Mr. Michel, I actually obtained indeed identical results the only difference is I used rotational form of Newton's second law and then I summed the all the torques acting on the rod, which is just the force of gravity on the center of mass, I solved for angular acceleration then I used uniformly angularly accelerated motion equation to solve for the final angular velocity which turned out to be having an angle in the equation which for in this case is Delta theta which is pi over 2 radians so my equation for angular velocity has pi over 2 in the square root for the equation instead of cosine of theta. Please assist me!
You can find all the playlists on Electrical engineeing easily from the home page of the channel. All of our courses are organized in chronological fashion. Let me know if you are having trouble finding them.
@@MichelvanBiezen hope I could not convey my question to u, there is a separate form of work energy theorem that needs to be applied in pure rotational motion, the que should actually be solved that way but as every book follows this wrong way, it has been the trend
Thanks for this video. It's really amazing! In a question, we had to find the acceleration of a rod hinged at topmost point making an angle theta with vertical and the answer was 3gsintheta/2. Please help me with the doubt
Note that in order to use the conservation of momentum, there is a collision, such that you keep the momentum of the system constant. (question: If you throw a snow ball against a wall and it stick to the wall, is momentum conserved?).
@@MichelvanBiezen Okay that makes sense. But why does the conservation of momentum in this example work even though there is no collision? A student sits on a freely rotating stool holding two dumbbells, each of mass 3.09 kg (see figure below). When his arms are extended horizontally, the dumbbells are 0.99 m from the axis of rotation and the student rotates with an angular speed of 0.749 rad/s. The moment of inertia of the student plus stool is 2.52 kg · m2 and is assumed to be constant. The student pulls the dumbbells inward horizontally to a position 0.298 m from the rotation axis. Find the new angular speed of the student.
@@Awawaeaawawawawawawa Conservation of momentum will apply *in general*, and if you know what you are doing, you can apply it to any situation. Whether it's useful or not, or is the optimal method, is another matter entirely. Conservation of momentum usually is the optimal method, if (A) there are no external forces, (B) external forces add up to zero, or (C) it happens so quickly that the impulse of external forces is negligible. This way, there are no external agents that would absorb some of the momentum that you might neglect to account for. In your example, it is conservation of angular momentum, and due to the lack of external torques, it will be the method you use to solve it.
Thanks professor you saved me on my exam from one of your videos I was learning while answering
Glad you found us. There are a hundred playlist on all topics in physics on this channel.
@@MichelvanBiezen Cool I'll look forward to more videos
I wish the hs in my town should teach like this video. Thank you
Where do you go to school?
Mr. Michel, I actually obtained indeed identical results the only difference is I used rotational form of Newton's second law and then I summed the all the torques acting on the rod, which is just the force of gravity on the center of mass, I solved for angular acceleration then I used uniformly angularly accelerated motion equation to solve for the final angular velocity which turned out to be having an angle in the equation which for in this case is Delta theta which is pi over 2 radians so my equation for angular velocity has pi over 2 in the square root for the equation instead of cosine of theta. Please assist me!
That is another good method to use.
@@MichelvanBiezen However, I'm having an issue! Please reread it again!
Very good professor . Such a great explanation
Please can you send me links( all of them ) for a full cours on electrical engineering
You can find all the playlists on Electrical engineeing easily from the home page of the channel. All of our courses are organized in chronological fashion. Let me know if you are having trouble finding them.
@@MichelvanBiezen thank you professor
@@MichelvanBiezen i found professor , all of them , thank you
Thanks alot for this ❤.
Good morning sir.
You are welcome. Good morning to you. 🙂
how do u relate a potential energy to rotational motion, can we solve it using work done by torque and equalling it with rotational kinetic energy.
Better to convert the potential energy to rotational kineiic energy.
@@MichelvanBiezen hope I could not convey my question to u, there is a separate form of work energy theorem that needs to be applied in pure rotational motion, the que should actually be solved that way but as every book follows this wrong way, it has been the trend
Thanks for this video. It's really amazing! In a question, we had to find the acceleration of a rod hinged at topmost point making an angle theta with vertical and the answer was 3gsintheta/2. Please help me with the doubt
That's the tangential acceleration but slowing down when theta goes to zero.
Would using the conservation of momentum work in this example? If not, why?
Note that in order to use the conservation of momentum, there is a collision, such that you keep the momentum of the system constant. (question: If you throw a snow ball against a wall and it stick to the wall, is momentum conserved?).
@@MichelvanBiezen Okay that makes sense. But why does the conservation of momentum in this example work even though there is no collision? A student sits on a freely rotating stool holding two dumbbells, each of mass 3.09 kg (see figure below). When his arms are extended horizontally, the dumbbells are 0.99 m from the axis of rotation and the student rotates with an angular speed of 0.749 rad/s. The moment of inertia of the student plus stool is 2.52 kg · m2 and is assumed to be constant. The student pulls the dumbbells inward horizontally to a position 0.298 m from the rotation axis. Find the new angular speed of the student.
@@Awawaeaawawawawawawa Conservation of momentum will apply *in general*, and if you know what you are doing, you can apply it to any situation. Whether it's useful or not, or is the optimal method, is another matter entirely.
Conservation of momentum usually is the optimal method, if (A) there are no external forces, (B) external forces add up to zero, or (C) it happens so quickly that the impulse of external forces is negligible. This way, there are no external agents that would absorb some of the momentum that you might neglect to account for.
In your example, it is conservation of angular momentum, and due to the lack of external torques, it will be the method you use to solve it.
Thank you Teacher
Good morning.
Thanku
You are welcome. 🙂
Thank you very much sir
You are welcome. 🙂
You're creative keep going✨✨✨✨✨..
Sender:your brother (Baraa) from Palestine
🇵🇸🇺🇲
First comment of the day!
👍easy
Glad you liked it.