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Here Why synchronous bit is not counted to find bit duration? Example 6.10 We have four sources, each creating 250 characters per second. If the interleaved unit is a character and 1 synchronizing bit is added to each frame, find (a) the data rate of each source, (b) the duration of each character in each source, (c) the frame rate, (d) the duration of each frame, (e) the number of bits in each frame, and (f) the data rate of the link. Solution We can answer the questions as follows: a. The data rate of each source is 250 x 8 = 2000 bps = 2 kbps. b. Each source sends 250 characters per second; therefore, the duration of a character is 1/250 s, or4 ms. c. Each frame has one character from each source, which means the link needs to send 250 frames per second to keep the transmission rate of each source. d. The duration of each frame is 11250 s, or 4 ms. Note that the duration of each frame is the same as the duration of each character coming from each source. e. Each frame carries 4 characters and I extra synchronizing bit. This means that each frame is 4 x 8 + 1 =33 bits.
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Your Appreciations, care and share matters a lot to me. #EnginneringLove.
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
You & this video are the reason why I still have my job. Thank you 😂🤓
Your welcome dear 🙏
Thank you sir ....it will be very helpful for me...
Thank u sir for your valuable lecture
Well done sir. Good explanation, however E1 is relevant in our case. Had to convert ur teaching to corresponding E1 standard. Thanks anyways.
sir i am following your digital communication playlist, which is proving very helpful.The way you are delivering the lectures is awesome . I simply wanted to ask what all topics are you going to cover under this playlist?
Definitely Yes
Sir voice sig is band pass signal ..so how we can find fs like this
Voice is low pass filter with cut off frequency around 3khz.
Sir why did you take two different formula for Rb and why we didn't use 1/Rb for bit duration.
In example 1 what is the difference between bit rate and transmission rate?
The bit rate is for a single bit. The transmission rate is for all the bits, that is the whole frame.
Sir shudnt the frame duration be called sample duration...duration of one sample of one channel only?
Nope
What is the difference between Bit rate and Transmission rate?
Bit rate is just for 1 sample and transmission rate is for whole frame
Transmission rate=24*bit rate+8000
Here Why synchronous bit is not counted to find bit duration?
Example 6.10
We have four sources, each creating 250 characters per second. If the interleaved unit is a character
and 1 synchronizing bit is added to each frame, find (a) the data rate of each source, (b) the duration
of each character in each source, (c) the frame rate, (d) the duration of each frame, (e) the number of
bits in each frame, and (f) the data rate of the link.
Solution
We can answer the questions as follows:
a. The data rate of each source is 250 x 8 = 2000 bps = 2 kbps.
b. Each source sends 250 characters per second; therefore, the duration of a character is 1/250 s,
or4 ms.
c. Each frame has one character from each source, which means the link needs to send
250 frames per second to keep the transmission rate of each source.
d. The duration of each frame is 11250 s, or 4 ms. Note that the duration of each frame is the
same as the duration of each character coming from each source.
e. Each frame carries 4 characters and I extra synchronizing bit. This means that each frame is
4 x 8 + 1 =33 bits.
Please reply me as soon as possible
Each bit is independent of the other. So time of one bit won't affect the other.
3.4*2=6.4 👏🏿
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