Proving Bernoulli's equation takes more that a few lines. The best way to think about it is the if P2 > P1 then at point 1 the fluid level must be at a higher elevation or the fluid velocity must be greater at point 1 (or both).
I have a final for fluid dynamics in 5 days, and I just came across your video. I’ve seen your lectures before and they help out so much. I’m done studying for the day, but when I wake up tomorrow, best believe I’m binge watching this. Thank you so much; you’re amazing
Mr. Michel Van Biezen, you have been my physics mentor for the past year, and haven't even known it. Thank you for your service, you are the true hero, and the OG, I salute you sir!
I wanted to take the time to thank you for your videos. I took physics I & II online over the summer and it was hard but with the help of your videos I got an A on both 😀
As someone who studied electricity I find learning about fluid dynamics fascinating and very useful. Thank you sir for providing this information so I and others can supplement my education. It is perhaps one of the most important endeavors our lives contain, the sharing and gathering of knowledge.
The derivation of this equation is actually very straightforward, and basically just the energy equation. It's the sum of the potential, kinetic, and extra energies, where the extra energy in this case is the pressure work. So you can set up the equation like this: m⋅g⋅h + 0.5⋅m⋅v² + p⋅V = constant From here, you can divide everything by the volume, which then gives you the final equation: ρ⋅g⋅h + 0.5⋅ρ⋅v² + p = constant
I don't know how I got here to see this video, but I don't regret playing it I learn something very valuable today, this is awesome when you turn your water and wonder how does it work? the answer is here. Bermoulli a genuine GENIUS
I'm Mechanical Engineer and you have explained it that even a person who don't have any physics background can understand it very clearly. You are a great teacher, those fellows are lucky to have a teacher like you. I have made a python program just to do the calculation so that I don't have to remember how a Bernoulis equation work. You just refreshed my concept thank you Sir.
I'm refamiliarizing myself with this topic (I originally learned about it in Anatomy & Physiology via how blood pressure & circulation work) because I want to design an under gravel filter system for aquariums that minimizes "dead spots" in flow. If this video is an indication of the quality of your content, I've found EXACTLY what I need! Thank you!
I'm studying medicine, and I find the Physics in Medicine unit tricky at times!! Your videos have helped so much, and make Physics concepts so much clearer. Thank you Michael!!
Sir thank you for your videos. I first discovered this channel when I was in college and that time I was just a student of the civil engineering program. Today I am teaching as a License Civil Engr and I am still using your example. .
Finished fluid statics, surface tension and buoyancy force in the previous couple of days Now studying fluid dynamics from you. You're giving me a lot of knowledge and saving a lot of time. 🙂❤
Hi, I just wanted to thank you, I have passed general physics in my university thanks to you. I thought that I can't do it but fortunately I did it with your help and I have graduated.
The Bernouilli's Equation-scene from "An Officer and a Gentleman" (1982) brought me here. But this lecture ofcourse, really puts the P in Physics. Although a certain Sheldon Cooper probably would beg to differ. Personally, I think this is an excellent lecture, of which I would like to see more of in the future. Preferably some lectures on the ever fascinating world of aviation and the dynamics of physics it entails. In the meantime, keep up the good work, Sir!
it's 11:30 pm here in italy, i never studied physics in my life and i'm not very good in english and math but this video just appeard in my suggested.. man, this is hypnotic: i understand everything and now i'm looking for part 2 of 7 thank you
Hi Mauro, Glad you found this video. There are 8,400 more videos on our channel. You can find them by going to the home page of "Ilectureonline" on TH-cam, or just type in: Michel van Biezen youtube and you will get to the home page. From there you can find all that you need.
The best all lecturers for this field, I remember my mechanics course in the semester 5, civil Engineering degree, in 2014, at that time I learnt this legend Professor Mechanics and hydraulics very well. I get these two difficult courses A plus, without attending for classes. Thank you Sir!
Thank you for your time and expertise in fluid dynamics. I’m attempting to utilize Bernoulli’s equation to answer which water pump (gallons per hour) I will need for an aquarium room I am building. Being able to have the proper mathematical direction will allow me to analyze manufacturers claims versus my actual needs and expectations. I’ll be using this information also for my questions addressing if I should utilize multiple pumps and how much energy will be needed and/or consumed with a single large pump versus multiple pumps. This information will only be used for my aquarium room build and personal pleasure of the sciences, not to discredit any manufacturer or anyone for that matter. My physics skills (plug and chug) were proficient 20+ years ago however I’d like to wipe off the cobwebs, with some help. I do recall that when a variable (A2, h2) changes there must be a change to P2, V2 and/or v2. For some reason I vaguely remember that for every increase of 12” in height the flow rate decreases “roughly” 80 gallons per hour. I am not able to recall where this came from however I would enjoy knowing the why and how this is worked out. I will have multiple aquariums at different heights ranging from 1’ to 5’ above the pump(s). The pumps gph ability will be dictated by the total number of gallons and changes in heights of the aquariums. The gph demand is for the health of the fish and or plants. Knowing what flow rates will be expected at specific heights will provide me with the skills to make an educated decision as to which size of pumps I will use for my specific aquarium setup. Thank you for your time and any direction you may provide. Cheers - Breaux
Bernoulli equations are conservation of energy statements in disguise. Pressure is energy divided by volume (look at the units). Density is mass divided by volume. So you can read the second term as mgh/vol. The third term is mass velocity squared / vol The equations basically say that energy in equals energy out.
