The Best Self Working Card Trick! (Tutorial)
ฝัง
- เผยแพร่เมื่อ 4 ต.ค. 2024
- The best self working card trick you will ever see!
You don’t even need to touch the cards at any point.
The cards can be shuffled and even borrowed.
Follow @AshMarlow52 for more…
Instagram, TikTok, Facebook and TH-cam.
This is crazy!! Ive done it 6 times and worked every time! Thanks for sharing
Insane! One of the best self working tricks I've ever seen. I'll definitely be adding it to my routine. Thank you! 🙂
This is simple arithmetic. You have 3 piles of cards on the table. Each of them has a card on the top that determines the number of cards in that pile. If the card has a value of X (A=1, 2, 3..., Q=12, K=13), the number of cards in that pile is 14-X (13 for A, ..., 1 for K). So, the total number of cards on the table is 3*14-X-Y-Z (X, Y, Z are the 3 topmost cards on the table). So, there is a 52-(42-X-Y-Z) = 10+X+Y+Z cards in the packet in hand. Then, if you substract X+Y+10 from this number, there are always Z cards left in hand. No magic, simple math :)
"it's not real magic!" ah comment
Whoever worked that one out??? Brilliant. Thanks so much for sharing 😊
I’ve been searching for this! My cousin showed me how to do this trick 10 to 15 years ago and told me I should be able to figure it out since I was good at math. This is the only trick that still amazes me
absolutely amazing trick one of favourite that i have learnt
Hi there, I learned this trick many years ago - well a variation of it. It's one of my favourites. It's all based on arithmetic. 13 is a key number: hint, hint. Thank you for sharing.
Very cool! Finally one of these I can get to work!
That’s awesome!!!
You have to somehow seem like more than just going through a procedure. There has to be an element of 'magic'.
The spectator needs to be as involved as possible. They shuffle the deck. They pick 5 random cards and lay them face up on the table. You count each pile to 13 as usual and flip the pile. They point to the two random piles that you place under your deck. They turn over top card on two of the 3 remaining piles. You just say, "okay, ten plus (top card) plus (other top card) equals (whatever). Then you deal out that number. Hand them the rest and have them count them. You say," that's amazing! I can't believe it. That's exactly the value of the top card on that pile!"
Have them turn it over!"
On a previous video, you counted off the word "impossible", one card for each letter - I use this version. I'm a support worker, and I did this with a young man I support who is Autistic. I called it the Impossible card, and had him mostly handling the cards. He was amazed at the outcome.
Given outer cards are both K, then K+K+10=36
For K in middle, then only 3 cards on table so you have 49 cards in the deck.
36 + 13 (value of middle K) = 49
For Q in middle => 4 cards on table & 48 in deck; 36+12=48
For A in middle=> 15 cards on table; 37 in deck; 36+1=37
It works ❤😍 amazing
I’m not sure why mine isn’t working, do you take out aces? Or how much are aces?
aces are 1
There's a different version of this trick that I"ve been doing since I was a kid. Instead of counting to 13, count to 12 instead. Also, I start counting with the cards facing up so I can see the value. If I get a J, Q or K as the starting count card, I shuffle it away. The trick is more effective if the number cards are on the top...otherwise, you'd have to explain the value of those 3 face cards. Before I start the count to 12, I'll tell the spectator that I'll shuffle the cards randomly...mainly just looking to avoid the J, Q and K. With a 12 count, you should be able to deal out more than 4 packs...maybe 5-7 or so. Either way, have the spectator remove the piles in excess of 4. Then have them turn over the top cards of any 3 piles. Add up those 3 cards and don't add 10 to that number as the video trick shows. Whatever number of cards remains will be the last top card of the 4th pile. This is a great and simple trick.
Super helpful tips, thanks!
I picked a king so had nothing to count to 13
What is this trick called? I'd like to see it done live so i can see the speil .. otherwise it's just counting out 13 a lot. (I know i can ask them to pick the cards etc but still need a reason we are doing any of it )
The power of 13
This is indeed a freaky trick, and there isn't an explanation on how it works. But the main thing is if others like the trick when you perform it that what matters.
What do you do if the card is an Ace?
then the value is one and you add 12 cards
@@DragantanWoW Thank you
I ran out of cards i had 9 and 10, then added 10 (29) and didnt have 29 left
you gotta put into the deck the two packets you removed and then you will have a sufficient number of cards
@@qotbahly4633 not if the decks you removed started with high numbers like face cards.
@@bcwalker1 no, you're wrong. The removed piles are totally irrelevant. If you have 10 and 9 on the table, the maximum number of cards on the table is 4+5+13=22 (4 for 10, 5 for 9, and 13 when there is an Ace in the 3rd pile; if the 3rd card is higher, the number of cards is smaller). Then, (in case of Ace) you have 30 cards in hand. You substact 29 and 1 is left, indicating the Ace.
You must have made a mistake. This is impossible.
It works almost every time. It breaks for me when I deal two or more kings when building the 5 piles. No idea why.
You need to have less than 13 cards left in your hand for it to work I think
It doesn't work.
Same with me😢
@@fernandezhernan1 🤣🤣 maybe we're just stupid
Maybe
@@fernandezhernan1 🤣
Works every time
Why are all card tricks 'the best'? Hmmmmmmm......
Need to find a way to explain adding 10 cards to the count. Open to any suggestions.
10 is my lucky number. Isn't it yours? LOL.
Before the trick, ask the spectator for their lucky number in between 1-10. Whatever they say, subtract from 10, and claim that number as your lucky number and remove that many cards equaling both numbers before starting. Or you can simply remove ten cards before hand. Basically, the trick works with 42 cards.
Just say you have to count a card for every letter in CARD TRICKS (that's 10 letters)
3 pack back on table and We count to 13….no one ask a bit.or play with 42 card. It should work 👍
I tried this. Not getting it correct and finding out that I forgot the K of Clubs in the box😂😂😂
Treat it as 1
So ace, 2,3,4,5...
And so on
that was my card! you are a master magician, lol
I spotted that the 3 of D was the first card in the 4th packet. So it’s just a maths trick. If we didn’t see the card at all then it would have been impossible.
I'm amazed that so many gullible people say this trick works. Like his other tricks, this is not a trick, it's a fraud... designed, I guess, to see how many people will fall for it. Not only can this "trick" not work, this "trick" cannot work... or if it ever did, it would be a total coincidence. Any good statistician can tell you why... I don't have the time or inclination to do that here.
This trick works if you try it… must remove jokers and have all 52 cards. It’s maths, also it’s amazing. All my tricks work 👌🏼
I've done this loads of times and it works every single time
did you even try it yourself?
I followed along with the video doing it myself. I was amazed that it worked.
You are totally wrong. You just don't understand this kind of tricks. It is nothing to do with statistics, but it's based on simple arithmetic. I posted the explanation.
another lie intended to waste your time.
Take out both jokers have all 52 cards and try again… all my tricks work
Did it 3 times, worked the 3