Set Theory-Maxima-Minima In Case of Three Sets (Part -II)

[@LRDIprep]

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[@bipinmahadik7969]

Stop hiring such unprepared teachers. The solution is INCORRECT. The intersection (All 3) value is fixed viz. 20. sum(Exactly 2) = 35 and sum(Exactly 1)= 60.
Be responsible with what you teach.

[@punjabmotorcycle2704]

Thank u Sir helped a lot

[@morningstar2728]

Thank you 💗

[@jirensama1622]

This is tough

[@vinayrj2766]

Amazing explaination 👏

[@elizabethleiva230]

thank you so much.

[@Santhosh-lv5mp]

Why you choose option a is correct

[@snehilkumar6643]

I think the minimum value of all three should be 20. And maximum of all three should be 25. If we take 15 as minimum, values don't add up to 115.

[@alishamanchanda728]

nicely explained

[@vimalk.r1570]

Very well explained. Thank you sir

[@kevinmmathew3453]

Thank you Sir

[@shashankgupta7767]

Thank you so very much sir...:))

[@anuragpandey2004]

Sir i am in 12th preparing for nda....your videos taught me alot....thank you so much.....

[@chetanyasharma2502]

This question has a definitive solution, no maxima minima and all. A*B*C=20, that is the only possible value. If you put A*B*C=15, then all values will not add up to 115

[@bipinmahadik7969]

Yesss! All 3 = 20, Exactly 2 = 35, Exactly 1 = 60.

[@TheScott689]

I’ll admit it’s not clearly mentioned throughout most of the two part video, but you are forgetting about the “not A, not B, and not C” region.
Depending on how many people we say are not part of any of the 3 sets, the answers can change.
In other words, we start out with two unknowns: n( A and B and C) and n(none of the 3 sets)
The approach is valid

[@arnabkumarroy496]

🙏🙏

[@priyanshtiwari2467]

can we do the same sum with chocolate concept?

[@shubham_banka]

✔️

[@payalverma2924]

Thank you sir