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1:29:27- (vi) (3x/2) - (5y/3) = - 2 ...(1) x/3 + y/2 = 13/6 ...(2) Multiply both the equations (1) and (2) by 6, to remove the denominatores and making it easier for calculation. [3x/2 - 5y/3 = - 2] × 6 9x - 10y = - 12 ...(3) [x/3 + y/2 = 13/6] × 6 2x + 3y = 13 ...(4) By solving equation (3) 9x - 10y = - 12 10y = 9x + 12 y = (9x + 12) / 10 ...(5) Substituting y = (9x + 12) / 10 in equation (4), we get 2x + 3 [(9x + 12) / 10] = 13 (20x + 27x + 36) / 10 = 13 47x = 130 - 36 x = 94/47 = 2 Substituting x = 2 in equation (5), we get y = (9 × 2 + 12) / 10 y = 30/10 y = 3 Thus, x = 2, y = 3 1:48:50 - Let the cost of 1 bat = ₹ x And the cost of 1 ball = ₹ y 7x + 6y = 3800 ....(1) 3x + 5y = 1750 ....(2) By solving equation (1), 7x + 6y = 3800 6y = 3800 - 7x y = (3800 - 7x) / 6 ....(3) Substituting y = (3800 - 7x) / 6 in equation (2), we get 3x + 5 [(3800 - 7x) / 6] = 1750 (18x + 19000 - 35x) / 6 = 1750 -17x + 19000 = 1750 × 6 17x = 19000 - 10500 x = 8500/17 x = 500 Substituting x = 500 in equation (3), we get y = (3800 - 7 × 500) / 6 y = 300/6 y = 50 Cost of 1 bat is ₹ 500 Cost of 1 ball is ₹ 50 2:04:20- ) Let the numerator = x And denominator = y Then the fraction is x / y When 2 is added to both numerator and denominator, (x + 2) / (y + 2) = 9/11 11(x + 2) = 9( y + 2) 11x + 22 = 9y + 18 11x - 9y + 22 - 18 = 0 11x - 9y + 4 = 0 ...(1) When 3 is added to both numerator and denominator (x + 3) / (y + 3) = 5/6 6(x + 3) = 5( y + 3) 6x + 18 = 5y + 15 6x - 5y + 18 - 15 = 0 6x - 5y + 3 = 0 ....(2) 5y = 6x + 3 y = (6x + 3) / 5 ....(3) Substituting y = (6x + 3) / 5 in equation (1) 11x - 9 [(6x + 3) / 5] + 4 = 0 [55x - 9(6x + 3) + 20] / 5 = 0 55x - 54x - 27 + 20 = 0 x - 7 = 0 x = 7 Substituting x = 7 in equation (3) we get, y = (6 × 7 + 3) / 5 y = (42 + 3) / 5 y = 45/5 y = 9 Thus, the fraction is 7/9. Substitution method: 2:20:30- (ii) 3x + 4y = 10 ....(1) 2x - 2y = 2 ....(2) By solving equation (1) 3x + 4y = 10 4y = 10 - 3x y = (10 - 3x) / 4 ....(3) Substituting y = (10 - 3x) / 4 in equation (2) 2x - 2[(10 - 3x) / 4] = 2 (4x -10 + 3x) / 2 = 2 7x - 10 = 4 7x = 4 + 10 x = 14/7 x = 2 Substituting x = 2 in equation (3) y = (10 - 3 × 2) / 4 y = (10 - 6) / 4 y = 4/4 y = 1 Thus, x = 2 and y = 1 (iii) Substitution method: 3x - 5y - 4 = 0 ....(1) 9x = 2y + 7 ....(2) By solving equation (1) 3x - 5y - 4 = 0 5y = 3x - 4 y = (3x - 4) / 5 ....(3) Substituting y = (3x - 4) / 5 in equation (2) 9x = 2[(3x - 4) / 5] + 7 9x = (6x - 8 + 35) / 5 45x = 6x + 27 45x - 6x = 27 39x = 27 x = 27/39 x = 9/13 [By simplifying and reducing the fraction] Substitute x = 9/13 in equation (3) y = [3(9/13) - 4]/5 y = (27 - 52)/13 × 1/5 y = - 25/13 × 1/5 y = - 5/13 Thus, y = - 5/13 and x = 9/13 (iv) Substitution method: x/2 + 2y/3 = - 1 ...(1) x - y/3 = 3 ...(2) By solving equation (2) x - y/3 = 3 x = y/3 + 3 x = (y + 9) / 3 ....