Lecture 07: Basic Laws (Contd.)

[@ASHOKKUMAR-cx4ey]

Kya mast muskuraate hain sir......... You know.... What you call..

[@debabratakundu9602]

Very informative & well explained lecture.Thanks a lot,Sir.

[@screenrecorder1070]

For Q2.10 if we apply KVL to the loop 2 then the answer will be i=5A & v=50V. Why it differs? Or is there any reason that we apply KVL in loop 2?

[@maragathamsukumaran634]

Helpful Sir! Thank You!

[@maragathamsukumaran634]

I have just started this playlist and hope to finish this within a month...not as a certificate course but for my understanding!

[@malvado8267]

Hello! Is example 2.8's solution is correct?

[@mrabbot-iit1908]

@@malvado8267 no i should be -2A and V should be 6v

[@sushmitamandal1677]

​@@mrabbot-iit1908can you tell me how sir is wrong?

[@dr.ritulathakur9145]

@@malvado8267 it is correct

[@AkashKumar-t4b5x]

@@sushmitamandal1677 v=ir when current flow from high to low potential and v=-ir when current flow from low to high potential. Here potential is low to high then also take take the positive sign. At 31:30 it will be 10 i2 not -10i2. sorry for replying 1 year after.☠

[@abdullaali87]

Thanks a lot sir