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in forced convection over plate in case of laminar boundary layer, Nu (nusselt number) is directly proportional to root x (i.e. x^0.5), this means Nu increases with x, which means Nu will be max at x= L, but avg Nu =2 x Nu at x=L. i.e avg Nu is more than maximum Nu. how is this possible ?
Dear GATE Aspirants, Lecture notes, DPP, Video and everything related to the class will be provided on the PW App. Inside the PW App, Gate Crash Course and Abhyas Batch for every class are created in the GATE category. There you can enroll in a free batch and access Videos, Notes, and DPPs.
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🛑 Check Our Mechanical Engineering Abhyas Batch: bit.ly/Abhyas_Mechanical
🛑 Check Our Mechanical Engineering Parakram Batch: bit.ly/Parakram_Mechanical_Hinglish
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▶ Our Telegram Page: t.me/gatewallah_official
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Dear GATE Aspirants, Any irrelevant/abusive comment will not be tolerated, students doing so will be blocked immediately.
sir garda uda diya maaja aagaya aapko dekhke
Sir h is 19.88 W/m2K not 213.823 sir it is Nu value not h value and heat transfer rate = 53.69 watts
Yes, same here
Can we get the notes of these lectures?
If yes, from where?
Sir, in last question Nu = 213.57 and h = 19.86 w/m2k right?
correct, h is 19.86 and Nusselt's number is 213.8
Yes correct
shit!!you are a below average student
Sir.....Sir.....Sir....
Thank you sir
sirf thank you se kaam nahi chalega 3 bar reshare karo
Thanku sir ji
in forced convection over plate in case of laminar boundary layer, Nu (nusselt number) is directly proportional to root x (i.e. x^0.5), this means Nu increases with x, which means Nu will be max at x= L, but avg Nu =2 x Nu at x=L.
i.e avg Nu is more than maximum Nu.
how is this possible ?
not nusselt number only th product of local heat transfer coeff and x
I think you are right…avg Nu should be 0.66 time local Nu
because nu directly proportional to h(x)
Maza a gya sir🔥🔥
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