Spanish |A Nice Algebra Problem | Math Olympiad👇

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  • āđ€āļœāļĒāđāļžāļĢāđˆāđ€āļĄāļ·āđˆāļ­ 29 āļ•.āļ„. 2024

āļ„āļ§āļēāļĄāļ„āļīāļ”āđ€āļŦāđ‡āļ™ • 9

  • @arvindkulkarni6580
    @arvindkulkarni6580 āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    Very well explained here

  • @LaxmanKumar-yi4cv
    @LaxmanKumar-yi4cv 2 āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    Bahut achha explanation

  • @NithyaGhumare
    @NithyaGhumare 16 āļŠāļąāđˆāļ§āđ‚āļĄāļ‡āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    Goos teaching method

  • @KeshavKulkarni-x1w
    @KeshavKulkarni-x1w 2 āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    Wow ðŸ˜ē

  • @Fred-yq3fs
    @Fred-yq3fs āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    One can also express this very easily with the half tangent t:
    P = (2t+2t^2)/(2t-2t^2)
    = (1+t)/(1-t)
    Given
    Tan(x)=2t/(1-t^2) and
    Sec(x)=(1+t^2)/(1-t^2)
    P=(1+t)^2/(1-t^2)=Tan(x)+Sec(x)

  • @raghvendrasingh1289
    @raghvendrasingh1289 2 āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    Nice
    Numerator mein agar a = sin x+1 aur b = cos x lekar a^2-b^2 use kiya jata to jaldi ho jata jaise ki denominator

  • @aruntiwari5714
    @aruntiwari5714 2 āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    Too good 👍

  • @Maheshkumar-cw6un
    @Maheshkumar-cw6un 2 āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    very nice

  • @satyadev3848
    @satyadev3848 2 āļ§āļąāļ™āļ—āļĩāđˆāļœāđˆāļēāļ™āļĄāļē +1

    âĪâĪ