(3) Substituting x = (y + 9) / 3 in equation (1) [(y + 9)/3] / 2 + 2y/3 = - 1 (y + 9 + 4y)/6 = - 1 5y + 9 = - 6 5y = - 6 - 9 y = - 15/5 y = -3 Substituting y = -3 in equation (3) x = (- 3 + 9) / 3 x = 6/3 x = 2 Thus, x = 2 and y = -3 2:32:46- Let the numerator = x And the denominator = y Then the fraction = x/y When 1 is added to the numerator and 1 is subtracted from the denominator, the fraction reduces to 1 as shown below. (x + 1)/(y - 1) = 1 x + 1 = y - 1 x - y + 1 + 1 = 0 x - y + 2 = 0 ...(1) When 1 is added to the denominator, the fraction becomes 1/2 as shown below. x/(y + 1) = 1/2 2x = y + 1 2x - y - 1 = 0 ...(2) By subtracting equation (2) from equation (1) (x - y + 2) - (2x - y - 1) = 0 x - y + 2 - 2x + y + 1 = 0 - x + 3 = 0 x = 3 Substitute x = 3 in equation (1) 3 - y + 2 = 0 y = 5 Equations are x - y + 2 = 0 and 2x - y -1 = 0 where the numerator of the fraction is x, and denominator is y. The fraction is 3/5. 2:36:24- Let the present age of Nuri = x years And the present age of Sonu = y years 5 years ago, Nuri’s age = (x - 5) years Sonu’s age = (y - 5) years x - 5 = 3(y - 5) x - 5 = 3y - 15 x - 3y - 5 + 15 = 0 x - 3y + 10 = 0 ...(1) 10 years later, Nuri’s age = (x + 10) years Sonu’s age = (y + 10) years x + 10 = 2(y + 10) x + 10 = 2y + 20 x - 2y + 10 - 20 = 0 x - 2y - 10 = 0 ...(2) By subtracting equation (2) from equation (1) (x - 3y +10) - ( x - 2y -10) = 0 x - 3y +10 - x + 2y +10 = 0 - y + 20 = 0 y = 20 Now, substitute y = 20 in equation (1) x - 3 × 20 + 10 = 0 x - 60 + 10 = 0 x - 50 = 0 x = 50 Linear equations are x - 3y +10 = 0 and x - 2 y -10 = 0 where the present age of Nuri is x and Sonu is y The age of Sonu is 20 years and age of Nuri is 50 years. 2:51:47- Let number of notes of ₹ 50 = x Number of notes of ₹ 100 = y Meena got 25 notes in all; x + y = 25 ...(1) Meena withdrew ₹ 2000; 50x +100y = 2000 50(x + 2y) = 2000 x + 2y = 2000/50 x + 2y = 40 ...(2) By subtracting equation (1) from equation (2) (x + 2y) - (x + y) = 40 - 25 x + 2y - x - y = 15 y = 15 Substituting, y = 15 in equation (1) x + 15 = 25 x =10 Equations are x + y = 25 and x + 2y = 40 where number of ₹ 50 and ₹ 100 notes are x and y respectively. The number of ₹ 50 notes is 10 and the number of ₹ 100 notes is 15. 2:57:59- Let the fixed charge = x Charge per extra day = y Saritha paid ₹ 27 for a book kept for 7 days; We know that the lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Therefore, x + (7 - 3) y = 27 x + 4y = 27 ...(1) Susy paid ₹ 21 for a book kept for 5 days; x + (5 - 3) y = 21 x + 2y = 21 ...(2) By subtracting equation (2) from equation (1) (x + 4 y) - (x + 2 y) = 27 - 21 x + 4y - x - 2y = 6 2y = 6 y = 6/2 y = 3 Substituting y = 3 in equation (1) x + 4 × 3 = 27 x + 12 = 27 x = 27 - 12 x = 15 Equations are x + 2y = 21 and x + 4y = 27 where fixed charge is ₹ x and charge for each extra day is ₹ y. The fixed charge is ₹ 15 and the charge for each extra day is ₹ 3.
