you did forget to mention that the mode is typically lower than the median. So, at the maximum point, the positively skewed graph should have been a mode instead of a median.
You are correct if the distribution was continuous. The example I used is discrete and I approximated the distribution with a curve for the purpose of explanation which was originally intended for my junior high school classes. This video is meant purely as a basic introduction & description without going into in-depth/specific details such as maximum stationary points on continuous distributions = mode. Thank you for your comment & feedback.
Thank you! This video helped me so much and you made it super easy to understand.
You're very welcome! 😀 Thankyou for your kind feedback!
How did u have the 16.14
16.14 is the mean of the data set (correct to 2 decimal places)
you did forget to mention that the mode is typically lower than the median. So, at the maximum point, the positively skewed graph should have been a mode instead of a median.
You are correct if the distribution was continuous. The example I used is discrete and I approximated the distribution with a curve for the purpose of explanation which was originally intended for my junior high school classes. This video is meant purely as a basic introduction & description without going into in-depth/specific details such as maximum stationary points on continuous distributions = mode. Thank you for your comment & feedback.
great
Thank you