@@khanjan-iv5uc frst use the equation "v=332+0.6T "to find speed and then use the equation "f=speed/wavelength" to find velocity, please try it & you will get your answer.
The speed of sound at 30 deg is 349 so the distance travelled is 17.45m and at 10 deg it becomes 16.85m which means that the speed of sound and temperature are directly proportional to each other
Sir distance increase by increase of temperature means we increase 30cintigrate so distance increase is equal to 17.45meter and we decrease a temperature so distance decrease means we decrease temperature 10cintegrat so distance is equal to 16.85meter
In reverberation and echo you say when it reflected before 0.10s is called reverberation.it is wrong.correctly it means that when it reach to ear before 0.10s is called reverberation.correct definition it is . and also it is the correct concept of statement which you write on board about reverberation.am I right.
Ap ki bat bilkul tk he, nd yahi mere kehne ka mtlb b he, hum reflection ko tb he feel krte he jab sound ear tak ponch jate he, koe dough person reflected sound ko to feel nhi kr skta na.
wo me ne questions kiye he k ap log check kre k agr hum temperature ko change krte he to kia distance me koe change ata he k nhi, to me ne as a example temperature 10° and 30°degree ka lia he
As To find the speed of sound by changing in temp we have the formula 331+0.6(Tċ) so the speed at 30 degree is 349 so the distance is 17.45 And the speed of sound at 10 degree is 337 so distance on 10degree is 16.85
jo speed yaha pr hm lete he wo standard value he, pir baqi values hm compare krte he s value k sat. ye values temperature dependent hote he jo temperature k sata km or zaida hote he.
@@taimurali3227 ise formula se he hm frequency, wavelength nd speed find out kr skte he. as we know that sound is a type of mechanical wave so hr wave ki frequency, wavelength and speed hota he, to s formula se hm kisi b wave ki frequency, wavelength and speed find out kr sakte he.
Sir at 30 degree temp d/s of echo is 17.45 and at 10 degree temp d/s of echo is 16.85 so its mean that increase in temperature the distance of echo will be increased
MashaAllah sir
Excellent 👌
Answer of Assignment,
1, S= 17.45 when Temperature= 30°
2, S= 16.85 when Temperature= 10°
@@Ahsan.Zaryab well done 👏
Mashallah sir i understand ❤
@@Shayankhan12127 your welcome
what is the frequency of sound with wavelenght 0.24 m in air with tempratur of 32°C ?🤔
@@khanjan-iv5uc frst use the equation
"v=332+0.6T "to find speed and then use the equation "f=speed/wavelength" to find velocity, please try it & you will get your answer.
The speed of sound at 30 deg is 349 so the distance travelled is 17.45m and at 10 deg it becomes 16.85m which means that the speed of sound and temperature are directly proportional to each other
yes great 👍 u Done very well
Great sir ♥️♥️
thanks
@@ephysics3801 welcome
Sir ya kasy check karna ha kon sa formula use karna ha kea hamarea pass temperature zeda ho tou speed kasy zeada or kam ho gi sir please batayea
watch the video from 8:15 to end, you will get your answer inshaAllah
Sir distance increase by increase of temperature means we increase 30cintigrate so distance increase is equal to 17.45meter and we decrease a temperature so distance decrease means we decrease temperature 10cintegrat so distance is equal to 16.85meter
yes, great 👍 👏
Sir ap nay 11.5 acoustics pay vidio nai banayi
@@HamzaAhmad-k2d no
@@ephysics3801 why sir ? Plz make a video on acoustics topic too
@@MTMConnect inshaAllah
In reverberation and echo you say when it reflected before 0.10s is called reverberation.it is wrong.correctly it means that when it reach to ear before 0.10s is called reverberation.correct definition it is . and also it is the correct concept of statement which you write on board about reverberation.am I right.
Ap ki bat bilkul tk he, nd yahi mere kehne ka mtlb b he, hum reflection ko tb he feel krte he jab sound ear tak ponch jate he, koe dough person reflected sound ko to feel nhi kr skta na.
@@ephysics3801 there is any reason behind that you skip acoustic topic
@@UmraisKhan-t2k no reason, randomly skip ho gia he.
Speed of sound At 30 degree is 349
And at 10 degree is 337 so the distance traveled are 17.45 and 16.85 respectively
Am I right sir?
yes 100% right
@@ephysics3801 Thank you sir
Sir plzz acoustic lecture upload kry
Good
Sir last me smajh ni aye 20 degree 10 degre kya krna hau plz short video bna den oa pe
wo me ne questions kiye he k ap log check kre k agr hum temperature ko change krte he to kia distance me koe change ata he k nhi, to me ne as a example temperature 10° and 30°degree ka lia he
@@ephysics3801 okok thnk u sirr
Sir g Slaam.... Dr saib ymaa yo request drtaa komaa da class 9 physics shoro kaye pa channel
W.salam, inshaAllah agha ba om koma kho filhal da complete kom
As To find the speed of sound by changing in temp we have the formula 331+0.6(Tċ) so the speed at 30 degree is 349 so the distance is 17.45
And the speed of sound at 10 degree is 337 so distance on 10degree is 16.85
Good
Sir hm speed koi b value ly skty han
jo speed yaha pr hm lete he wo standard value he, pir baqi values hm compare krte he s value k sat. ye values temperature dependent hote he jo temperature k sata km or zaida hote he.
@@ephysics3801 Thanks 👍
@@ephysics3801 sir ya Jo equ ha
V=f lamda is ka speed of sound sy kia relation ha
@@taimurali3227 ise formula se he hm frequency, wavelength nd speed find out kr skte he. as we know that sound is a type of mechanical wave so hr wave ki frequency, wavelength and speed hota he, to s formula se hm kisi b wave ki frequency, wavelength and speed find out kr sakte he.
Thanks
c++ language wrsraa hum shoro kaye plzzzz sir
InshaAllah zaror
Good sir❤❤❤
thanks
Sir at 30 degree temp d/s of echo is 17.45 and at 10 degree temp d/s of echo is 16.85 so its mean that increase in temperature the distance of echo will be increased
Yes 👍
Sorry 😔 sir speed nahi distence
Washroom singer😮
Washroom singer 😅❤
gando ki olad sir hy tara jaso ka bap hy bap ko singer ny bolty mader chod