Visually, in less than a minute, we see that the possibility set is 4, 1, 1 X can be 4; Y = 1 ; Z = 1; Y can be 4; X = 1 ; Z = 1; Z can be 4; X = 1 ; Y = 1; I tried to find the values by developing the equations, but I didn't find a successor. Now I'm going to see your magic!!!!
Consider a=x½, b=y½, c=z½ and eq a+b+c=4, a²+b²+c²=6, a⁴+b⁴+c⁴=18 a,b,c are nonnegative By the routine calculations, ab+bc+ca=5, abc=2. So {a,b,c}={1,1,2}. Thus, {x,y,z}={1,1,4}. Note that { } is a set symbol.
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X=1, y=4, z=1
Right but there are total 3 solutions.
Visually, in less than a minute, we see that the possibility set is 4, 1, 1
X can be 4; Y = 1 ; Z = 1;
Y can be 4; X = 1 ; Z = 1;
Z can be 4; X = 1 ; Y = 1;
I tried to find the values by developing the equations, but I didn't find a successor. Now I'm going to see your magic!!!!
Thank you
SENSATIONAL!!
Thanks!
Consider
a=x½, b=y½, c=z½ and eq
a+b+c=4,
a²+b²+c²=6,
a⁴+b⁴+c⁴=18
a,b,c are nonnegative
By the routine calculations, ab+bc+ca=5, abc=2. So {a,b,c}={1,1,2}.
Thus, {x,y,z}={1,1,4}.
Note that { } is a set symbol.
Correct but it is only one of the 3 solutions.Thanks for sharing and your feedback!
@@vijaymaths5483 { } is a set symbol. This set symbol contains all three solutions.
13:38 it is easy to use SDM instead of long division.
You mean synthetic division method?
@@vijaymaths5483 yes
Amazing!
Thanks!
How do you get the cubic equation of m?
Nice solution 👏
Yes, thanks
Great effort for solving the solution Thanks 👍
Welcome 👍