Time to learn the entire A2 course in 2 days because someone spent most of year 13 doodling in her book rather than paying attention in class. Great work on these videos btw, I think if I put in even half the effort you do I could probably get an A :D
Something that you didn't necessarily cover is the question type where you are given like the flow rate of a machine in Kg/s. So you must use the fact that P= Q/t to calculate the Power of the machine when only given change in temp and flow rate. :)
I have trouble understanding what you did from 10:30 . Doesn't water have different specific heat capacities at different states? If it does, then why can we use E = mcT to calculate the energy in raising the temperature at two different states?
At 11:09 you say that we can combine the change in temperature for both ice and water but I don't think we can as the specific heat capacity for ice and water are different. Won't it give a different answer?
At 12:32 , why is it (20-T) isn’t the change in a factor (final - initial) so whatever the final temp is at comes first. You did final minus initial for ice where u said (T-5) but not for the first part. Could u explain why ?
The change in temperature must always be positive as it is a magnitude, we know T must be less than 20 but higher than -5. So T-20 will be negative and will not be used whereas 20-T is positive and used.
The T is the temperature that is transferred due to equilibrium into the other substance - Ice. T is therefore lost by the orange juice and gained by the ice, but as the ice already has a temp of -5, we must factor in that the ices new temp will be T (new gained temp) -5.
As Jerry Smith already poited out correctly below, the last example is a bit unfortunate. The cube of ice heats up from -5C to 0°C. Then it melts, it turns into water, which would have 0°C. This water then warms up to the final temperature T. Whilst this is happening , the limonade cools from 20°C to the unknown temperature T. The specific heat capacity of ice is 2090 J/kg.K, the specific heat capacity of water is 4180 J/kg.K, they are very much different, so there is definitely missing a third member on the right side of the equation. Also, notice that specific latent heat of melting of ice is 334 kJ/kg, so the energy needed to melt the ice cube in this example is very roughly 10x greater than to warm it up, first by 5°C in the form of ice, then by T°C as water. Indeed, small ice cubes are cooling drinks by melting, because melting needs a lot of energy.
at the end of the video would you not also have to consider the thermal energy of the water, in addition with the thermal energy when melting the ice, and the thermal energy of the ice??
@ really? But in order for thermal equilibrium to be reached does the energy of the liquid not have to equal to the energy of the ice, energy used to melt the ice then the energy of the ice in a liquid state?
@@robellyonathan440 For the orange juice it is cooling down so the change in temp is 20-T however for the ice it is warming up so the change in temp is T-(-5)
@@Holly-ew7ps If I've understood correctly, then it is final temp minus initial temp. T is the final temp -5 is the initial temp So final temp - initial temp = T-(-5) Sub in some values for T and you'll see that it works.
So the reason why u made the equations for the energy of the juice and ice equal is because the loss of energy/temp of the juice will be the gain of energy/temp of the ice? And why did you add on ml
He adds on ml because he assumed that the ice melts, therefore changing state and meaning some energy will be used to break the interactions between the liquid molecules, which is a reasonable assumption to make. 12:54
dude if i get a B or an A for physics im naming my child after you and im donating one of my kidneys in your name.
So...'Shorts' as their middle name?
What did you get?
Looks like he accidentally donated both kidneys.
@@hishamawan16 This is the best comment anyone's ever left on one of my videos.
Science Shorts
Thanks sir. I’m from Pakistan and I find your videos very helpful.
Can you please do a video on electronics and communication systems.
I ain't gonna lie it's less than 24 hours until the exam and I'm only learning this now
BigTobz_ygm literally same here
How did you lot do?
What'd you get?
Great!
My exam is an hour from now and it's now I'm learning it😂😅😢
Time to learn the entire A2 course in 2 days because someone spent most of year 13 doodling in her book rather than paying attention in class.
Great work on these videos btw, I think if I put in even half the effort you do I could probably get an A :D
why is it soo easy to be distracted at level?? lol
@@hlomoyo6655 freedom
@xxtenchingchong7055 9 months later im in the exact same position
@@osqmeister no comment😥
@@osqmeister 5 months later in the exact same position
wow, this visual way of teaching is amazing. It's clear and helps me actually remember stuff, thanks ^w^
Something that you didn't necessarily cover is the question type where you are given like the flow rate of a machine in Kg/s. So you must use the fact that P= Q/t to calculate the Power of the machine when only given change in temp and flow rate. :)
These videos are perfect for small revision
Super explanation 👍🏾. You really know how to break things down for even a toddler to understand 👌
Nice one, keep it up
Thank you so very much!! Helped me immensely, especially the harder problem in the end...
For SLH could I say: "The energy required to melt/vapourise 1kg of subtance *without changing temperature*
for anyone reading this in the future, make sure to put without changing the temperature to make sure you get the mark
@@jakebrown5967 Person from the future is here to thank you for the heads up
thank you!!
Amazing work, thanks for taking the time to help everyone out
lmao anyone notice how he paused before adding the extra zero to 420
Lol...?
nah but this video is bare helpful thank you
Np. You obviously think I'm far edgier than I am :P
what a legend ;)
@@ScienceShorts trust me bro your videos are damn helpful
28 hours to cram the entire of A2 physics, lol.