You are a living god for all students, your every explanations are Crystal clear, thank god for giving you!!! Thank you so much sir❤ . My one only doubt is why our lecturer can't teach as the way you teach????. They are getting that valuable teaching/lecturing job to earn money and destroying life of students . I think so!!!
Sometimes I wonder why I even bother looking at different TH-cam videos on physics not made by you. I understand everything so much better in your videos compared to others
Thank you for the confidence in our videos. We have 9500 on this channel so we cover most of physics and math with some engineering and others as well.
Why is it still same speed at the top although it is gaining potential energy. Is it because water particles are constrained with pipe wall? Single macro particle does not have pressure effect and so no option for it to be decreasing. Instead velocity is decreasing when it is lifted. But in fluids first pressure is decreasing instead of velocity. But in aerodynamics velecocity and pressure is reversely proportional to each other. So in this example why is velocity still constant although its pressure is changing?
For a fluid in the pipe with constant diameter the amount of fluid flowing through the pipe in any section of the pipe must be the same. Thus the velocity must be the same everywhere. That is why the pressure will drop when the pipe goes up, to compensate. That is what Bernoulli discovered with his equation.
I’ve noticed that this is very similar to the conversation of energy law but tailored for fluid kind of. If that’s the case, shouldn’t there be a term related to drag in the Bernoulli Equation?
Oh bro i really appreciated ur video it helps me a lot. and i could understand many things in fluid dynamics from this video im korean professor thanks a lot
Michel van Biezen dont get confused...... V stands for Volume and for velocity, it depends on the formula. dV/dT is volumetric flow (m^3/s) that s why = A*Velocity.
Hi..., How about if density of fluid that flowing changing to decrease. Let say there is an heating process in the middle of the pipe that makes density to decrease its about less than 25%, so the density of water to be 750kg/m3. My opinion : With P1 give a constant pressure, h2>h1, A1=A2 such as your task so, 1. Pressure at point two or P2 would be increase; 2. Velocity of the fluid at point two would be increase as well; 3. And if the the velocity of the fluid increase so for next pipe after poin two rate of the fluid or Q would be increase as well. Please your advice about my opinion Thanks...
I think I love your videos. Now I can understand. And I got this explained in my native language first, English is my second languge. Also I love that you use meters and not inches or whatever, tho...
This must be true on a universal scale as well. And eventhough it isn't, it gives me somethinv to work with. Love it! Absolutely. Bedankt voor de videos. Dit maakt mijn begrip een stuk beter
I wanna thank you on all the lectures you giving us its very helpful. You have educative way to explain it so easy to students, It will be great if you can do some courses about Mass and energy Balances in chemical engineering.
If a tube is conected to a compressor on one end and opened to the atmosphere on the other end, and the compressor injects a fluid at 40 psi, will the tube walls be subjected to the same pressure along the whole length of the tube? or is this pressure just to move the fluid? will the walls expand due to the 40 psi? Thanks for the help
after al the time you spend in making these video's, it's the least i can do ;) got my exam next week and i get more convedent every day so ones again, thanks alot
@@MichelvanBiezen Hello Michel, sorry for the very late reply. Yes, I think that you are an amazing lecturer, the clarity with how you teach and I have been very happy to watch many of your lectures, I love to 'try to' understand physics as my line of work is engineering and love programmes on how structures are built and how they overcome problems, I loved the one on the Corinth Bridge with Richard Hammond. One thing that I have found difficult to understand is the 'natural frequency' of materials, components etc in relation to vibration, but again there are good videos online. Really appreciate the time, effort and willingness to share your knowledge with others. Thank again, Michel, you're a star.
Just one question , so in a hydraulic system where the height also changes constantly , continuously, as in the case of a tractor loader, is the system somehow coming up with the changes in pressure and compensate it by regulating it or how it is done? Or is the change of the pressure so negligible? Thank you
Clear presentation, Sir! Of course in a real life there is always pressure loss in the pipe, therefore Bernoulli's equations as such is pretty useless when solving these kind of issues. Hopefully you could add some day one additional video where you would also take into account the pressure loss (i.e. the extended Bernoulli equation and Darcy-Weisbach). Thanks!
