Organic Chemistry 2: Chapter 20 - Carboxylic Acids and Their Derivatives (Part 1/2)

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  • เผยแพร่เมื่อ 7 ม.ค. 2025

ความคิดเห็น • 10

  • @ninjagothebestshowonearth7277
    @ninjagothebestshowonearth7277 ปีที่แล้ว +4

    Subhanallsh your do great at teaching
    🤩
    You make organic chem seem as if it’s easy 😂

    • @professoreman2289
      @professoreman2289  ปีที่แล้ว +1

      Thank you so much!! Alhamidullah I am glad I could help :)

  • @JW-ps8vp
    @JW-ps8vp ปีที่แล้ว +5

    Damn this channel is underrated

    • @professoreman2289
      @professoreman2289  ปีที่แล้ว +1

      Thank you omg! Please share with your friends

  • @oluwasefunmioluwafemi1628
    @oluwasefunmioluwafemi1628 2 ปีที่แล้ว

    LAH and H2O would not form a great yield of the primary alcohol because it would instead form the carboxylate of benzoic acid due to the strength of LAH asa reducing agent in combination with H2O, H3O+ should be used instead. @11:11

    • @professoreman2289
      @professoreman2289  2 ปีที่แล้ว

      You can use LiAlH4 in an individual step followed with water as the last step and that actually should be okay. Essentially, Oxidation of the starting material to benzoic acid an be accomplished with sodium chromate. And then reduction of the resulting carboxylic acid can be done with lithium aluminum hydride FOLLOWED by protonation with water will produce the desired product. You can do this another way too! A bromine can be installed in the benzylic position using NBS/heat. Subsequent reaction with sodium hydroxide will then also give you the final product you desire. I hope this helped friend :)

  • @ashanti9120
    @ashanti9120 ปีที่แล้ว +1

    by still using Na2Cr2O7, H2SO4 and water, can i use NaBH4 to oxidize the carboxylic acid and turn it into an alcohol ?

  • @yararoummani4722
    @yararoummani4722 2 ปีที่แล้ว

    Couldn’t you use Grignard and h3o+?

    • @professoreman2289
      @professoreman2289  2 ปีที่แล้ว

      Hi Yara! Which specific problem are you referring to? In general, there is more than one way to solve some of these problems for sure! you could use different reagents to solve most synthesis problems, but lmk which one you are referring to :)