Yes. I said that because KI was not in the instructional material which react with lead to give a bright yellow ppts, nor was Na2S there which also react with lead to give a black ppts. Actually they might ask them to add potassium dichromate to give a bright yellow ppt
Thanks for all you do sir. You've convinced me to finally subscribe. How do you get enough distilled water ? Did you prepare it or it there a way to go about it?
Please sir how many mole of HCl, HNO3, H2SO4 ,and NH3 and in how many cm3 to make a bench reagent, also how many gram of NaOH and BaCl in what cm3 to make a bench reagent. Thanks sir.
1. HCl (0.1M HCl in 500cm3) C1V1 = C2V2 C1 = 12M V1= ? C2 =0.1M V2 = 500cm³ 12M x V1 = O.1M x 500cm³ V1 = 4.2cm³ (Measure 4.2cm³ of HCl and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 2. H2SO4 (0.1M H2SO4 in 500cm3) C1V1 = C2V2 C1 = 18.4M V1= ? C2 =0.1M V2 = 500cm³ 18.4M x V1 = O.1M x 500cm³ V1 = 2.7cm³ (Measure 2.7cm³ of H2SO4 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 3. HNO3 (0.1M HNO3 in 500cm3) C1V1 = C2V2 C1 = 15.9M V1= ? C2 =0.1M V2 = 500cm³ 15.9M x V1 = O.1M x 500cm³ V1 = 3.1cm³ (Measure 3.1cm³ of HNO3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 4. Ammonia NH3 (0.1M of 35% NH3 in 500cm3) C1V1 = C2V2 C1 = 18.1M V1= ? C2 =0.1M V2 = 500cm³ 18.1M x V1 = O.1M x 500cm³ V1 = 2.8cm³ (Measure 2.8cm³ of NH3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 5. NaOH (0.1M NaOH in 500cm³) Weigh 2g of NaOH into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water 6. BaCl2 (0.1M BaCl2 in 500cm³) Weigh 10.4g of BaCl2 into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water
1. HCl (0.1M HCl in 500cm3) C1V1 = C2V2 C1 = 12M V1= ? C2 =0.1M V2 = 500cm³ 12M x V1 = O.1M x 500cm³ V1 = 4.2cm³ (Measure 4.2cm³ of HCl and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 2. H2SO4 (0.1M H2SO4 in 500cm3) C1V1 = C2V2 C1 = 18.4M V1= ? C2 =0.1M V2 = 500cm³ 18.4M x V1 = O.1M x 500cm³ V1 = 2.7cm³ (Measure 2.7cm³ of H2SO4 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 3. HNO3 (0.1M HNO3 in 500cm3) C1V1 = C2V2 C1 = 15.9M V1= ? C2 =0.1M V2 = 500cm³ 15.9M x V1 = O.1M x 500cm³ V1 = 3.1cm³ (Measure 3.1cm³ of HNO3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 4. Ammonia NH3 (0.1M of 35% NH3 in 500cm3) C1V1 = C2V2 C1 = 18.1M V1= ? C2 =0.1M V2 = 500cm³ 18.1M x V1 = O.1M x 500cm³ V1 = 2.8cm³ (Measure 2.8cm³ of NH3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water) 5. NaOH (0.1M NaOH in 500cm³) Weigh 2g of NaOH into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water 6. BaCl2 (0.1M BaCl2 in 500cm³) Weigh 10.4g of BaCl2 into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water
It's the molar concentration of the stock acid solution. You get it by calculating the conc. Of the stock solution using a combination of the percentage purity, molar mass and density. If you want to learn more on it drop ur Whatsapp number n I ll send u a dm
Dissolve 1g of calcium hydroxide in 1000cm³ of water, mix properly and allow it to stand for several hours or overnight. Then carefully pour out the clear solution through a filter paper. The filtrate is your lime water.
You are doing well, but addition of aqueous Ammonia and sodium hydroxide are not confirmatory test for Lead
Yes. I said that because KI was not in the instructional material which react with lead to give a bright yellow ppts, nor was Na2S there which also react with lead to give a black ppts. Actually they might ask them to add potassium dichromate to give a bright yellow ppt
I wish I saw this page earlier .. you’re so good .. can you make a video on how to operate the electric scale , thank you sir
Thanks a lot 🙏😊
I will do that as requested by you
My brother you are too much,you are a grade 1 teacher,i appreciate your efforts so much,and i have subscribed
Thanks so much Sir! I appreciate your wonderful comment 😌🙏
You have done a great job ✅
Thanks Sir
Thanks for all you do sir. You've convinced me to finally subscribe. How do you get enough distilled water ? Did you prepare it or it there a way to go about it?
Thank you very much
My lime water didn't turn milky and the residue dried, what can i do
Ensure the pipe is inserted into the lime water, check ur lime water also
Pls I want to ask the HNO3, NH3 and HCL you added to the residue are they diluted or concentrated.
