CosA/1+SinA+1+SinA/CosA=2 SecA

[@rEEt_..]

Thank you so much mam for explanation ☺️❤️

[@sahilgupta-ry9qs]

superb explanation mam

[@gamingwithsaviour5982]

1:07 mam if we take cos^2a and (1+sina)^2 as (a+b)^2 = a^2+b^2+2ab i think we will get ' Cos^2a+1+sin^2a+2.cos a .1+sin a'
but u wrote 2.sin a only why mam ? It is my only doubt

[@GargTutorials]

We will use (a+b)*2 only in (1+SinA)*2 hope this will help you

[@vaibhav5002]

Great teacher

[@ankitasureshbablad500]

Thanks a lot mam.. it helped me a lot😊

[@peacelover8]

thankyou mam❤❤❤❤❤❤❤

[@Belha-f9n]

Ma'am apne bhot ache se samjhaya

[@mymissvanshika5002]

Hi ma'am thank you for this video

[@vishalmusicdoneparcha]

Thank you mam

[@SkAmaan-vo6xf]

Maam mujhe ek doubt hai.
a²+b²+2ab = (A+b)²
cos a ² + (1+sin a)² + 2 cosa Sin a aana chahiye na.

[@amanpradhan7762]

Mera bhi wohi doubt hi hai

[@ankitaaaa9387]

Kyunki waha cos2 aur sin2 pe nhi balki (1+sinA)² pe identity lag rhi hai

[@pradippatra1562]

Mam i have doubt

[@GargTutorials]

??

[@AbidAli-wj5il]

❤❤❤❤❤❤

[@RakeshKumar-c8i2t]

Ok

[@sudarshansudha5657]

Thank s mam

[@AnkitRaj-cm7xw]

❤❤❤