Maam i am using another formula in which the order is given by the formula N = log{(10^-kp/10 - 1)/(10^-ks/10 - 1)}/2log(wp/ws) and not getting the order =4... Can you explain why so?
Our teacher was making us just solve the numerical problems , which was very boring. In this video, you have explained the basic concept that is very useful. Thank u ma'am.
I have a question...as omega tends to infinity. For a Butterworth filter, Why does the magnitude of the frequency response tend to (omega/omega_c)^-N and not 0...,where omega_c is cutoff frequency
Nicely explained ma'am. Helped me in completing my assignments! Thank you 😊
love from jashore university of science and technology, Bangladesh.🙏❤
Please let me know 🙏
How your voice is clear
I am also teaching about 3d printing humanminiature but background voice is more 😔
I do use normal hear phone
Can you let me know what device are you using for recording audio
Do you use any audio separating amplifier?
Maam i am using another formula in which the order is given by the formula N = log{(10^-kp/10 - 1)/(10^-ks/10 - 1)}/2log(wp/ws) and not getting the order =4... Can you explain why so?
this is a question explained as per the textbook
Why did you not solved lower term in log and only upper term solved for calculating
Why did you mam not explain 10power 0.1
Tq mam it is very useful for me and your teaching is excellent mam
Our teacher was making us just solve the numerical problems , which was very boring. In this video, you have explained the basic concept that is very useful. Thank u ma'am.
Thanks for the support
plz do problems on active filter on 1st order butterworth filter for isro TA exam.
Crystal clear mam tq
Love your class mam
thankuu for the vid it's helpful , however the sound is not really clear using a mic will improve the quality. Thanku
Impressive. how did you do estimate log value ?
How you get log value explain in other videos
What happens when attenuations are not given in db.what to do if they give As and Ap
I have a question...as omega tends to infinity. For a Butterworth filter, Why does the magnitude of the frequency response tend to (omega/omega_c)^-N and not 0...,where omega_c is cutoff frequency
Hey ..Buddy ..Can you Plzz tell your question clearly ..?
What happens to the magnitude of the impulse response if frequency tends to infinity?
@@andyralph9495 Impulse response is unit step function .It lies on Y axis on all frequency.(I guess plz check)
I meant magnitude response...not impulse response...m sorry..my bad
@@andyralph9495 Maximum attenuation. Ideally we take 0 magnitude response if omega tends to infinite .(No signal will pass)
Mam please put high pass filter video
Thanks ma'am , supper explanation , it helped me a lot thank you so much
Excellent❤️
Great Video!
Glad you liked it
Exalent teaching.
Please subscribe and share
Any video related chebishev low pass filter ? . Thanks for these type of dsp exam point view classes.
I will do shortly
Mam It's amazing ..
Please share among classmates
Ma'am i have one doubt, I've got 3.28 so may i take it as N= 4?
Ma'am please reply 👏👏
Respect and Love From Bhutan.
U have to take N =4
@@EasyElectronics975 i shall remain Grateful to You.
Thank you Very Much🙏
Wow from Bhutan, I am overwhelmed
@@EasyElectronics975 hii mam, may i use the same formula to calculate the order of HPF? Also the cut off Freq of HPF will also be same????
🙏🙏
Thank you ma’am
mam good book to practce
Thank you so much your videos are really helpful
Please share with colleagues
Thank You mam. It helped. ❤
Please subscribe and share
Wowww.... vry easy explanation thank u mam🙏🙏🙏
Eee order kanunna video ano adyam padikkendath butterworthil
Yes