Yes you are correct. Just like anything else in physics we first learn the principles without friction, wind resistance, etc. Then we add the additional concepts when we are ready. We are planning a series on fluid dynamics in the future as time permits.
Good day master. It's an insignificance that does not intend to subtract any merit from masterly explanations, but if you use the SI, I think you should indicate the symbol of second, in "s" That is, the speed unit would be in m / s.
That comes out of the equation. It depends what you need to solve for. Once you have substituted all the given values, that question will be automatically answered.
Hi, The principle states that, if velocity decreases than the pressure increases. However, I'm not sure about the reason behind this principle. Would be helpful if you could explain the scientific reasoning why this works.
If the fluid is static, then all the forces (weight) of the top molecules push down on the molecules below creating the largest pressure. When the molecules are moving all the molecules will be rolling over one another and bumping around in random directions. The space between them will also increase. Which means that not all the downward forces are not as large and the pressure decreases.
Sir, how can be that v1 = v2?? I don't understand because I'm thinking that if water is climbing from 1 to 2, how can it not lose velocity?? I saw your fluids playlist so far and I understood the A1v1 = A2v2 in the inicial vídeo, because water did not climb, but here I can't understand.
The velocity can only change if the cross sectional area changes. That is the key to Bernoulli's equation, if the velocity cannot change then the pressure changes.
@@MichelvanBiezen Yes sir, matematically I can understand that. But physically, how can the gravity perform a work in the liquid and the liquid still have the same speed?
902hater Since the amount of fluid per unit time flowing through the pipe must be constant (the same amount of fluid entering the pipe on one end must be equal to the amount of fluid leaving the pipe during the same time interval), and since dV/dt = A v, A is cross sectional area and v is velocity, the velocity must decrease if the cross sectional area increases.
Hello, Mr. Biezen! I find this video super helpful and I want to make sure everyone can understand and enjoy it. That's why I wanted to let you know that your captions are a little off. At about 0:27 the auto-captions say "Bendel's Equation" where they meant to say "Bernoulli's Equation." When you get a chance, could you please fix that? That'll help the 360 million folks globally who rely on closed captions to understand videos. Thank you, and keep up the great work!
If we ignore friction, viscosity, etc. as in this simplified method of looking at it, then no. If we include those other factors, then the length of the pipe definitely does factor in.
This playlist goes into more detail, but we still have to create the course in fluid dynamics covering all these various aspects: PHYSICS 34.1 BERNOULLI'S EQUATION & FLOW IN PIPES
Wait , how do you assume speed stays constant when we're sure gravity has an effect , or do we just ignore gravity's effect ? Because whatever change in potential energy has to equal change in kinetic energy if gravity is involved and then pressure would be constant , what am i getting wrong ?
we have been using this formula (potential energy+kinetic energy+pressure energy). this formula often confusing me rather than the formula that you have given. in addition, how about the venturi meter, vena contracta and those orifice? is this formula could be use? Thanks Mr. Michel.
According to the Continuity Equation and Bernoulli's Equation, the smaller the cross-sectional area the larger the velocity, thus the smaller pressure. However, the formula for pressure is F/A, which indicates that the smaller the cross-sectional area the larger the pressure. Can anyone please explain this contradiction? Also, is the pressure in capillaries higher or lower than the pressure in aorta (since the capillaries have larger cross-sectional area than aorta, but I am confused with the contradiction I mentioned before)? Thank you!
But sir please explain what you mean by pressure of the fluid. Is it the hydrostatic pressure or the static? And where is this pressure exactly applied? Parallel to the walls of the tube or vertical to them? Just ''pressure of the fluid'' doesn't help me at all to understand 😒
When you dive down to the bottom of a swimming pool, or a lake, or the ocean, you will pressure on your ear drums. It doesn't matter where you are, everywhere in the water sufficiently deep you will feel that pressure.
Dear Sir............Example Problem : One hydraulic cylinder, the end is connected to the Threaded rod so that it can be rotated. Cylinders with a bore size of 18 mm, 10 mm rod and a stroke of 300 mm single acting in a condition that is filled with oil. If the cylinder is rotated 10 mm. a. How to calculate it b. What is the gauge pressure
Very clear explanation! I understood everything you were saying in this video. I wish you were my fluids professor :( *Edit: forgot to say thanks a bunch!! :)
Wow, very useful video. Hi am Mech. Engr working in the stream of quality in construction and piping. can you please tell me, is the above Bernoulli's equation applicable to find the pressure drop in hydro testing procedure.?,
Depending on the application, you may need to include type of fluid used, viscosity, temperature, material of the pipes, etc. But this will give you a good estimate in an "ideal" situation
very useful video thanks for sharing. I have a question, how does the Bernoulli equations adapts to the situation where both the area and height varies in the pipe? Do you have any video for it, If so could you share ?
