Very helpful. I missed a week containing the lecture over Gravimetric Analysis and Titrations in my Chemistry class. This made things much clearer! Please come be my professor! :-(
This very much cleared up the foggy mess of my brain with regards to gravimetry :) always a fun time to learn when you really understand what's being taught to you. Thank you agaaaiiinnnn Professor Dave!!!!!
Here in the Netherlands, you gain no points whenever your write something like CaSO4 (aq). Spectator ions should never be used in reactions and ions are seperated in solution! Furthermore, nice videos! Keep on going!
It's not a net ionic equation, calcium sulfate must be written because we are doing stoichiometry to figure out the initial mass of it that was in the solid mixture.
Of course I realize that in order to know the initial mass you need to know the molar mass of CaSO4 and that you were not doing a net ionic equation. I just want to prevent misconceptions from happening. For example, you could describe the precipitation reaction as Ba2+ + SO4 2- -> BaSO4 and then deduce (since the source of Barium ions is in surplus) that the sulfate ions are the limiting factor. Then from the process of dissolving calciumsulfate you can and should determine the eventual stoichiometry. Being a science teacher I cannot stand people who write for example NaCl (aq), since we all know there is no such thing. So there's another way of explaining it, is all I'm saying. I understand your reasoning for presenting the matter in this way, but it should be explicitly stated that said notation is chemically incorrect. I hope I don't offend you, since I'm really in love with the work you're doing! I'm even learning Italian because of you!! (yet, I still don't know why...)
@@ProfessorDaveExplains Oh that's okay then. I just assumed all practice problems had tutorials related to them and I figured I'd watch it too but this video is still helpful on its own so thank you
Hello from India..thank you for solution I have different solution. Gravimetric factor=Formula wt of analyte/formula wt of ppt X mole of analyte/mol of ppt =136.14/233.38=0.5833 Weight of analyte=Gravimetric Factor X wt of ppt =0.5833 X 0.6168 =0.3597g Percent content=0.3597/0.4550*100 =79.05%
It's the same solution. Your Gravimetric factor came from a similar process. That equation was derived just like in the video. But helps to do quick maths in the exams I guess. :D
what i am trying to do is apply this method to an experiment. all the info that I have are from that experiment but there are two acids applied to the ferrous sulfite substance, hydrochloric acid and nitric acid. what should I do?
Bro IDK what I did wrong on Khan Academy's example problem with no video cuz it said I was wrong then I came here to see how to do it and I did literally the same steps as this video... I must have messed up my arithmetic somewhere or rounded wrong or something.
I think nobody can help you neang, since no analytical solutions exist to this integral. Just two short comments: 1. why are you posting this as a reply to this (chemical) video? 2. if you really want an approximate solution: just use the Taylor expansion of e^x and then use integration by parts.... Good luck!
Very helpful. I missed a week containing the lecture over Gravimetric Analysis and Titrations in my Chemistry class. This made things much clearer! Please come be my professor! :-(
wait, so its just stoichiometry? man i was tripping thinking i missed something..
Always has been
Same
Not if you have to actually do it in the lab
man i wish u were my chemistry professor
You wouldn't want that. He's a terrible person.
This was very helpful and easy to understand. Thanks so much for uploading this Professor Dave!!!
thanks chemistry jesus, I was stuck for a while on this topic
Much thanks Professor, your science tutorials have been very helpful for long time. Of course you deserve much more than subscribe. Be blessed.
This very much cleared up the foggy mess of my brain with regards to gravimetry :) always a fun time to learn when you really understand what's being taught to you. Thank you agaaaiiinnnn Professor Dave!!!!!
Was looking up what gravimetry was I still don't know but I understand everything that happened here. Thanks Dave
such a clear explanation! Thanks a lot !!!
Better than my university lecturer.
Here in the Netherlands, you gain no points whenever your write something like CaSO4 (aq). Spectator ions should never be used in reactions and ions are seperated in solution! Furthermore, nice videos! Keep on going!
