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Very well explained here
Bahut achha explanation
Goos teaching method
Wow ðē
One can also express this very easily with the half tangent t:P = (2t+2t^2)/(2t-2t^2) = (1+t)/(1-t)Given Tan(x)=2t/(1-t^2) and Sec(x)=(1+t^2)/(1-t^2)P=(1+t)^2/(1-t^2)=Tan(x)+Sec(x)
NiceNumerator mein agar a = sin x+1 aur b = cos x lekar a^2-b^2 use kiya jata to jaldi ho jata jaise ki denominator
Too good ð
very nice
âĪâĪ
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Very well explained here
Bahut achha explanation
Goos teaching method
Wow ðē
One can also express this very easily with the half tangent t:
P = (2t+2t^2)/(2t-2t^2)
= (1+t)/(1-t)
Given
Tan(x)=2t/(1-t^2) and
Sec(x)=(1+t^2)/(1-t^2)
P=(1+t)^2/(1-t^2)=Tan(x)+Sec(x)
Nice
Numerator mein agar a = sin x+1 aur b = cos x lekar a^2-b^2 use kiya jata to jaldi ho jata jaise ki denominator
Too good ð
very nice
âĪâĪ