😇what if a question was like this ( a water tank has a valve at the bottom. If this valve is opened, what is the maximum height attained by the water stream coming out of the right side of the tank? Assume that h = 10.0 m, L = 2.00 m, and θ = 30.0°, and that the cross-sectional area at A is very large compared with that at B.) how can solve it
Solve for the velocity of the water coming out of the hole (as shown in a video like that in this playlist). Then calculate the vertical component of the velocity (Vo sin(theta)) and then use the equations of kinematics to determine how high it goes V^2 = Vo^2 + 2 g (h)
Hii Sir, how we calculate drain time of pressurised closed pipe (two isolation valve) as if we consider water is at 7 bar as it start drain pressure star decreasing
That is a bit complicated to try and expalin in the comment here. We hope to cover that type of question in the future when we expand our playlists on fluid dynamics.
If you use your cantilever for a piping systeme support , how do you calculate the dynamic charge of the fluid and then add the dynamic weight to the centalever calculation ?
Proving Bernoulli's equation takes more that a few lines. The best way to think about it is the if P2 > P1 then at point 1 the fluid level must be at a higher elevation or the fluid velocity must be greater at point 1 (or both).
Wow man, your back must hurt from carrying me all the way to university. Thank you very much.
LOL, Happy to help!
😂😂😂😂
If I ever get rich one of my goals would be to sponsor Michael to get a bigger audience. His videos go into detail unlike many others.
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I have a final for fluid dynamics in 5 days, and I just came across your video. I’ve seen your lectures before and they help out so much. I’m done studying for the day, but when I wake up tomorrow, best believe I’m binge watching this. Thank you so much; you’re amazing
Good luck on your exam.
Mr. Michel Van Biezen, you have been my physics mentor for the past year, and haven't even known it. Thank you for your service, you are the true hero, and the OG, I salute you sir!
I wanted to take the time to thank you for your videos. I took physics I & II online over the summer and it was hard but with the help of your videos I got an A on both 😀
Excellent!
hi
@@dexentjutt4084 could you help me please .. why did he take p1 as 2 atm ..what steps ?
As someone who studied electricity I find learning about fluid dynamics fascinating and very useful. Thank you sir for providing this information so I and others can supplement my education. It is perhaps one of the most important endeavors our lives contain, the sharing and gathering of knowledge.
Man, u are better than my physics professor by an order of magnitude equal to Avogadro's Number + Faraday's Constant...THANKS!
Joey,
That gave me quite a chuckle. Thanks for the compliment.
Awesome hgahaha!!
Your units... lmao
minus the charge of an electron.
He is not a man he is a angel
The derivation of this equation is actually very straightforward, and basically just the energy equation.
It's the sum of the potential, kinetic, and extra energies, where the extra energy in this case is the pressure work.
So you can set up the equation like this:
m⋅g⋅h + 0.5⋅m⋅v² + p⋅V = constant
From here, you can divide everything by the volume, which then gives you the final equation:
ρ⋅g⋅h + 0.5⋅ρ⋅v² + p = constant
I don't know how I got here to see this video, but I don't regret playing it I learn something very valuable today, this is awesome when you turn your water and wonder how does it work? the answer is here. Bermoulli a genuine GENIUS
This is not even my mother language but it's 10 times better explained than in German.. thank you so much!
ja wohl
I'm Mechanical Engineer and you have explained it that even a person who don't have any physics background can understand it very clearly. You are a great teacher, those fellows are lucky to have a teacher like you.
I have made a python program just to do the calculation so that I don't have to remember how a Bernoulis equation work. You just refreshed my concept thank you Sir.
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Oh boy, I could never get this in my head in my years at college. You made it stick in 10 minutes. Brilliant. Thanks
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I'm refamiliarizing myself with this topic (I originally learned about it in Anatomy & Physiology via how blood pressure & circulation work) because I want to design an under gravel filter system for aquariums that minimizes "dead spots" in flow. If this video is an indication of the quality of your content, I've found EXACTLY what I need!
Thank you!
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I'm studying medicine, and I find the Physics in Medicine unit tricky at times!! Your videos have helped so much, and make Physics concepts so much clearer. Thank you Michael!!
All the best in your studies. Keep it going.
@@MichelvanBiezen managed to get an A- in my exam thanks to your help!! Medical imaging is next semester.
Sir thank you for your videos. I first discovered this channel when I was in college and that time I was just a student of the civil engineering program. Today I am teaching as a License Civil Engr and I am still using your example. .
Congratulations on your success! Glad you still find our videos helpful. 🙂
Finished fluid statics, surface tension and buoyancy force in the previous couple of days
Now studying fluid dynamics from you. You're giving me a lot of knowledge and saving a lot of time. 🙂❤
Great! Glad you found our videos. 🙂
Hi, I just wanted to thank you, I have passed general physics in my university thanks to you. I thought that I can't do it but fortunately I did it with your help and I have graduated.
