Your solutions are great and you go through the solution very effectively. Just one suggestion, avoid saying "it's pretty easy", multiple times because it can scare beginners.
bro your are explaining well but starters like us cant able to catch your idea . so pls write your explaination as a psedocode and then start writing the code . so that youill get a good recognition amoung people like us .
People use leetcode for internships/jobs/competitive programming. Don't try to do leetcode just for fun lol. Learn your desired language to a certain degree first. Easies aren't easy for someone with a little bit of programming experience either. You need to fully understand your programming language to solve some easy questions. Apart from fizz buzz or defanging an IP address or whatever, lots of easies are challenging.
I didn't get idea of using last if statement, every time you are adding even numbers to result and then 1 in the result, won't that make the same sense adding them in first place, coz you you divide something by to and multiply the result by 2 it will always be even then why if statement?
This it to add one non-matching character to be considered palindrome string. We are allowed to add only 1 character which does not have a matching. In the example output in leetcode window("dccaccd"), it was character 'a'. Once you add one such scenario, you are not allowed to add one more e.g: 'b' which was left out from output. This was achieved as result became odd once 'a' was added.
Good explanation, So you say that add all the even characters length to palindrome's length and finally take the longest odd number character length. am I right ?
@@HK-ct1tg @Vineet Rawat We need to add all even lengths characters but for odd length, we may take any 1 character (as a center char) if you have multiple odd characters. Also keeping in mind we will be considering all the odd values too in sum but just 1 less every time.
![Longest palindrome substring - LeetCode Interview Coding Challenge [Java Brains]](http://i.ytimg.com/vi/DK5OKKbF6GI/mqdefault.jpg)
Your solutions are great and you go through the solution very effectively. Just one suggestion, avoid saying "it's pretty easy", multiple times because it can scare beginners.
how is this considered easy?
lol
Really tricky to think of. Thanks Nick
I was trying to this problem on my own, I closely come up with a solution, but it was to verbose. This video helped me a lot
One question, why a wrapper class Integer is used in second for loop instead of primitive type?
my mistake i think i accidentally typed that out
you can use primitive type as well
Anything is fine there
The best solution Nick..Awesome
Thanks a lot, ez and helpful solution!
bro your are explaining well but starters like us cant able to catch your idea . so pls write your explaination as a psedocode and then start writing the code . so that youill get a good recognition amoung people like us .
You probably shouldn't be doing competitive programming if you don't know how to code.
People use leetcode for internships/jobs/competitive programming. Don't try to do leetcode just for fun lol. Learn your desired language to a certain degree first. Easies aren't easy for someone with a little bit of programming experience either. You need to fully understand your programming language to solve some easy questions. Apart from fizz buzz or defanging an IP address or whatever, lots of easies are challenging.
I didn't get idea of using last if statement, every time you are adding even numbers to result and then 1 in the result, won't that make the same sense adding them in first place, coz you you divide something by to and multiply the result by 2 it will always be even then why if statement?
This it to add one non-matching character to be considered palindrome string. We are allowed to add only 1 character which does not have a matching. In the example output in leetcode window("dccaccd"), it was character 'a'. Once you add one such scenario, you are not allowed to add one more e.g: 'b' which was left out from output. This was achieved as result became odd once 'a' was added.
My like for the concise code.
what if we had 3 'e' and 5 'f' other than these characters ?
the if condition will only work once and after that it will never be satisfied
@@kamalpreetsingh4782 oh now I got it
Thanks bro
After one if condition, string would become odd and will remain always after that
Good explanation, So you say that add all the even characters length to palindrome's length and finally take the longest odd number character length. am I right ?
+1
@@HK-ct1tg @Vineet Rawat
We need to add all even lengths characters but for odd length, we may take any 1 character (as a center char) if you have multiple odd characters. Also keeping in mind we will be considering all the odd values too in sum but just 1 less every time.
Thanks a lot
2:04
Cool!!!
truly greedy