@@azraquyoom36 exam kya andhwishwas keh sath doge? Toh thik hai bhai main bhi padhai nahi karungi kyuki 1 like karne seh toh 100marks mil hi jayenge naa💀
1:48:51 ATTENTION ⚠️ Equation is wrong ... 1:48:51 So that's why when I' try more times to solve but my answer comes wrong so the right equation is := 7x+6y=3800 3x+5y=1750 In video this "1750" change in "1780" So write the right equation...👍🏻✨*
Guys I really want you all to study from Ritik sir in Class 10th coz' before watching his lectures I always get less marks in Maths but after watching his lectures I feel very confident and I starting loving Maths and when I see paper I feel like I have done this question he's awesome ❤❤ Thankuuu sirrrrr ❤❤
@@AlfaizAnsari-cb6wq You can skip NCERT questions but examples are very imp. Coz' CBSE knows that we didn't solve examples so they sometimes give examples so yes examples are imp.
😂I will not tell u to like my comment to score 95%+ or 100marks in boards 😂I just want to say go and work hard don't waste time in watching comments in between lectures 😂😂😂😂😂😂😂😂😂😂jao padho exam he kl
40:30 Actually vaha par minus sign nahi de rakha so vo consistent hogaa! (5x-3y=11) not ( -5....) So vaha par -1/2 ki jagah 1/-2..aata Correct me if I'm wrong
I got 3.2 ex. As homework for summer vacations but with sbstitution method and i was absent before holidays so i didnt understood elimination method too and thats why this helped me a lot☺😊
Home work on 1:29:14 X = 2 Y = 3❤❤❤ Home work of ex 3.3 question no 2 part 3 ans 1:49:10 Cost of one bat will be 500 and cost of one ball be 50 ❤❤ Home work of ex 3.3 question 2 part 5 on 2:04:00 X= 7 Y= 9 🎉🎉🎉
Sir aapko jitna thankyou bolu utana kaam h aapko pata h mujhe ya ch Kitna tough lag raha gha but aab aapse padhna ka baad ya ch mere liya kuch bhi nhi h 😅 thankyou thankyou so much sir love you so much sir ❤
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2:58:02
Fixed charge for 3 days is ₹15
Additional charge for per day is ₹3
❤
1:29:27-
(vi) (3x/2) - (5y/3) = - 2 ...(1)
x/3 + y/2 = 13/6 ...(2)
Multiply both the equations (1) and (2) by 6, to remove the denominatores and making it easier for calculation.