Fantastic! Hard work and perseverance will succeed in the end.Thanks for sharing.
The Bernouilli's Equation-scene from "An Officer and a Gentleman" (1982) brought me here.
But this lecture ofcourse, really puts the P in Physics. Although a certain Sheldon Cooper probably would beg to differ. Personally, I think this is an excellent lecture, of which I would like to see more of in the future. Preferably some lectures on the ever fascinating world of
aviation and the dynamics of physics it entails. In the meantime, keep up the good work, Sir!
it's 11:30 pm here in italy, i never studied physics in my life and i'm not very good in english and math but this video just appeard in my suggested.. man, this is hypnotic: i understand everything and now i'm looking for part 2 of 7
thank you
Hi Mauro,
Glad you found this video. There are 8,400 more videos on our channel. You can find them by going to the home page of "Ilectureonline" on TH-cam, or just type in: Michel van Biezen youtube and you will get to the home page.
From there you can find all that you need.
I did not realize the important of understanding the fundamental fluid dynamics until i work in a offshore engineering industry. Keep up 🆙
Yes, and thank you.
The best all lecturers for this field, I remember my mechanics course in the semester 5, civil Engineering degree, in 2014, at that time I learnt this legend Professor Mechanics and hydraulics very well.
I get these two difficult courses A plus, without attending for classes.
Thank you Sir!
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Thank you so much for these videos. I have an exam in 2 weeks and its only now after watching your video i finally get it!!
Thank you!!!
Work as an electrician in a steel strip mill. Work a lot with hydraulics: This channel is great for me. Always learning; Thank you.
Great job! Love the flag!
Thanks for that explanation, saying that if one term increases then the other must decrease helped me understand better how constant equations work.
Glad it was helpful!
bless your soul i have an exam in two hours and im speedrunning this
Probably best online lecture channel ever ..
This is awesome. I'm just refreshing my memory with these great videos for my midterm. Thank you for your videos sir
THANKYOU! Your videos are super super helpful for me and I finally feel like I can actually do physics...never stop please, you're the best.
Thank you Michael for all your videos, you are helping people with your education.
Thank you for your time and expertise in fluid dynamics. I’m attempting to utilize Bernoulli’s equation to answer which water pump (gallons per hour) I will need for an aquarium room I am building. Being able to have the proper mathematical direction will allow me to analyze manufacturers claims versus my actual needs and expectations. I’ll be using this information also for my questions addressing if I should utilize multiple pumps and how much energy will be needed and/or consumed with a single large pump versus multiple pumps. This information will only be used for my aquarium room build and personal pleasure of the sciences, not to discredit any manufacturer or anyone for that matter. My physics skills (plug and chug) were proficient 20+ years ago however I’d like to wipe off the cobwebs, with some help. I do recall that when a variable (A2, h2) changes there must be a change to P2, V2 and/or v2. For some reason I vaguely remember that for every increase of 12” in height the flow rate decreases “roughly” 80 gallons per hour. I am not able to recall where this came from however I would enjoy knowing the why and how this is worked out. I will have multiple aquariums at different heights ranging from 1’ to 5’ above the pump(s). The pumps gph ability will be dictated by the total number of gallons and changes in heights of the aquariums. The gph demand is for the health of the fish and or plants. Knowing what flow rates will be expected at specific heights will provide me with the skills to make an educated decision as to which size of pumps I will use for my specific aquarium setup. Thank you for your time and any direction you may provide. Cheers - Breaux
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now a days i enjoy physics with your videos.thank u soo much professor
Sir you are a real teacher. Double thumbs up to you.🇬🇾
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Never been in a school, but so easy to follow. Thank you for teaching me.
School is not the only place to get an education. Remember what Mark Twain said: " Don't let schooling interfere with your education".
Thank you for the video you make! They really helped me in understanding more about Bernoulli Equation. Very useful. Keep up the good work.
Michel van Biezen, best physics teacher EVER!!
English is not even my first language but this helped me so much
back with fluid mechaics
You came to the right place.
Bernoulli equations are conservation of energy statements in disguise. Pressure is energy divided by volume (look at the units). Density is mass divided by volume. So you can read the second term as mgh/vol. The third term is mass velocity squared / vol The equations basically say that energy in equals energy out.
You are a living god for all students, your every explanations are Crystal clear, thank god for giving you!!! Thank you so much sir❤ . My one only doubt is why our lecturer can't teach as the way you teach????. They are getting that valuable teaching/lecturing job to earn money and destroying life of students . I think so!!!
Just a simple man, blessed that I have been given the opportunity to make these videos and a wonderful wife who helps me tremendously making them.
Sometimes I wonder why I even bother looking at different TH-cam videos on physics not made by you. I understand everything so much better in your videos compared to others
Thank you for the confidence in our videos. We have 9500 on this channel so we cover most of physics and math with some engineering and others as well.
