NYT Hard Sudoku Walkthrough | February 19, 2024
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- เผยแพร่เมื่อ 5 ต.ค. 2024
- Solving today's The New York Times Hard Sudoku for February 19, 2024
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Thanks dude! Regards from Brazil!
really good solve and explanation as always, thanks!
11 mins for me today, nice puzzle. Good work 👍
I did this one yesterday, used a bit of limited notation and wasn't fast. I find the level of New York Times Hard puzzles to be something like 'tricky'. I would say that a lot of the work in them can be just writing in solution numbers, with one particular trick being helpful, that being to deal with more than one number - in this one an example would be how the 5 & 7 look into box 4 from C1 and R6, and you have a pair. You then get a 3 & 9 pair from C1 as well leaving a last pair in C1 of the block. (I'm not a Sudoku genius, and would be completely up the creek with one of the 'Tatooine' sudokus, one of which I saw solve with the 'set equivalence thing - amazing!)
In this puzzle i used the auto fill provided by nyt .. With just that and no corner marks got it done. I just wanted to try a different technique.. thanks as always!!
I don't think the 57 pair in box 4 was a key moment, in my solve I filled that complete box without noticing that pair until they were my last two cells. I agree about the 248 triple in column 6.
Good solve, not too tricky. For me, that 57 pair was key! I circled around for a while. Thanks!
Just over 20' for me, I'm happy with that time given this grid configuration.
kind comment
Completed in 8m07s
3:13 "I was kinda hoping for a naked single, but that's alright"
Got stuck on the 6 in box 5 bottom right. Don't understand the 248 triple logic there at all
Just to be clear, are you talking about the 248 naked triple I found at 8:40?
If so, those three cells can only be from 248 based on how they were pencilmarked. So, the rest of the column other than those cells cannot be 2, 4, or 8. There are a few ways you might think about this, but maybe this way will help:
Each cell in the column needs a unique value from 1-9. You can't repeat any. Also, no cell can end up empty. So, what would happen if you tried to spread just 2, 4 or just 2, 8 or just 4, 8 across those 3 cells? Well, one would end up empty, right? Not enough butter for the bread. You can fill two of them, but not all three. You need three different numbers to go into those cells, and the only three numbers that are available for those cells are 2, 4, and 8. No matter how we end up placing those into those cells, the 2, 4, and 8 will end up in them somewhere. As a result, the other cells in the column will have 2, 4, and 8 eliminated regardless of what order we place them in. Another way to think of it is, what would happen if we tried to put a 2 anywhere else in the column other than those 3 cells? Well, that would eliminate 2 from all three of those cells. Now those cells have only the values 4 and 8 to go between them, and again that's just not enough butter for our bread. You can fill two of them: one with a 4, and one with an 8, but what will the third be filled with? It's just not possible. Two digits can't go into three cells.
I hope that helps!
I’m still a beginner and I haven’t seen a triple like the 248 one yet. What’s the logic behind that one exactly?
I've just answered a similar question for another commenter, but I'll paste it here as well for you:
Those three cells can only be from 248 based on how they were pencilmarked. So, the rest of the column other than those cells cannot be 2, 4, or 8. There are a few ways you might think about this, but maybe this way will help:
Each cell in the column needs a unique value from 1-9. You can't repeat any. Also, no cell can end up empty. So, what would happen if you tried to spread just 2, 4 or just 2, 8 or just 4, 8 across those 3 cells? Well, one would end up empty, right? Not enough butter for the bread. You can fill two of them, but not all three. You need three different numbers to go into those cells, and the only three numbers that are available for those cells are 2, 4, and 8. No matter how we end up placing those into those cells, the 2, 4, and 8 will end up in them somewhere. As a result, the other cells in the column will have 2, 4, and 8 eliminated regardless of what order we place them in. Another way to think of it is, what would happen if we tried to put a 2 anywhere else in the column other than those 3 cells? Well, that would eliminate 2 from all three of those cells. Now those cells have only the values 4 and 8 to go between them, and again that's just not enough butter for our bread. You can fill two of them: one with a 4, and one with an 8, but what will the third be filled with? It's just not possible. Two digits can't go into three cells.
I hope that helps!
@@Rangsk Thank you so much for the detailed explanation! I really appreciate it!
What was the logic placing 3 in box 8?
th-cam.com/video/ZUb1fA60rE8/w-d-xo.htmlsi=TWqYtXbCJOhujX_u&t=568