Constant Current Regulator using Transistor and Zener diode | CCR | BJT as a current regulator.
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- เผยแพร่เมื่อ 18 มิ.ย. 2024
- #foolishengineer #ConstantCurrentRegulator #Transistor
0:00 Index
00:20 what is the current regulator
01:35 Current regulator design
02:17 Current regulator using BJT & Zener
03:15 Circuit diagram
04:07 Current regulator example
06:41 Simulation of Current regulator
07:36 Advantages
07:46 Disadvantages
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The world's best teacher thanks nice explanation
thank you so much! you made my day
Very simple explanation! Thank you
THANKYOU AMAZING
very good i have to design a project for college and we are using a bunch of these. thanks for explanation
You are welcome!
Very good....thank you...
Thank you so much for watching!! Please subscribe to our channel
Emitter current is equal to base current plus collector current. So here question is arises that 122ohs resistance branch current is equal to emitter current.pls explain
Hi if we using voltage 3.7 with constant current of 10mA or 20mA or 30mA and than we want to voltage should be less than 3.5 . so what components should be use?
That was very helpful (I think). Would I be right in thinking at that input voltage it's super inefficient? i.e. there's more power dissipation over the other components than from the LED?
Yes, you are correct. But it is cost effective & easy to use
@@FoolishEngineer thanks for confirming. I really wasn't sure!
What do you think of’proteus for circuit simulation? it seems to me their are not very precise regarding some transistors’s specs, i Don’t know about LTspice
LTspice is used widely in industry. I don't know about Proteus!
Thank you so much for watching!!
5:19 sir.. one double..
where is written 10mA on datasheet.. a am confused..
please reply... thanks
How did you get 10mA for Iz? not 37mA?
So nice
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First, I am very far to be an expert but maybe this can help understanding efficiency of this circuit and why in some cases it can be usefull and give a good efficiency while in other cases it will give poor efficiency and should be avoided:
IMHO, I think this circuit is suitable and very usefull when the load is well know and components are adjusted to average load and do not change too much, it is not really made to be versatile and used with uncontrolled loads.
As the base & zener diode currents are very small they may be ignored in total power consumption, so powering a single 2.2Vx50mA LED (110mW) with a 14V battery ouputting at least 50mA will always result in a bad efficiency as the total consumption with this circuit will always be at least 700mW for 50mA (14*50), wich give an efficiency of 15% for A SINGLE LED (590mW lost).
But :
1 - with a lower voltage V+, efficiency can increase a lot, using lower voltage zener (or maybe rather one or two regular diodes) but it would become less versatile and wont allow a big change in loads, ex: with V+=3V and one or two regular diode in place of the zener diode, it would give an efficiency of ≃ 75% as PT = 3V*50mW = 150mW
2 - efficiency can also be a lot better in case this circuit is used for more than one LED, with a maximum of 3 LED in this specific case (V+ = 14V and zener = 6.8V) wich give 2.2*3=6.6v (330mW), then the efficiency become 15%*3 ≃ 45% (or 330mW/700mW), efficiency can be even higher with more LED using a lower voltage zener.
PS: in case it is necessary to deal with a wide range of unpredictable loads there are probably a lot of better and more versatile ways, but more complicated and costly (like DC-DC Buck converter).
What if we need a 8V Across the load
Sir , i want to make a constant current power DC driver , for my LED strip ..
The required constant current is around 300 mA , and Load is around 60v , plzz suggest something acoordingly ..
You can use the same circuit
300 mA current ??
Same circuit is able to power that much current ??
Can you pls tell which simulator you are using?
LTspice
Big fan
Bas kya Bhai!!!!
Why you selected 6.8v zener diode
Can I know why the Vz and the Vre should be the same? I think Vre should be Vz - Vbe. Am I wrong?
Imagine Vz as a reference and Vre is the negative feedback which is given to the regulator, as mentioned in the working the voltage drop across both zener diode & Re takes care of the regulation process.
@@FoolishEngineer Thank you so much. It took me 3 weeks to understand the idea. Because the feedback path for this circuit is implicit. So it's so hard to understand.
Foolish Engineer, that's a bullshit response. Vz and Vre are NOT the same!. Vre will always be ~0.7 volts lower than Vz. The base -emitter junction of the BJT acts like a diode. Build the circuit and see!
This can't be... if there is a voltage V_BE, then V_Z = V_BE + V_RE, and not V_Z = V_RE... V_BE should be around 0.7V if it is made of silicon, so V_RE is 0.7V smaller than V_Z. At 3:38, it is wrong... later you include V_BE = 0.7V and then it is right... XD