I undestand your concept better than my proffesor thanks a lot prof michael.
We appreciate the feedback.
Why is it still same speed at the top although it is gaining potential energy. Is it because water particles are constrained with pipe wall? Single macro particle does not have pressure effect and so no option for it to be decreasing. Instead velocity is decreasing when it is lifted. But in fluids first pressure is decreasing instead of velocity. But in aerodynamics velecocity and pressure is reversely proportional to each other. So in this example why is velocity still constant although its pressure is changing?
For a fluid in the pipe with constant diameter the amount of fluid flowing through the pipe in any section of the pipe must be the same. Thus the velocity must be the same everywhere. That is why the pressure will drop when the pipe goes up, to compensate. That is what Bernoulli discovered with his equation.
I think am in love with his explanations he is the best teacher in the world.
I’ve noticed that this is very similar to the conversation of energy law but tailored for fluid kind of. If that’s the case, shouldn’t there be a term related to drag in the Bernoulli Equation?
Yes indeed, this is very similar to the energy conservation equation. For simplicity loss due to drag is not included.
Oh bro i really appreciated ur video it helps me a lot. and i could understand many things in fluid dynamics from this video im korean professor thanks a lot
Mark,
Since v = dx/dt Av = dV/dt
Sir, will you make videos on differential equations in the future?
That would be really helpful.
Thanks a lot for all your videos.
Laurelindo That is part of the plan
Michel van Biezen dont get confused...... V stands for Volume and for velocity, it depends on the formula. dV/dT is volumetric flow (m^3/s) that s why = A*Velocity.
Hi...,
How about if density of fluid that flowing changing to decrease. Let say there
is an heating process in the middle of the pipe that makes density to decrease
its about less than 25%, so the density of water to be 750kg/m3.
My opinion :
With P1 give a constant pressure, h2>h1, A1=A2 such as your task so,
1. Pressure at point two or P2 would be increase;
2. Velocity of the fluid at point two would be increase as well;
3. And if the the velocity of the fluid increase so for next pipe after poin
two rate of the fluid or Q would be increase as well.
Please your advice about my opinion
Thanks...
it will become a problem of thermodynamics i think
no one needs to go to college or university... this tutorial is enough... i wish i could meet Professor Michel in my life time once..
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I think I love your videos. Now I can understand. And I got this explained in my native language first, English is my second languge. Also I love that you use meters and not inches or whatever, tho...
Glad you found our videos helpful. 🙂
This must be true on a universal scale as well. And eventhough it isn't, it gives me somethinv to work with. Love it! Absolutely. Bedankt voor de videos. Dit maakt mijn begrip een stuk beter
This is a good place to start in order to understand Bernoulli's equation.
I 'd love to see a thermosiphon analysis, using Lagrange formulation thank you for your great work.
These are great videos, well explained and easy to follow, thank you so much for this superb resource. 🖖
You're welcome! Glad you found our videos.
Thankyou, sir. You help me like A LOT tonight. I'm ready for my exam tomorrow. Thankyou again for sharing your knowledge. You're awesome!
Good luck on your exam.
Excellent and simple explanation!! Thank you !!
Thank you and welcome.
sir u r very much better than my fluid lecturer.u r explanation gave me relief from my exam fear.u just awesome sir.thank u very much sir
I wanna thank you on all the lectures you giving us its very helpful. You have educative way to explain it so easy to students, It will be great if you can do some courses about Mass and energy Balances in chemical engineering.
Fiiinally, the explanation I was looking for ;D great video
Glad you found our videos. (there are 9500 more on this channel). 🙂
I am an Indian, Sir thanks a lot every videos help me when I confused to solve physics questions
Welcome to the channel
If a tube is conected to a compressor on one end and opened to the atmosphere on the other end, and the compressor injects a fluid at 40 psi, will the tube walls be subjected to the same pressure along the whole length of the tube? or is this pressure just to move the fluid? will the walls expand due to the 40 psi?
Thanks for the help
thank you alot for these video's, they make studying much more easy and fun
Maarten,
Thanks for taking the time to let me know.
after al the time you spend in making these video's, it's the least i can do ;) got my exam next week and i get more convedent every day so ones again, thanks alot
Have a physics exam tomorrow at school, and it's the best place to study.
At last, I got it. Thank you!!
Glad it was helpful. 🙂
You are a class act Michel, love your amazing lectures. Thanks so much for the way you present the info and how you always give the units, fantastic.
Glad you like them!
@@MichelvanBiezen Hello Michel, sorry for the very late reply. Yes, I think that you are an amazing lecturer, the clarity with how you teach and I have been very happy to watch many of your lectures, I love to 'try to' understand physics as my line of work is engineering and love programmes on how structures are built and how they overcome problems, I loved the one on the Corinth Bridge with Richard Hammond. One thing that I have found difficult to understand is the 'natural frequency' of materials, components etc in relation to vibration, but again there are good videos online. Really appreciate the time, effort and willingness to share your knowledge with others. Thank again, Michel, you're a star.
