Good question! I just worked with the dimensions I was given. If we treat the bracket as the hypotenuse of a triangle, we have a 1.5m base and 2m height. This is equivalent to the 3 4 5 triangle i draw later in the problem. From there, if you wanted the angle with respect to x, you can do tan-1 (3/4). Hope that helps!
Hey! Its a special triangle (also called a 3 4 5 triangle). You can use 1.5, 2 and 2.5, but its just common to write it as 3 4 5 when you have the equivalent relationship. Hope that helps
No problem As a brief recall of what the equation means, we are taking the equilibrium equation for Moment at A because it removes the Reactions at A (Ax and Ay), leaving the last unknown Fb to solve for. Now, since this is a equilibrium of moment equation, we remember that M= F*d (Moment = Force * Distance), so we are doing this for every force and reaction within our member (remembering that there is zero distance between the reactions at A and point A, the logic behind not solving for these in this equation). The formula takes 600N as Negative since it creates a Clockwise rotation with respect to A, and its located 1m from A ( Similar logic for the 800N force as well in the equation). The 900Nm moment is Negative for CW rotation as mentioned at well, but distance is not relevant since it is already in terms of moment for the equation. Lastly Fb: We need the Y component of this force because the x component will create no rotation about A. To do this, we use the special triangle to break down the component of Fb, so Fby is Fb * ( 3/5 ), then we must not forget the Counter clockwise rotation about A (+ sign) and distance from A. The rest is easy, bring over the constant values to the other side of the equation (don't forget sign changes), divide by the coefficients of Fb, and BOOM... Fb is solved. Hope this helps
Thankyou so much, send lots of love❤
Thanks for the support, glad I could help!
Skip to 2:45 if you wish to only see the problem solving steps, thanks for watching!
Very insightful video, you just got another sub!
how did you get the slope of force CB?
Good question! I just worked with the dimensions I was given. If we treat the bracket as the hypotenuse of a triangle, we have a 1.5m base and 2m height. This is equivalent to the 3 4 5 triangle i draw later in the problem. From there, if you wanted the angle with respect to x, you can do tan-1 (3/4). Hope that helps!
Good video! Thanks for the help.
No problem, Glad it helped!
Hello,for c beam 100 mm, length is 1.5 m at 0,75m we have force strut, question is: how many kg can it take at the end of the beam? Thank You
Why is a 3 and not 1.5?
Hey! Its a special triangle (also called a 3 4 5 triangle). You can use 1.5, 2 and 2.5, but its just common to write it as 3 4 5 when you have the equivalent relationship. Hope that helps
can you explain how to solve that first equation to get Fb
No problem
As a brief recall of what the equation means, we are taking the equilibrium equation for Moment at A because it removes the Reactions at A (Ax and Ay), leaving the last unknown Fb to solve for.
Now, since this is a equilibrium of moment equation, we remember that M= F*d (Moment = Force * Distance), so we are doing this for every force and reaction within our member (remembering that there is zero distance between the reactions at A and point A, the logic behind not solving for these in this equation). The formula takes 600N as Negative since it creates a Clockwise rotation with respect to A, and its located 1m from A ( Similar logic for the 800N force as well in the equation). The 900Nm moment is Negative for CW rotation as mentioned at well, but distance is not relevant since it is already in terms of moment for the equation. Lastly Fb: We need the Y component of this force because the x component will create no rotation about A. To do this, we use the special triangle to break down the component of Fb, so Fby is Fb * ( 3/5 ), then we must not forget the Counter clockwise rotation about A (+ sign) and distance from A.
The rest is easy, bring over the constant values to the other side of the equation (don't forget sign changes), divide by the coefficients of Fb, and BOOM... Fb is solved.
Hope this helps
respect
Cheers, glad I could help!
thank you!!!
No problem Luisa, glad I could help