Norms

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  • เผยแพร่เมื่อ 11 พ.ย. 2024

ความคิดเห็น • 44

  • @SorryBones
    @SorryBones ปีที่แล้ว +7

    Oh man, 3 years later and this is still saving students. Thank you for explaining it so clearly!

  • @heidioid
    @heidioid 2 ปีที่แล้ว +5

    Wow very good straightforward explanation. The simplicity and clarity is A+! Thank you so much for sharing this!

  • @oraz.
    @oraz. 2 ปีที่แล้ว +2

    This is the most in depth definition of the norm

  • @aminuabdulsalami4325
    @aminuabdulsalami4325 3 ปีที่แล้ว +3

    Excellent tutor. Norms made simple.

  • @samsilarifeen2367
    @samsilarifeen2367 2 ปีที่แล้ว +1

    simply amazing. you described it as crystal clear. Thank you so much.

  • @zeyadramadan8759
    @zeyadramadan8759 ปีที่แล้ว

    Excellent explanation of what the norm is. I was searching for days until I found your video. Well done and keep it up please.

  • @Rahul_IMD
    @Rahul_IMD ปีที่แล้ว

    You are advised to enhance your presentation technology i.e. video quality, obviously teaching skill and provided content is excellent 👍.

  • @tagoreji2143
    @tagoreji2143 2 ปีที่แล้ว +1

    Thank you Sir.It was a Wonderful Session

  • @johnk8174
    @johnk8174 2 ปีที่แล้ว

    can somebody link to the playlist that this comes from?

  • @SwavimanKumar
    @SwavimanKumar 3 ปีที่แล้ว +1

    So it's understandable that the L2 norm will give us the distance of the point from origin & L1 norm gives the sum of distances of its 3 base coordinates. But what L3 or higher norms of the same 3d vector signifies? I find it difficult to get the intuition behind higher norms in terms of distance. Kindly explain.

  • @apoorva3635
    @apoorva3635 3 ปีที่แล้ว +1

    Beautifully explained Sir!!

  • @rishisingh6111
    @rishisingh6111 3 ปีที่แล้ว

    Extremely well taught, thanks a ton!

  • @_justacoder_
    @_justacoder_ 3 ปีที่แล้ว

    please provide playlist link in description of the video

  • @adiai6083
    @adiai6083 2 ปีที่แล้ว

    Very nice explaination

  • @manasa2927
    @manasa2927 ปีที่แล้ว

    Crystal clear

  • @khayum009
    @khayum009 4 ปีที่แล้ว

    Is there any way I could get the slides of the presentation.. it would be helpful to make notes out of it..

  • @diegososa5280
    @diegososa5280 4 ปีที่แล้ว +1

    Great job, thank you

  • @arkadipbasu2348
    @arkadipbasu2348 3 ปีที่แล้ว

    Great explanation, thank you

  • @sumayyakamal8857
    @sumayyakamal8857 3 ปีที่แล้ว

    great vid, THANK YOU!

  • @captainstreamer3261
    @captainstreamer3261 3 ปีที่แล้ว

    At 7.19 min The Direction Of The 3rd Vector Is Wrong I Think , It Does not Satisfy normal vector addition rule ....

  • @अंशुमानअवस्थी
    @अंशुमानअवस्थी 3 ปีที่แล้ว

    Isn't it counter intuitive/ productive to associate a number with a vector/matrix.....i mean two entirely different matrices may have equivalent norms,but that closeness will mean nothing.!!!??

  • @bharathmadduri
    @bharathmadduri 3 ปีที่แล้ว

    Vector addition x+y is based on parallelogram rule of addition

  • @ranjithabc9004
    @ranjithabc9004 3 ปีที่แล้ว

    What is norm of a vector having complex numbers?

    • @physicsforum4725
      @physicsforum4725 2 ปีที่แล้ว +1

      as i know if we have a complex vector say Z=(1-2i,i,3i,1+i) and if we find 1- norm ,||Z||= (|v1|^2+|V2^2|+.......|Vn|^2 )^1/2
      =sqrt 17 so it gives a real number.

  • @ariffaridi6699
    @ariffaridi6699 2 ปีที่แล้ว

    Thank you, sir

  • @Ifeeezenwoye-ec6sx
    @Ifeeezenwoye-ec6sx 8 หลายเดือนก่อน

    I still don't understand 😢😢

  • @prithwishguha309
    @prithwishguha309 2 ปีที่แล้ว

    You Showed (x+y) Wrongly(in reverse direction)

  • @tulaycaglayan8674
    @tulaycaglayan8674 3 ปีที่แล้ว +1

    8:10 isn't it x-y instead of x+y?

    • @rinkukumar721
      @rinkukumar721 3 ปีที่แล้ว

      No, it is x+y, look at the tail and head of the vectors

    • @rinkukumar721
      @rinkukumar721 3 ปีที่แล้ว

      although, it's either of 3 vectors, one should have the opposite direction...

  • @shritejchavan6222
    @shritejchavan6222 5 ปีที่แล้ว +3

    I am unclear about the difference between Frobenius norm and L2 norm.

    • @AdityaMishra-ve6yu
      @AdityaMishra-ve6yu 4 ปีที่แล้ว +1

      L2 norm is for vectors while Frobenius is for matrices. The method is same however.

    • @BVSrinivasan
      @BVSrinivasan 4 ปีที่แล้ว +2

      To add to what Aditya Mishra said, Frobenius for matrices looks similar to the L2 norm for vectors. However, for technical reasons, there is a separate L2 norm for matrices with different properties.

    • @physicsforum4725
      @physicsforum4725 2 ปีที่แล้ว

      @@AdityaMishra-ve6yu if the method is same for both ,it must gives same value but acc ||A||2 should not be equal to ||A||f.

  • @MahmoudSY-f3s
    @MahmoudSY-f3s 3 ปีที่แล้ว

    Thanks Sir

  • @Arpita-fo2dl
    @Arpita-fo2dl 4 หลายเดือนก่อน

    done sir

  • @SMM_5
    @SMM_5 4 ปีที่แล้ว

    hi sir.. when this course will come in nptel?

  • @jamesang7861
    @jamesang7861 3 ปีที่แล้ว

    THANK YOU!

  • @anushkaverma914
    @anushkaverma914 4 ปีที่แล้ว

    For this is it compulsory that we have prior knowledge of MATLAB...

    • @BVSrinivasan
      @BVSrinivasan 4 ปีที่แล้ว

      No, it is not. It is just for demonstration.

    • @ytg6663
      @ytg6663 3 ปีที่แล้ว

      Hi, do you have job?

  • @vikashroy6058
    @vikashroy6058 3 ปีที่แล้ว

    1. Show that the following relations hold for the input signal u whose 2-norm ≤ 1. Here y is the output signal and G is the transfer function (stable and strictly proper)
    (a) ||y||2 = ||G(s)||∞ ||u(t)||2
    (b) ||y||∞ ≤ ||G(s)||2 ||u(t)||2
    (c) pow (y) = 0.