[3x/2 - 5y/3 = - 2] × 6
9x - 10y = - 12 ...(3)
[x/3 + y/2 = 13/6] × 6
2x + 3y = 13 ...(4)
By solving equation (3)
9x - 10y = - 12
10y = 9x + 12
y = (9x + 12) / 10 ...(5)
Substituting y = (9x + 12) / 10 in equation (4), we get
2x + 3 [(9x + 12) / 10] = 13
(20x + 27x + 36) / 10 = 13
47x = 130 - 36
x = 94/47 = 2
Substituting x = 2 in equation (5), we get
y = (9 × 2 + 12) / 10
y = 30/10
y = 3
Thus, x = 2, y = 3
1:48:50 -
Let the cost of 1 bat = ₹ x
And the cost of 1 ball = ₹ y
7x + 6y = 3800 ....(1)
3x + 5y = 1750 ....(2)
By solving equation (1),
7x + 6y = 3800
6y = 3800 - 7x
y = (3800 - 7x) / 6 ....(3)
Substituting y = (3800 - 7x) / 6 in equation (2), we get
3x + 5 [(3800 - 7x) / 6] = 1750
(18x + 19000 - 35x) / 6 = 1750
-17x + 19000 = 1750 × 6
17x = 19000 - 10500
x = 8500/17
x = 500
Substituting x = 500 in equation (3), we get
y = (3800 - 7 × 500) / 6
y = 300/6
y = 50
Cost of 1 bat is ₹ 500
Cost of 1 ball is ₹ 50
2:04:20-
) Let the numerator = x
And denominator = y
Then the fraction is x / y
When 2 is added to both numerator and denominator,
(x + 2) / (y + 2) = 9/11
11(x + 2) = 9( y + 2)
11x + 22 = 9y + 18
11x - 9y + 22 - 18 = 0
11x - 9y + 4 = 0 ...(1)
When 3 is added to both numerator and denominator
(x + 3) / (y + 3) = 5/6
6(x + 3) = 5( y + 3)
6x + 18 = 5y + 15
6x - 5y + 18 - 15 = 0
6x - 5y + 3 = 0 ....(2)
5y = 6x + 3
y = (6x + 3) / 5 ....(3)
Substituting y = (6x + 3) / 5 in equation (1)
11x - 9 [(6x + 3) / 5] + 4 = 0
[55x - 9(6x + 3) + 20] / 5 = 0
55x - 54x - 27 + 20 = 0
x - 7 = 0
x = 7
Substituting x = 7 in equation (3) we get,
y = (6 × 7 + 3) / 5
y = (42 + 3) / 5
y = 45/5
y = 9
Thus, the fraction is 7/9.
Substitution method:
2:20:30-
(ii) 3x + 4y = 10 ....(1)
2x - 2y = 2 ....(2)
By solving equation (1)
3x + 4y = 10
4y = 10 - 3x
y = (10 - 3x) / 4 ....(3)
Substituting y = (10 - 3x) / 4 in equation (2)
2x - 2[(10 - 3x) / 4] = 2
(4x -10 + 3x) / 2 = 2
7x - 10 = 4
7x = 4 + 10
x = 14/7
x = 2
Substituting x = 2 in equation (3)
y = (10 - 3 × 2) / 4
y = (10 - 6) / 4
y = 4/4
y = 1
Thus, x = 2 and y = 1
(iii) Substitution method:
3x - 5y - 4 = 0 ....(1)
9x = 2y + 7 ....(2)
By solving equation (1)
3x - 5y - 4 = 0
5y = 3x - 4
y = (3x - 4) / 5 ....(3)
Substituting y = (3x - 4) / 5 in equation (2)
9x = 2[(3x - 4) / 5] + 7
9x = (6x - 8 + 35) / 5
45x = 6x + 27
45x - 6x = 27
39x = 27
x = 27/39
x = 9/13 [By simplifying and reducing the fraction]
Substitute x = 9/13 in equation (3)
y = [3(9/13) - 4]/5
y = (27 - 52)/13 × 1/5
y = - 25/13 × 1/5
y = - 5/13
Thus, y = - 5/13 and x = 9/13
(iv)
Substitution method:
x/2 + 2y/3 = - 1 ...(1)
x - y/3 = 3 ...(2)
By solving equation (2)
x - y/3 = 3
x = y/3 + 3
x = (y + 9) / 3 ....(3)
Substituting x = (y + 9) / 3 in equation (1)
[(y + 9)/3] / 2 + 2y/3 = - 1
(y + 9 + 4y)/6 = - 1
5y + 9 = - 6
5y = - 6 - 9
y = - 15/5
y = -3
Substituting y = -3 in equation (3)
x = (- 3 + 9) / 3
x = 6/3
x = 2
Thus, x = 2 and y = -3
2:32:46-
Let the numerator = x
And the denominator = y
Then the fraction = x/y
When 1 is added to the numerator and 1 is subtracted from the denominator, the fraction reduces to 1 as shown below.
