After going all over youtube to find help on this stuff I find my self at the person who taught me calculus, my man, PatrickJMT, I really love this guy!! Hes awesome haha. He knows everything! Please make more and more physics videos, i think we are good on calculus haha
Work = (force)(Distance)....Using Hooke's Law we know Force is proportional to kx. So, essential, we have deltaW = kx(deltax). Since this example gave us a value for Work to start with, we were able to solve for k by integration. In the last example, we used F=kx because we had information on F and x provided. I know you asked this question a year ago..lol
I just watched all of your videos for calculating work. Thank you thank you thank you!!! Just learned this today in class and didn't understand ANYTHING:( but you make it really clear:) The different colors really help too THANK YOU!!
why can't you use F=kx to find k in this example? like why can't you just do 2/.12 to find k? EDIT: i see, it's because work is given to us this time, not force kk thx m80
kalef1234 thank you! I just commented with the same question and it was driving me up the wall. Glad to know I wasn't the only one who made that mistake
@patrickJMT, it might be helpful to leave a comment explaining the difference between calculating k between this video and the last so it will show up in Uploader Comments. There seems to be some confusion, and I know it took me a moment to figure it out.
hey for these types of questions you cant use the regular equations (like W=Fnet*d)? can u use something with PE=1/2*kx^2 cuz its dealing with springs and stretching?
I'm not a math teacher or anything, but the reason you can't do that is because in order to do what you are implying we must be given a force- that of which is not given unlike the first video- in this case we are given the "work" so we must work backwords to get k. Hope that helps.
in the first video he was given the force(10lb) so the equation would be F=kx, but in this video he was given the work done(2J) so the equation would be W=integral(kx)dx both different ways of finding the k depending on what you are given
Thanks for the videos Patrick. Just wanted to clarify, why do you just set f(x) = kx in example 1 but here you used an integral in order to solve for k? Is it because ex 1 gives you the force required to hold the spring x units past its natural length while ex 2 gives you the work required to hold the spring x units past its natural length?
@GfunkERA3131 hahaha same here I was like "I am going to see if patrickJMT can lead me into the right direction" and lo and behold he does the exact question I was stuck on. Thanks, patrickJMT!
what if you have the value of the work used to stretched the spring and the distance that is exerted by the work ( for example 0.05 J of work to stretch to the distance of 1 cm ) and they are asking you to find the spring's constant and natural length ?
woah woah woah, that is some pretty good arithmetic skills! haha i can never turn a decimal like that into a fraction off the top of my head =P yet another helpful video though thanks
i spent 20 min trying to figure it out and did this first but i couldnt prove it right, so i went on here to see if i could get help and bam! same thing i did (:
my pleasure :)
im glad people like you exist who are willing to take the time out of their days to help make educated youth
Thank you SOOO much for doing this! My teacher didn't explain this well, so you are a life saver.
After going all over youtube to find help on this stuff I find my self at the person who taught me calculus, my man, PatrickJMT, I really love this guy!! Hes awesome haha. He knows everything! Please make more and more physics videos, i think we are good on calculus haha
Real Talk! When I got confused on my subjects. I always go on your videos. Thanks a lot. Godbless and more power Mr. PatrickJMT! :)
Work = (force)(Distance)....Using Hooke's Law we know Force is proportional to kx. So, essential, we have deltaW = kx(deltax). Since this example gave us a value for Work to start with, we were able to solve for k by integration. In the last example, we used F=kx because we had information on F and x provided. I know you asked this question a year ago..lol
My professor didn't cover how to find the spring constant from a given value for work... Thanks for enlightening me. :D
Thank you so much. I couldn't figure this damn problem out until I saw your video.
Wow, you rule! I hadnt noticed you had videos involving physics!
Impressive!
I just watched all of your videos for calculating work. Thank you thank you thank you!!!
Just learned this today in class and didn't understand ANYTHING:( but you make it really clear:) The different colors really help too THANK YOU!!
why can't you use F=kx to find k in this example? like why can't you just do 2/.12 to find k? EDIT: i see, it's because work is given to us this time, not force kk thx m80
kalef1234 thank you! I just commented with the same question and it was driving me up the wall. Glad to know I wasn't the only one who made that mistake
these questions are from my textbook. hookes law 1 was the question i was working on and this is the question im working on now. epic.
HAhahah me too! man those first few problems were a pain. I hate this lesson.
Single Variable Calculus Early Transcendentals 7th edition? Lol this problem is also in my book...its was a very annoying problem
Deuterium52 wasn't that annoying
I love your videos, you make calculus easy!
@patrickJMT, it might be helpful to leave a comment explaining the difference between calculating k between this video and the last so it will show up in Uploader Comments. There seems to be some confusion, and I know it took me a moment to figure it out.
thank you! your video was really helpful. well done.
Thanks. Greeting from Canada.
hey for these types of questions you cant use the regular equations (like W=Fnet*d)? can u use something with PE=1/2*kx^2 cuz its dealing with springs and stretching?
I'm not a math teacher or anything, but the reason you can't do that is because in order to do what you are implying we must be given a force- that of which is not given unlike the first video- in this case we are given the "work" so we must work backwords to get k. Hope that helps.
Its alway easier when you pull that constant out of the integration first.
in the first video he was given the force(10lb) so the equation would be F=kx, but in this video he was given the work done(2J) so the equation would be W=integral(kx)dx both different ways of finding the k depending on what you are given
Isn't K = N/m? I think at 3:35 you said Nm. I might be wrong though.
Because we are given work not force from the beginning of the problem.
So if you use 2=.12k to solve for k, it will give you the wrong answer.
Words can't find a way to say thank you.
Thanks for the videos Patrick. Just wanted to clarify, why do you just set f(x) = kx in example 1 but here you used an integral in order to solve for k? Is it because ex 1 gives you the force required to hold the spring x units past its natural length while ex 2 gives you the work required to hold the spring x units past its natural length?
+SirTrollingham because we were given the WORK of 2J, not some force. I just figured this out.
@GfunkERA3131 hahaha same here I was like "I am going to see if patrickJMT can lead me into the right direction" and lo and behold he does the exact question I was stuck on. Thanks, patrickJMT!
what if you have the value of the work used to stretched the spring and the distance that is exerted by the work ( for example 0.05 J of work to stretch to the distance of 1 cm ) and they are asking you to find the spring's constant and natural length ?
woah woah woah, that is some pretty good arithmetic skills!
haha i can never turn a decimal like that into a fraction off the top of my head =P
yet another helpful video though thanks
Why is it necessary to use the integral to solve for k in this example, but not in the first example on Hookes Law?
Hey Nat. It is because we were given force before and now we are given work. Best of luck on your exam.
i dont get it ?:(
i spent 20 min trying to figure it out and did this first but i couldnt prove it right, so i went on here to see if i could get help and bam! same thing i did (:
Thank you so much!
Thank you!
where is the 3rd hooke's law video?
thank you
Exact same problem from the Cal book
@honeypot11 He probably used a calculator's decimal to fraction converter :p
I decided to not convert the value of k from a decimal into a fraction (why add more steps?) ... but then once I integrate I get negative numbers. >.
why cant you go 2J = k(.12m)
k = 50/3
like u did in example 1
waiting for the next example
this video goes sort of fast... in the first half i wasn't very clear on how you determined the limits of integration... then I just got lost.
I'm pretty sure that he dropped the denominator after he began to plug things in.
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what level of math is this lol