11:26 ice and water have different specific heat capacities
for A level they use the same to make it less complicated
I have trouble understanding what you did from 10:30 . Doesn't water have different specific heat capacities at different states? If it does, then why can we use E = mcT to calculate the energy in raising the temperature at two different states?
In reality, yes, but not at A-level.
Oh I see, thank you
Good question though
You're the best!!! Thx A LOT for the video!!!
These lectures are quiet old, can i still watch these?
literally saved my life
At 11:09 you say that we can combine the change in temperature for both ice and water but I don't think we can as the specific heat capacity for ice and water are different. Won't it give a different answer?
You are correct. In reality they are quite different!
Thanks!@@ScienceShorts
At 12:32 , why is it (20-T) isn’t the change in a factor (final - initial) so whatever the final temp is at comes first. You did final minus initial for ice where u said (T-5) but not for the first part. Could u explain why ?
It’s because the energy needs to be +ve. If you did (T-20) you’d get a -ve answer as T is smaller than 20. InshaAllah that helped.
@@abdullaahimohamed2695 it helped but a little too late 😂 I’m a Engineer at UCL now
@@bionic3604 that’s really cool btw
@Science Shorts Thanks will 100% donate :)
In the last example, why the equation is m×c×(20-T) instead of m×c×(T-20)
The change in temperature must always be positive as it is a magnitude, we know T must be less than 20 but higher than -5. So T-20 will be negative and will not be used whereas 20-T is positive and used.
Thank you
or you could do |T-20| :P
The T is the temperature that is transferred due to equilibrium into the other substance - Ice. T is therefore lost by the orange juice and gained by the ice, but as the ice already has a temp of -5, we must factor in that the ices new temp will be T (new gained temp) -5.
As Jerry Smith already poited out correctly below, the last example is a bit unfortunate.
The cube of ice heats up from -5C to 0°C. Then it melts, it turns into water, which would have 0°C. This water then warms up to the final temperature T. Whilst this is happening , the limonade cools from 20°C to the unknown temperature T. The specific heat capacity of ice is 2090 J/kg.K, the specific heat capacity of water is 4180 J/kg.K, they are very much different, so there is definitely missing a third member on the right side of the equation.
Also, notice that specific latent heat of melting of ice is 334 kJ/kg, so the energy needed to melt the ice cube in this example is very roughly 10x greater than to warm it up, first by 5°C in the form of ice, then by T°C as water. Indeed, small ice cubes are cooling drinks by melting, because melting needs a lot of energy.
Yes, my example was very general, going with the assumption that the SHC for ice and water are the same.
Hmmm surely on the flat part of the graph, the energy is breaking the intermolecular forces, not the bonds?
amazing !!!
finally got exactly what I was looking for 😇
saving my arse rn
this was really helpful please can you go further to the calculations
Shouldn't it be T - (-5) at 13:35.
it is, just the brackets aren't there. Look closely
What if you can't tell if the orange juice will freeze or the ice block will melt?
Very nice video
thank you for the explanation, the last equation in heating curves is that equation fixed?
Thanks man !
at the end of the video would you not also have to consider the thermal energy of the water, in addition with the thermal energy when melting the ice, and the thermal energy of the ice??
No
@ really? But in order for thermal equilibrium to be reached does the energy of the liquid not have to equal to the energy of the ice, energy used to melt the ice then the energy of the ice in a liquid state?
Thhxx ommgggg ommggg ommgg it's saved me OMMMGGGGGGGGGGGTGGGGGGGG 😭😭😭😭😭
why is the energy of ice not (-5 - T )
You put (t- - 5 )
the temperature would have to be positive as the ice is melting and therefore cant get colder
@@chloelouise7123 if thats the case then why is it 20-T for the orange juice??
@@robellyonathan440 For the orange juice it is cooling down so the change in temp is 20-T however for the ice it is warming up so the change in temp is T-(-5)
@@CCCZMC nah I still dont get it. Why isn't it just (final temp - initial temp)
@@Holly-ew7ps If I've understood correctly, then it is final temp minus initial temp.
T is the final temp
-5 is the initial temp
So final temp - initial temp = T-(-5)
Sub in some values for T and you'll see that it works.
LIFEEEEEE SAVERRRRRRRRRRR ♥
thanks g
Is this for Cambridge A2 level or for edexcle student
were we meant to do the last example? we were not given masses
So the reason why u made the equations for the energy of the juice and ice equal is because the loss of energy/temp of the juice will be the gain of energy/temp of the ice? And why did you add on ml
He adds on ml because he assumed that the ice melts, therefore changing state and meaning some energy will be used to break the interactions between the liquid molecules, which is a reasonable assumption to make. 12:54
God bless you
P3 feat. P2 (aqa)
is this according to the syllabus of CIE ?
Cie crap Why there aren't more source for cie maths and physics 😠
what iam i doing to my summer?
The thing you do when alone, if you have one...
Worth
hepls sooooooooooooooooooooooo much
thank u daddy)\