It's not a net ionic equation, calcium sulfate must be written because we are doing stoichiometry to figure out the initial mass of it that was in the solid mixture.
Of course I realize that in order to know the initial mass you need to know the molar mass of CaSO4 and that you were not doing a net ionic equation. I just want to prevent misconceptions from happening. For example, you could describe the precipitation reaction as Ba2+ + SO4 2- -> BaSO4 and then deduce (since the source of Barium ions is in surplus) that the sulfate ions are the limiting factor. Then from the process of dissolving calciumsulfate you can and should determine the eventual stoichiometry. Being a science teacher I cannot stand people who write for example NaCl (aq), since we all know there is no such thing. So there's another way of explaining it, is all I'm saying. I understand your reasoning for presenting the matter in this way, but it should be explicitly stated that said notation is chemically incorrect. I hope I don't offend you, since I'm really in love with the work you're doing! I'm even learning Italian because of you!! (yet, I still don't know why...)
I just learn that I have to learn more. Just catched 10%. Nice video to study, Thanks.
Thanx dr Dave we all appreciate it ♥️
This was really helpful, Thank You!
THANK YOUUUU SOOOO MUCH SIR!!!
this is just a matter of stoichiometry, just take note of the whole chemical reaction then ur good. stoich works with titration problem as well for me
Thx that was a good help☺️
Thanks it was very helpful
thank you！So helpful！
Thanks so much. you have solved the exact problem in my handout, I failed to solve it
Thank you
Please I need more calculations on gravimetric of qualitative analysis of inorganic mixtures for pharmacy please
at 3:16 where did u get 0.4550
i mean why do use that value?
initial mass of the sample, given information at the start
Is there a lecture for this? I couldn't find one despite using the search function on the channel
actually no i never did a tutorial on this
@@ProfessorDaveExplains Oh that's okay then. I just assumed all practice problems had tutorials related to them and I figured I'd watch it too but this video is still helpful on its own so thank you
should've used different coefficents on stuff like the SO_4 to illustrate that concept
Hello from India..thank you for solution
I have different solution.
Gravimetric factor=Formula wt of analyte/formula wt of ppt X mole of analyte/mol of ppt
=136.14/233.38=0.5833
Weight of analyte=Gravimetric Factor X wt of ppt
=0.5833 X 0.6168
=0.3597g
Percent content=0.3597/0.4550*100
=79.05%
It's the same solution. Your Gravimetric factor came from a similar process. That equation was derived just like in the video. But helps to do quick maths in the exams I guess. :D
thank you chemistry daddy
1:06 where did Ca(No³)² came from
Double displacement. You switch out the cations (Ca and Ba) and it results in Ca(NO3)2.
Where did you get the 136.14g?
it's the molar mass of CaSO4
40(Ca)+96(SO4)=136
Thnks
that opanic when he want when youre ready give it a try when i dont know whta to do huhuhuhuh
sir suggested book for promblem of gravimetry
what i am trying to do is apply this method to an experiment. all the info that I have are from that experiment but there are two acids applied to the ferrous sulfite substance, hydrochloric acid and nitric acid. what should I do?
This was soooo helpful, thank you!
Now if only my data will cooperate with me 😭😭😭
Bro IDK what I did wrong on Khan Academy's example problem with no video cuz it said I was wrong then I came here to see how to do it and I did literally the same steps as this video... I must have messed up my arithmetic somewhere or rounded wrong or something.
haha no its just a wack problem :/
help ∫eˣln(x)dx
I think nobody can help you neang, since no analytical solutions exist to this integral. Just two short comments:
1. why are you posting this as a reply to this (chemical) video?
2. if you really want an approximate solution: just use the Taylor expansion of e^x and then use integration by parts.... Good luck!
sorry
Here noe
O Arjun, I am seated in the heart of all living entities. I am the beginning, middle, and end of all beings.
waste of time..
Change your name to JESUS CHEMISTRY