There is a small correction, In ur 1st slide ( rotational raman), In the calculation of transition btw j to j +2 , in the second step it is (j+2+ 1) , u have written it as ( j +2 + 2). But you got the answer correct. No issues.
relative intensities of successive lines in the obtain raman spectra of nitrogen molecule is (a) 1:3 (b) 2:3 (c) 3:4 (d) 1:2 What will be the answer and how?
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Very good explaination 👌👌👌. Thank you madam👍
There is a small correction,
In ur 1st slide ( rotational raman),
In the calculation of transition btw j to j +2 , in the second step it is (j+2+ 1) , u have written it as ( j +2 + 2). But you got the answer correct. No issues.
One mistake is there B(J+2)(J+2+1)this is correct you written (J+2+2) remaing good very good explanation
Thanks a lot Ma'am....
Tqs mam🙏 from my side because of i was fully doubted 😔
Thanku mam😘❣️❣️❣️😍
Thank you so much mam......❤
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Prestigious mam
Tq 🙏🏻
relative intensities of successive lines in the obtain raman spectra of nitrogen molecule is
(a) 1:3
(b) 2:3
(c) 3:4
(d) 1:2
What will be the answer and how?
Thank you very much ma'am
well explained 😊
thank you very much mam..
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Simple and fine.
Nice information.. madam
J+2+1 or J+2+2 ?
Mistakenly written . it shud be (j+2+1)
Qualitative lecture
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Mam,plz spectral structure ko bataiye na
Nice explanation
Tq Madam
Thanx alot mam for this video🙏🙏🙏
About transition is super mam
Nice one☺
Thank you mam 😊
Very good effort ....
At 3.29 it shud be B(J+2)(J+2+1) not (J+2+2) crct it please.
happy teacher,s day mam
Exam mai no to cut ni hoge agr ye kr diya to
thankyou mam
Nice
Thank u mam
Thank you so much ma'am