of home work question no.1.
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