Just one question , so in a hydraulic system where the height also changes constantly , continuously, as in the case of a tractor loader, is the system somehow coming up with the changes in pressure and compensate it by regulating it or how it is done? Or is the change of the pressure so negligible?
Thank you
In hydrolic systems, the volume of fluid is so small and the pressures are so high that the difference in height makes very little difference.
Clear presentation, Sir! Of course in a real life there is always pressure loss in the pipe, therefore Bernoulli's equations as such is pretty useless when solving these kind of issues. Hopefully you could add some day one additional video where you would also take into account the pressure loss (i.e. the extended Bernoulli equation and Darcy-Weisbach). Thanks!
Yes you are correct. Just like anything else in physics we first learn the principles without friction, wind resistance, etc. Then we add the additional concepts when we are ready. We are planning a series on fluid dynamics in the future as time permits.
Good day master. It's an insignificance that does not intend to subtract any merit from masterly explanations, but if you use the SI, I think you should indicate the symbol of second, in "s" That is, the speed unit would be in m / s.
All your videos are awesome 🎉🎉🎉🎉🎉
Glad you like them!
THANK YOU SO MUCH SIR.. I am from India and your videos are helping me so much 😊😊😊
Welcome to the channel!
Sir no word's 4 u,,,,,,,,,,,,,,2moro i will be ma exam,and i got the concept thank u
Hello, so you calculated P2? how much pressure from the lower point required to make it equal? to one atmospheric pressure =2(1.01cx10^5 B/sm^2)?
Since the differnce in the height requires 49,000 N/m^2 to overcome, you need P1 = 101,300 Pa + 49,000 Pa for P2 = 101,300 Pa = 1 ATM
very useful one! One question please, how to determine when to calculate h1-h2 or h2-h1? i'm confused
That comes out of the equation. It depends what you need to solve for. Once you have substituted all the given values, that question will be automatically answered.
Hi,
The principle states that, if velocity decreases than the pressure increases. However, I'm not sure about the reason behind this principle. Would be helpful if you could explain the scientific reasoning why this works.
If the fluid is static, then all the forces (weight) of the top molecules push down on the molecules below creating the largest pressure. When the molecules are moving all the molecules will be rolling over one another and bumping around in random directions. The space between them will also increase. Which means that not all the downward forces are not as large and the pressure decreases.
Sir, how can be that v1 = v2??
I don't understand because I'm thinking that if water is climbing from 1 to 2, how can it not lose velocity??
I saw your fluids playlist so far and I understood the A1v1 = A2v2 in the inicial vídeo, because water did not climb, but here I can't understand.
The velocity can only change if the cross sectional area changes. That is the key to Bernoulli's equation, if the velocity cannot change then the pressure changes.
@@MichelvanBiezen Yes sir, matematically I can understand that.
But physically, how can the gravity perform a work in the liquid and the liquid still have the same speed?
By changing the pressure. (Note that there are 3 variables: P, v, and h)
What is the relationship between Diameter and Velocity?
I mean, why does Velocity decrease with Diameter increase, and vice versa?
Thank you!
902hater
Since the amount of fluid per unit time flowing through the pipe must be constant (the same amount of fluid entering the pipe on one end must be equal to the amount of fluid leaving the pipe during the same time interval), and since dV/dt = A v, A is cross sectional area and v is velocity, the velocity must decrease if the cross sectional area increases.
Thank you sir for your videos. They actually helped me a lot on my studies. God bless you sir
Hello, Mr. Biezen! I find this video super helpful and I want to make sure everyone can understand and enjoy it. That's why I wanted to let you know that your captions are a little off.
At about 0:27 the auto-captions say "Bendel's Equation" where they meant to say "Bernoulli's Equation."
When you get a chance, could you please fix that? That'll help the 360 million folks globally who rely on closed captions to understand videos. Thank you, and keep up the great work!
Im doing Fluid mechanics in civil engineering...statics and dynamics
I know that it is not represented in the equation however does the length of the pipe in any way have an affect on pressure difference?
If we ignore friction, viscosity, etc. as in this simplified method of looking at it, then no. If we include those other factors, then the length of the pipe definitely does factor in.
@@MichelvanBiezen Brilliant, thank you. Do you have any examples taking these factors into consideration?
This playlist goes into more detail, but we still have to create the course in fluid dynamics covering all these various aspects: PHYSICS 34.1 BERNOULLI'S EQUATION & FLOW IN PIPES
Wait , how do you assume speed stays constant when we're sure gravity has an effect , or do we just ignore gravity's effect ? Because whatever change in potential energy has to equal change in kinetic energy if gravity is involved and then pressure would be constant , what am i getting wrong ?