They are all dilute
Please sir how many mole of HCl, HNO3, H2SO4 ,and NH3 and in how many cm3 to make a bench reagent, also how many gram of NaOH and BaCl in what cm3 to make a bench reagent. Thanks sir.
1. HCl (0.1M HCl in 500cm3)
C1V1 = C2V2
C1 = 12M
V1= ?
C2 =0.1M
V2 = 500cm³
12M x V1 = O.1M x 500cm³
V1 = 4.2cm³ (Measure 4.2cm³ of HCl and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
2. H2SO4 (0.1M H2SO4 in 500cm3)
C1V1 = C2V2
C1 = 18.4M
V1= ?
C2 =0.1M
V2 = 500cm³
18.4M x V1 = O.1M x 500cm³
V1 = 2.7cm³ (Measure 2.7cm³ of H2SO4 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
3. HNO3 (0.1M HNO3 in 500cm3)
C1V1 = C2V2
C1 = 15.9M
V1= ?
C2 =0.1M
V2 = 500cm³
15.9M x V1 = O.1M x 500cm³
V1 = 3.1cm³ (Measure 3.1cm³ of HNO3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
4. Ammonia NH3 (0.1M of 35% NH3 in 500cm3)
C1V1 = C2V2
C1 = 18.1M
V1= ?
C2 =0.1M
V2 = 500cm³
18.1M x V1 = O.1M x 500cm³
V1 = 2.8cm³ (Measure 2.8cm³ of NH3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
5. NaOH (0.1M NaOH in 500cm³)
Weigh 2g of NaOH into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water
6. BaCl2 (0.1M BaCl2 in 500cm³)
Weigh 10.4g of BaCl2 into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water
@@ChemEasy_Eko
Wow... Thank you very for the break down analysis. I am grateful sir.
You are welcome
Wow, this is so helpful
Is it possible to use 2M of each of this solutionsinstead of the 0.1M you used. What is the implication?
Is it the same residue that was heated and passed through lime water that was used for the remaining tests or you only took a part of it?
The same residue
😮🎉🎉🎉🎉
Please sir what's the name of the holeyou used to pass the carbon dioxide gas to the lime water. And the name of what you used to cover the test tube
Stoppers or cork
Rubber latex hose
You're good Man
Thanks 👍🙏
Please can you teach me to prepare the reagents
1. HCl (0.1M HCl in 500cm3)
C1V1 = C2V2
C1 = 12M
V1= ?
C2 =0.1M
V2 = 500cm³
12M x V1 = O.1M x 500cm³
V1 = 4.2cm³ (Measure 4.2cm³ of HCl and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
2. H2SO4 (0.1M H2SO4 in 500cm3)
C1V1 = C2V2
C1 = 18.4M
V1= ?
C2 =0.1M
V2 = 500cm³
18.4M x V1 = O.1M x 500cm³
V1 = 2.7cm³ (Measure 2.7cm³ of H2SO4 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
3. HNO3 (0.1M HNO3 in 500cm3)
C1V1 = C2V2
C1 = 15.9M
V1= ?
C2 =0.1M
V2 = 500cm³
15.9M x V1 = O.1M x 500cm³
V1 = 3.1cm³ (Measure 3.1cm³ of HNO3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
4. Ammonia NH3 (0.1M of 35% NH3 in 500cm3)
C1V1 = C2V2
C1 = 18.1M
V1= ?
C2 =0.1M
V2 = 500cm³
18.1M x V1 = O.1M x 500cm³
V1 = 2.8cm³ (Measure 2.8cm³ of NH3 and add to about 400cm³ of distilled water and then dilute it to 500cm³ with distilled water)
5. NaOH (0.1M NaOH in 500cm³)
Weigh 2g of NaOH into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water
6. BaCl2 (0.1M BaCl2 in 500cm³)
Weigh 10.4g of BaCl2 into about 400cm³ of water. Stir properly until it dissolves and then dilute to 500cm³ with distilled water
God bless you is not enough.. God bless you abundantly
Hahahaha
Amen. Thanks 👍😊 Do well to subscribe!
Please your c1 how did you get the values
It's the molar concentration of the stock acid solution. You get it by calculating the conc. Of the stock solution using a combination of the percentage purity, molar mass and density. If you want to learn more on it drop ur Whatsapp number n I ll send u a dm
Pls sir how did you make lime water
Dissolve 1g of calcium hydroxide in 1000cm³ of water, mix properly and allow it to stand for several hours or overnight. Then carefully pour out the clear solution through a filter paper. The filtrate is your lime water.
This content is really loaded
Thanks my dear
I really love your teaching
I need your assistance, I kept getting 8.6 as my average, what can I do @ChemEasy_Eko
I want to ask if the residue you added HNO3 is the one you added other reagents. Or you added other reagents to the residue directly?
It is the residue I added the HNO3 directly