(x + 1)/(y - 1) = 1
x + 1 = y - 1
x - y + 1 + 1 = 0
x - y + 2 = 0 ...(1)
When 1 is added to the denominator, the fraction becomes 1/2 as shown below.
x/(y + 1) = 1/2
2x = y + 1
2x - y - 1 = 0 ...(2)
By subtracting equation (2) from equation (1)
(x - y + 2) - (2x - y - 1) = 0
x - y + 2 - 2x + y + 1 = 0
- x + 3 = 0
x = 3
Substitute x = 3 in equation (1)
3 - y + 2 = 0
y = 5
Equations are x - y + 2 = 0 and 2x - y -1 = 0 where the numerator of the fraction is x, and denominator is y.
The fraction is 3/5.
2:36:24-
Let the present age of Nuri = x years
And the present age of Sonu = y years
5 years ago,
Nuri’s age = (x - 5) years
Sonu’s age = (y - 5) years
x - 5 = 3(y - 5)
x - 5 = 3y - 15
x - 3y - 5 + 15 = 0
x - 3y + 10 = 0 ...(1)
10 years later,
Nuri’s age = (x + 10) years
Sonu’s age = (y + 10) years
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x - 2y + 10 - 20 = 0
x - 2y - 10 = 0 ...(2)
By subtracting equation (2) from equation (1)
(x - 3y +10) - ( x - 2y -10) = 0
x - 3y +10 - x + 2y +10 = 0
- y + 20 = 0
y = 20
Now, substitute y = 20 in equation (1)
x - 3 × 20 + 10 = 0
x - 60 + 10 = 0
x - 50 = 0
x = 50
Linear equations are x - 3y +10 = 0 and x - 2 y -10 = 0 where the present age of Nuri is x and Sonu is y
The age of Sonu is 20 years and age of Nuri is 50 years.
2:51:47-
Let number of notes of ₹ 50 = x
Number of notes of ₹ 100 = y
Meena got 25 notes in all;
x + y = 25 ...(1)
Meena withdrew ₹ 2000;
50x +100y = 2000
50(x + 2y) = 2000
x + 2y = 2000/50
x + 2y = 40 ...(2)
By subtracting equation (1) from equation (2)
(x + 2y) - (x + y) = 40 - 25
x + 2y - x - y = 15
y = 15
Substituting, y = 15 in equation (1)
x + 15 = 25
x =10
Equations are x + y = 25 and x + 2y = 40 where number of ₹ 50 and ₹ 100 notes are x and y respectively.
The number of ₹ 50 notes is 10 and the number of ₹ 100 notes is 15.
2:57:59-
Let the fixed charge = x
Charge per extra day = y
Saritha paid ₹ 27 for a book kept for 7 days;
We know that the lending library has a fixed charge for the first three days and an additional charge for each day thereafter.
Therefore,
x + (7 - 3) y = 27
x + 4y = 27 ...(1)
Susy paid ₹ 21 for a book kept for 5 days;
x + (5 - 3) y = 21
x + 2y = 21 ...(2)
By subtracting equation (2) from equation (1)
(x + 4 y) - (x + 2 y) = 27 - 21
x + 4y - x - 2y = 6
2y = 6
y = 6/2
y = 3
Substituting y = 3 in equation (1)
x + 4 × 3 = 27
x + 12 = 27
x = 27 - 12
x = 15
Equations are x + 2y = 21 and x + 4y = 27 where fixed charge is ₹ x and charge for each extra day is ₹ y.
