EXTENSION THEOREM OF BASIS | LINEAR ALGEBRA 🔥

[@shining8oyfitness]

Amazing explanation 👌🙏

[@Soravsharma-mh1qg]

Thnku sir ❤🎉

[@sonamabrol8916]

Ty very much sir for this video ...you explained this theorem in very simple way ..I understood this theorem..

[@ashusharma8929]

Very nice and easy explanation 👌

[@niharikathakur284]

Your video such very helpful

[@rana.archit]

Samajh m aa gya sir thankyou ..

[@shubhamshinkar5692]

Good video sirji

[@devrajgour91]

Classic video ....thanks sir

[@MathematicsAnalysis]

Thanks dear

[@RohitKumar-xm9po]

Thanks a lot & sir aap Comment or description mein pdf ka link de diya kariye 😅

[@prernapatel9988]

Sir jb B elements bhi basic hai it means vo bhi L.I. hoge to phir Bi ko hi ku remove krege... please sir reply

[@janmejaybehera8405]

Nice sir ji

[@Princek0707]

With the same argument bets are also linearly independent as they are basis elements.

[@sdmusicworld1922]

❤️❤️❤️

[@mathsclass3692]

Sir I have proved extension theorem in other way.plz give your suggestion about the proof

[@omgaytri2859]

Tq sir.

[@AmitKumar-og2dh]

prove that there exists a basis for each finite dimensional vector space. Sir answer kya hoga

[@AartiPal-t5m]

Sir in sabhi theorem ki playlist bna dijiye

[@ashusharma8929]

But sir beta terms are also a basis of v ,then set b bhi li hoga ,to fir beta se hi element kaise liya gya.

[@fiziksfire]

Thanks sir

[@simhadridevada2958]

Thank you

[@mraspirant9326]

One doubt sir
..we have considered B be a basis...then elements of B also linearly independent

[@kalpanabhandari6043]

Same here

[@monteesaran5896]

Yes of course basis vala set linearly independent e hota h

[@kavitakohli5632]

Yes exactly my doubt , I came here looking for this particular doubt

[@prernapatel9988]

Ya particular usi doubt ke karn aayi thi mughe bhi yhi confusion hai ki B hi ku le rhe jb vo bhi basis( L.I.) hai to

[@Devil-dn2ew]

Came for the same doubt? Did u get clarity, pls explain?

[@lovepreetsingh6682]

Sir. Phele to screen ke jo left side per. Mathematics h. Yo problem de rha hai.

[@rajendrarawat6923]

Basis and dimension mai jitni v theorem hai unko night tk apload kr lena becouse kl ppr hai

[@ritesh5090]

Sir pura book ka to chaap diye ho , kuch practical examples deke samjha dete to syd achaa hota 😂😂😂

[@rajendrarawat6923]

Sir plzzz invariance theorem v abi dalo kal ppr hai

[@sonamabrol8916]

One dout sir....
Agar hum pura yahi theorem exam mein krenge toh full marks mil jaaega..or aapne sirf understanding k liye bnaayi hai??

[@ushamishra4589]

May be this video will help you
th-cam.com/video/luT4lfGNWBg/w-d-xo.html

[@subhamsaha17]

Extension theorem k problem par video baaniye sir

[@ushamishra4589]

th-cam.com/video/luT4lfGNWBg/w-d-xo.html

[@googgli3965]

Iska ek do application bhi btaye .. Ek qsn h jo ho nhi rha h

[@meghasahu3177]

Thanx and nice but I want to all process in the discription box pls

[@MathematicsAnalysis]

Ok dear

[@meghasahu3177]

Pls sir

[@sajidmunir560]

Any finite dimensional vector space contains a basis ka proof nhi hai

[@alokarya319]

H k yo 😝

[@defencewarrior7993]

Sir iska 18 marks mil jayega 🙏🙏🙏🙏

[@kumariekta6500]

Yha equcation b vala set to khud linear indepdent hota h fir hm use linear combination theorem me bi kyu kete h

[@ushamishra4589]

th-cam.com/video/luT4lfGNWBg/w-d-xo.html

[@dhakadmathconcept6032]

Last moment n-m kese hua

[@ushamishra4589]

th-cam.com/video/luT4lfGNWBg/w-d-xo.html

[@Amityadav-il2rp]

Sir ji samajh nhi aaya
😢

[@himangshukalita3099]

Eliminate Beta me se hi Kyu karu. Betas to basis ka part he or isliye linearly independent bhi he.

[@Hah948]

Chomu usne alpha vale let kiya hai L.I starting mai dekh, beta’s k element sb bad mai consider hua hai

[@Hah948]

Condition k according isme betta belong ni krta basis mai srf alpha k krte

[@reakhakumari7794]

Complete theorems smjao

[@MathematicsAnalysis]

Coming soon

[@pardeeptechofficial]

Kuch nhi smjh mein Aya sir sab uper se gaya

[@reakhakumari7794]

Basis and dimensions ki

[@JasbirKaur-vq7iy]

Sir I think there one mistake...
If final basis is S itself ( all beta's get removed) , then there is no extension in no. of elements of S....
Plz review it ..

[@kumariekta6500]

I think so because union make LD to make LI then we take beta and remove all the beta and this minimal set is make which is definitely a Li

[@crazy_rider46]

Key full mark milega

[@MathematicsAnalysis]

Ha

[@Village_vlogger-24x7]

Very bad explanation

[@mathsclass3692]

Sir I have proved extension theorem in other way.plz give your suggestion about the proof