you can solve it algebraically using identities for csc^2x: we want to use "1+cot^2x = csc^2x" •find cotx first: tanx = -2√2 (from part A) cotx = 1/tanx, so: cotx = 1/(-2√2) •find cot^2x by squaring both sides: cot^2x = 1/8 •therefore using the aforementioned identity "1+cot^2x = csc^2x": 1+cot^2x = 9/8 csc^2x = 9/8 •finally root both sides for cscx: cscx = (3√2)/4
It would give the wrong answers when using the cos graph to find the other solutions. Cos theta= 1/2 theta = 60 degrees So theta = 60 in the boundary of 0180. Seen on many Mark schemes with trigonometry questions, they increase the boundary by the coeffienct of theta/x. Finding the other solutions, them dividing them solutions by the coefficient for just theta, and any solutions outside the default boundary is not accepted. Hope this helps.
Very juicy tekky equations you have submantled their Zeeshan
hey hey
If this guy was my maths teacher I would defo get an A*
You've got his vids here - no excuse cmon.
Yooo so sad no one saw cosPeter and sinPeter :'( such an underappreciated joke
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Who's that lucky peter man😂😂😂
Broooo what a legend
15:49 how would you get the value of 1/sin theta if you didn’t do the triangle method ?
Did you find out?
Just draw the right angled triangle again then find sin using tan then do the inverse
you can solve it algebraically using identities for csc^2x: we want to use "1+cot^2x = csc^2x"
•find cotx first:
tanx = -2√2 (from part A)
cotx = 1/tanx, so:
cotx = 1/(-2√2)
•find cot^2x by squaring both sides:
cot^2x = 1/8
•therefore using the aforementioned identity
"1+cot^2x = csc^2x":
1+cot^2x = 9/8
csc^2x = 9/8
•finally root both sides for cscx:
cscx = (3√2)/4
very very juicy video teacher of Peter. I approve.
11:49 how do i know its only the negative value that works without using the cast diagram
If u look at the the tan graph between 90 and 180 as that's the range, the line would be under the x-axis meaning that it's negative.
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you writing peter makes me go into depression
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14:56 , doesnt tan theta give you -1/3??
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18:15 couldn’t you have divided by 2 and gotten cos theta equals a half instead of having cos 2 theta
Yes
It would give the wrong answers when using the cos graph to find the other solutions.
Cos theta= 1/2
theta = 60 degrees
So theta = 60 in the boundary of 0180.
Seen on many Mark schemes with trigonometry questions, they increase the boundary by the coeffienct of theta/x. Finding the other solutions, them dividing them solutions by the coefficient for just theta, and any solutions outside the default boundary is not accepted.
Hope this helps.
you
Did he say juicy identities 💀
u must be new here
Best