for (I), wouldn't you have two compounds since both carbons are secondary carbons and so the bromine could either end up with carbon #3 or carbon #2 since they're equally stable?
In problem D there is the formation of two tertiary carbocations. However the stabilization is the product of hyperconjugation. The position "1" with the methyl group gets stabilized by 3 C-H-bonds whereas in position "2" with the ethy group it should only get stabilized by 2 C-H-bonds since its -CH2-CH3. So im thinking that the more stable product ist the one wehre the Cl sits on Position "1". Am I thinking about this wrongly? Help or correction would be appreciated, thanks :)
Helped me so much in learning this chapter thank youuu!
why are u lying to urself
for (I), wouldn't you have two compounds since both carbons are secondary carbons and so the bromine could either end up with carbon #3 or carbon #2 since they're equally stable?
Why does Bromonium ion attack more substituted carbon ?
🤔🤔
Please explain how the structure came about
Please ask a question that makes sense
Wonderful explanations!
Very awesome mam.Keep it up 👍😊
In problem D there is the formation of two tertiary carbocations. However the stabilization is the product of hyperconjugation. The position "1" with the methyl group gets stabilized by 3 C-H-bonds whereas in position "2" with the ethy group it should only get stabilized by 2 C-H-bonds since its -CH2-CH3. So im thinking that the more stable product ist the one wehre the Cl sits on Position "1". Am I thinking about this wrongly? Help or correction would be appreciated, thanks :)
that's what I thought haha, I'm pretty sure it (the H) adds to the less substituted
B will be syn or anti addition?
Great video, sums up a lot of ideas, thank u so much
This is so helpful. Thank you!
Wonderful.......
God bless you.....
For B, wouldn't it also be racemic?
that's what I thought,
I don't think that the C with the OH and CH3 is a stereocenter, It Is only attached to 3 different groups not 4.
@@nastasiamijucic6791 that was my thought also
First year thank you
Helped me in my revision
Thanks a lot ma'am .
😂😂
very informative! thanks!
In G 14:10 will there be no formation of hexane ?
a little late, but yeah a hexane would form from rearrangement good catch lol
no cuz cyclohexane is less stable than cyclopentane
if there was cyclohexane with a cation then yes with rearrangement it would turn into cyclopentane
Roci or racimic i can't see d handwriting
Nice one
Thank you so much omg
Nice
what the fuck?