sir,the example no 3. is not an LTI system since the coefficient is time dependent( voilating time invariant property) so we cannot proceed ahead. am i right???????? plz revert
We'll have to check for the coefficient only for the case of input and output relationship... h(t) is defined only for LTI systems.. if incase you have a valid h(t) relationship, that implies the system is LTI system! Hope you can understand?
sir, if u solve laplace of h(t) in ques 3. u will find y(t)=exp[-(t+1)].x(t) that is not A LTI system then how can u defind it is causal LTI SYSTEM infact it is firstly not a TIME INVARIENT system. pls give any solution.
No , we are not having any input output relationship here , to get that follow the method no. 2 as discussed in problem no. 2 in the above lecture . Take laplace transform and then inverse laplace transform and the check the condition ....
A causal system has input x(n) and output y(n) .find the umpulse response h(n) for x(n)=δ(n)+1/6.δ(n-1)-1/6.δ(n-2), y(n)=δ(n)-2/3.δ(n-1) Please help anyone 😢😢😢
take laplace transformation of x[n] and y[n] then divide Y[s] with X[s] you'll get transfer function then convert this transfer function to impulse function
both are non casual as because u(t+2) starts from negative axis of t and also the second problem is the value of e^-2t is not zero for t
both are non causals for homework problems
thanks sir
both___ non causal
Both the systems are non-causal because the condition h(t) = 0 is not satisfied when t
Non causal system
Non causal system
At 3:00, isn`t the Laplace transform of 3*Delta(t+2) = 0 ?
Thanks you sir❤
tnx for the lecture.
sir,the example no 3. is not an LTI system since the coefficient is time dependent( voilating time invariant property) so we cannot proceed ahead. am i right???????? plz revert
We'll have to check for the coefficient only for the case of input and output relationship... h(t) is defined only for LTI systems.. if incase you have a valid h(t) relationship, that implies the system is LTI system! Hope you can understand?
@@ajaykumar-mo9bq dear ...if are not getting it to be time invariant than how can we sait it is LTl
@@eddyr978 Check the condition only for Input and Output relationship , not on Impulse Response of the system .
@@ajaykumar-mo9bq Thanks...
sir, if u solve laplace of h(t) in ques 3. u will find y(t)=exp[-(t+1)].x(t) that is not A LTI system then how can u defind it is causal LTI SYSTEM infact it is firstly not a TIME INVARIENT system. pls give any solution.
Same doubt
Both are non- causal systems.
both non causal
these two are non causal
both are non-causal
Bro.are you able to qualify exam for which you are preparing
Reply..i notice you respond almost on every vedio
homework problem both are NON CASUAL LTI SYSTEM .
WE CAN SOLVE 1ST BY GRAPH AND 2ND BY TAKING LAPALAS TRANSFORM
Problem no 4 is time variant....is anyone agree?
No , we are not having any input output relationship here , to get that follow the method no. 2 as discussed in problem no. 2 in the above lecture . Take laplace transform and then inverse laplace transform and the check the condition ....
Answer for the first & second homework question is : Non -causal.
yaaaaa u r absolutely right
Both are non-casual
Non causal both
Both non causal
both are non causal.
non casual
non casual
both are non causal LTI sys
both are non causal
A causal system has input x(n) and output y(n) .find the umpulse response h(n) for x(n)=δ(n)+1/6.δ(n-1)-1/6.δ(n-2), y(n)=δ(n)-2/3.δ(n-1)
Please help anyone 😢😢😢
take laplace transformation of x[n] and y[n] then divide Y[s] with X[s] you'll get transfer function then convert this transfer function to impulse function
both are non casual
Both cases non causal
non causal
NC
NC
both non causal
both are non causal
non causal