The fixed charge is ₹ 15 and the charge for each extra day is ₹ 3.
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Jisne bhi like nhi kiya vo 💯 percent fail hoga
Legend are watching one day before exam like here nahi to fail❤❤❤
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Yesss😂😊
Yes
1 like = 100 marks
Logic left its chat💀
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@@azraquyoom36 exam kya andhwishwas keh sath doge? Toh thik hai bhai main bhi padhai nahi karungi kyuki 1 like karne seh toh 100marks mil hi jayenge naa💀
@@saradapradhan3906 Haan thik hai 💀karlu try lekin bag pack krke rkhna baad Mai time lagega
Likes ki bheekh maangne ka tarika thoda casual h 😂
1:48:51 ATTENTION ⚠️ Equation is wrong ... 1:48:51 So that's why when I' try more times to solve but my answer comes wrong so the right equation is :=
7x+6y=3800
3x+5y=1750
In video this "1750" change in "1780" So write the right equation...👍🏻✨*
Thankyou ayushi
Yes sir missed
Ohh I haven't noticed, i solved the sum by myself and skipped the part
same with me bruhhh
i got y=256.060060006
💀
Guys I really want you all to study from Ritik sir in Class 10th coz' before watching his lectures I always get less marks in Maths but after watching his lectures I feel very confident and I starting loving Maths and when I see paper I feel like I have done this question he's awesome ❤❤ Thankuuu sirrrrr ❤❤
@@luvvv_dishaagr examples na lgae toh kyuki time km h 😢
@@AlfaizAnsari-cb6wq You can skip NCERT questions but examples are very imp. Coz' CBSE knows that we didn't solve examples so they sometimes give examples so yes examples are imp.
@@luvvv_disha sis agr examples na kre sirf ncert krle tuh pass tuh ho hi jaege 🥲
@@AlfaizAnsari-cb6wq Ha ofc pass to hi jayenge but accha score krne ke liye examples laga sakte hai
@@luvvv_disha ok thanks 😄
Exam is near "
"Nothing is clear"
"No need to fear"
Because our favorite PWs😍 sir is here """""""" ❤❤❤
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Kitne paise liyeee ve bolne ke 🤣🤣
@@Oceancharm13 dedh sau rupiya 😂
@@Oceancharm13 50 rupee overacting k bhi katenge 😂
Thanks to whole PW team for working so hard for us ❤️
X=25-6=19 2:16:28
m bhi yhi comment krne aaya thaa
24-25 batch
jai baba ki
1 like =99.99%
😂I will not tell u to like my comment to score 95%+ or 100marks in boards 😂I just want to say go and work hard don't waste time in watching comments in between lectures 😂😂😂😂😂😂😂😂😂😂jao padho exam he kl
Bhai kitna percent aay?
Bhai ye just 1.5 mahine pehle 10th me aaya hoga
@@shivam_y192
@@shivam_y19275% tumhara
Aur tu kya kar raha hai comment section par
😂😂
2025 batch attendance do😂
Yes
Present
Mee
Present 😂
Me bro 😅
Who is watching just 1 day before exam 😅 in 2x speed only legend 👏 are their i think 😂😅😅
Well as an Average student ,I wish I could score above 80%.
Bss goal rakh hi rahe ho to 95+ ka rakho
Yumhari english se to nahi lagta hai😂
Uski eng sahi hai bro@@mixupgaming2914
@@ImranKhan-zz1iryes bro if someone is going to make 60% and his goals is to achieve 95 then he can 80% easily it's good 👍
Basic Wale attendance laga do 😅
Hey bro basic maths ke liye NCERT enough h kya ya or kuch karna hai 😢🙏
Hnn @@AlfaizAnsari-cb6wq
@@AlfaizAnsari-cb6wq pyq (basic) + ncert
After an amazing 😊 lecture we should thank them and they are saying thanku
I hope allow of you get better marks in boards exam❤
Babua Sir's ever class is a different emotion, it has the power to bring you back to studies every time you get distracted
2:16:10 21 nhi hoga 19 hoga
Hn
40:30
Actually vaha par minus sign nahi de rakha so vo consistent hogaa! (5x-3y=11) not ( -5....) So vaha par -1/2 ki jagah 1/-2..aata
Correct me if I'm wrong
Nah u r fake😂
@@inaam_aiimsdelhi you got me 😂
@@fake7330 yes i am speed❤️🔥
Ya
Dono same hai budbak 😂
Thank u so much sir..
