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1:11:55 t-log (1-t) should be multiplied by integrating factor when writing a solution
Yes
Thanku Sir, 💐💐💐 aapke video ke karan mera 🌱🌱 Gate ho gya
25:05Sir linearly dependent solution mein n y1 and y2 are scalar multiple of each otherToo yha kaise...?
awesome sir jiiii
Nice 😮
Thank you sir ❤❤❤
28:35 z=1/(t+1) hoga
43:14 e tA=y comes,but options d is etA=y1 ,is it correct?
Thanks sir for sharing such nice logics 🙏🙏🙏
Thank you sir
Sir can you give solution on non parametric method from statistics ???
22:10 waha par -y1+y2 hoga na
At 28:23 on using IC for Z we should get C=1 !? Isn't it.
yesss I too got confused ...
22:10 par -y1+y2 hoga na And 36:50 pe jo question he use aapne apne ek purane video mai uniqueness and existence wale mai option 4 sahi bataya he aur yha par option 2 toh sahi kaun sa hoga sir
option explained in this video is correct
@@DrHarishGarg thankyou sir
Tnku so much sir..
Sir please make vdo on boundary value problems 😊
Ese hi net ke saare topic krwa dijiye
@59;37 it is unstable node sir...because it is real and equal which is negative sign
Its asymptotically stable bcz roots are real & equal with -ve sign otherwise u stable..
50:00 option 3 kaise wrong hai... Wo nahi samjh aaya.....
Ek question me te^2t me yee let kiya ki t multiple hone per repeated root hai 9:11 vale me yee consider kyu nhi Kiya
Plz reply
te^t is part of particular integral, solved using conventional ways only. Nothing is assumed or let. Please check again.
🎉🎉🎉🎉
Sir plz sare topic krwa dijiye
Eigen values are -1,-1
Isn't Blows up means that the function vanishes??!!
No
1:11:55 t-log (1-t) should be multiplied by integrating factor when writing a solution
Yes
Thanku Sir, 💐💐💐 aapke video ke karan mera 🌱🌱 Gate ho gya
25:05
Sir linearly dependent solution mein n y1 and y2 are scalar multiple of each other
Too yha kaise...?
awesome sir jiiii
Nice 😮
Thank you sir ❤❤❤
28:35 z=1/(t+1) hoga
43:14 e tA=y comes,but options d is etA=y1 ,is it correct?
Thanks sir for sharing such nice logics 🙏🙏🙏
Thank you sir
Sir can you give solution on non parametric method from statistics ???
22:10 waha par -y1+y2 hoga na
At 28:23 on using IC for Z we should get C=1 !? Isn't it.
yesss I too got confused ...
22:10 par -y1+y2 hoga na
And 36:50 pe jo question he use aapne apne ek purane video mai uniqueness and existence wale mai option 4 sahi bataya he aur yha par option 2 toh sahi kaun sa hoga sir
option explained in this video is correct
@@DrHarishGarg thankyou sir
Tnku so much sir..
Sir please make vdo on boundary value problems 😊
Ese hi net ke saare topic krwa dijiye
@59;37 it is unstable node sir...because it is real and equal which is negative sign
Its asymptotically stable bcz roots are real & equal with -ve sign otherwise u stable..
50:00 option 3 kaise wrong hai... Wo nahi samjh aaya.....
Ek question me te^2t me yee let kiya ki t multiple hone per repeated root hai 9:11 vale me yee consider kyu nhi Kiya
Plz reply
te^t is part of particular integral, solved using conventional ways only. Nothing is assumed or let. Please check again.
🎉🎉🎉🎉
Sir plz sare topic krwa dijiye
Eigen values are -1,-1
Isn't Blows up means that the function vanishes??!!
No
22:10 waha par -y1+y2 hoga na