You cannot take Bernoulli's principle in isolation. You also have to include A1v1 = A2v2. When A is the cross sectional area and v is the velocity.
I love this channel. Addictive. He makes it fun.
https: //th-cam.com/video/paVOEi7cYrA/w-d-xo.html.( Mec.English and french)👍👍👍👍👍👍👍👍👍💐
we have been using this formula (potential energy+kinetic energy+pressure energy). this formula often confusing me rather than the formula that you have given. in addition, how about the venturi meter, vena contracta and those orifice? is this formula could be use?
Thanks Mr. Michel.
Great video, really helped my understanding! Thanks Mr Biezen!
Glad it helped!
I used to watch your videos all the time before i started college (this was around 5 years ago)... Just came back for a little stroll haha!
No 1 best teacher, i like u from srilanka
Welcome to the channel!
According to the Continuity Equation and Bernoulli's Equation, the smaller the cross-sectional area the larger the velocity, thus the smaller pressure. However, the formula for pressure is F/A, which indicates that the smaller the cross-sectional area the larger the pressure. Can anyone please explain this contradiction? Also, is the pressure in capillaries higher or lower than the pressure in aorta (since the capillaries have larger cross-sectional area than aorta, but I am confused with the contradiction I mentioned before)? Thank you!
There are a few videos in the playlist that explain that apparent contradiction.
But sir please explain what you mean by pressure of the fluid. Is it the hydrostatic pressure or the static? And where is this pressure exactly applied? Parallel to the walls of the tube or vertical to them? Just ''pressure of the fluid'' doesn't help me at all to understand 😒
When you dive down to the bottom of a swimming pool, or a lake, or the ocean, you will pressure on your ear drums. It doesn't matter where you are, everywhere in the water sufficiently deep you will feel that pressure.
Dear Sir............Example Problem : One hydraulic cylinder, the end is connected to the Threaded rod so that it can be rotated. Cylinders with a bore size of 18 mm, 10 mm rod and a stroke of 300 mm single acting in a condition that is filled with oil. If the cylinder is rotated 10 mm.
a. How to calculate it
b. What is the gauge pressure
Beautifully explained. 👏
Thank you. 🙂
Very clear explanation! I understood everything you were saying in this video. I wish you were my fluids professor :(
*Edit: forgot to say thanks a bunch!! :)
This is really interesting - thanks for all these great videos.
Our pleasure!
Wow, very useful video. Hi am Mech. Engr working in the stream of quality in construction and piping. can you please tell me, is the above Bernoulli's equation applicable to find the pressure drop in hydro testing procedure.?,
Depending on the application, you may need to include type of fluid used, viscosity, temperature, material of the pipes, etc. But this will give you a good estimate in an "ideal" situation
@@MichelvanBiezen ok then were any pressure drop occurs during hydrotest, ?? On the pipe which has the elevation of 8mtr,??
very useful video thanks for sharing. I have a question, how does the Bernoulli equations adapts to the situation where both the area and height varies in the pipe? Do you have any video for it, If so could you share ?
I don't think we have such an example, but it is a excellent suggestion. We'll add it to the top of the list of videos to make.
Great , Thanks I will be looking forward to that video :) Best wishes
😇what if a question was like this ( a water tank has a valve at the bottom. If this valve is opened, what is the maximum height attained by the water stream coming out of the right side of the tank? Assume that h = 10.0 m, L = 2.00 m, and θ = 30.0°, and that the cross-sectional area at A is very large compared with that at B.) how can solve it
Solve for the velocity of the water coming out of the hole (as shown in a video like that in this playlist). Then calculate the vertical component of the velocity (Vo sin(theta)) and then use the equations of kinematics to determine how high it goes V^2 = Vo^2 + 2 g (h)
Congratulations on 500,000 Subscribers.
Thank you. We appreciate it.
Is the pressure in Bernoulli's equation the pressure exerted on the fluid in the tube or the pressure exerted by the fluid
It is the fluid pressure.
Michel van Biezen Thank you :-)
Hii Sir, how we calculate drain time of pressurised closed pipe (two isolation valve) as if we consider water is at 7 bar as it start drain pressure star decreasing
That is a bit complicated to try and expalin in the comment here. We hope to cover that type of question in the future when we expand our playlists on fluid dynamics.
Great explanation. This was very clear and easy to understand. Thanks for posting this video!
your videos are INSANELY good! Im learning a lot. Keep it up! :)
You know... for years I've heard 'I Lecture Online' as 'Electro or Electric Online' because those are your videos I have mostly watched haha.
Yes, many viewers interpret it that way. (I think it is funny).
Well explained, perfect concept development. Most of all is gorgeus, instant subscribe and like for you sir.Best regards from indonesia
Welcome to the channel!
If you use your cantilever for a piping systeme support , how do you calculate the dynamic charge of the fluid and then add the dynamic weight to the centalever calculation ?