You are best teacher of mathematics you made my concepts crystal clear. And cleared all my doubts😊
Maths is feel so simple when I see your lecture
Sis.... kitna percent aay?
Sir, please provide us chapter wise previous year questions of last 10 years.🙏🙏🙏🙏🙏
PW student like button ✅
WTF YOU ARE TALKING BOUT 🙄
Tera comment kabhi famous nahi hoga 😂
Best of luck for class 10❤
I got 3.2 ex. As homework for summer vacations but with sbstitution method and i was absent before holidays so i didnt understood elimination method too and thats why this helped me a lot☺😊
Jo hamare question hote ha vo sir ke mind me hai .😊
Actually 🙃
2:54:51 kaash school me aisa concept clear krte to vahi teacher se same cheez coaching me na padhne padta uske bad bhi clear TH-cam me hora h
Basic maths ke liye NCERT enough h kya plz koi bta de🥲🙏
Hnn fichli bar ka paper ncert se hi aaya tha
quadratic equation ke liye vote kro..❤😅sb ke 90 percent aajaye..
1:11:45 Anyone notice what did he say 😅😅 💀💀🗿🗿
Yes 😂
Hn😂
28:19 Sir is ma coincident system nahi aata consistent aata hai.......... BTW love u Babua❤❤❤❤ 28:19
2:51:39 no.of notes of Rs.50 is 10
And no.of notes of Rs.100 is 15
Thankyou so much sir 😊😊😊😊
Babua is the best math's teacher of the world 🌎🌎❤
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❤❤❤❤❤❤
Hey 🔱👋😎 wheir are you from ♨️🤒
@@srgaming7786 I am from my house 🏠 😁😎😎
Oo I think you are from ⚠️? 🙃
Best nhi😊 best se bhi best hai sirf physicswallah platform ❣️💯💎🙏
Who is watching 1 day before exam😂😂
😂😂😂😂 SU WATI GARAI
You
Kon kon 95+% lana chata hai
😂😂😂😂😂😂
😊😊😊
Me bro😢
😊😊
Me bro 😢
1:29:16 value of x=2 and y=3
Hats off to you sir ❤for making video daily for us 🥹
2:46:36
Yeh dekh Ke Jana haste haste jawo gay
BTW I am not insulting sir just wanted to make others laugh.
Home work on 1:29:14
X = 2
Y = 3❤❤❤
Home work of ex 3.3 question no 2 part 3 ans 1:49:10
Cost of one bat will be 500 and cost of one ball be 50 ❤❤
Home work of ex 3.3 question 2 part 5 on 2:04:00
X= 7
Y= 9 🎉🎉🎉
1:29:15
X= 2
Y = 3
I score 72 out of 80 because of you...
Thnx
Kon kon pw ki lectures me hi pw ka ads dekhta hai😂
40:34 epic movement 😅😅
its moment
😂😂 bilkul
@@meenakshichoudhary3785😂😂 nhi sir move kr rhe the 😂😂 isliye epic movement 😂😂🤣🤣
Ajj mera birthday hai happy birthday bol do yarr🥲
Happy birthday to you yaar❤🎉🎉
@@saiandsarthakentertainment8818 ❤️
Bak🎉🎉🎉
Happy birthday😂❤
Thanks for the blessing guys 🥺
Ma bhagwan se parthna karta hu Jo bhi comments padg RHA ha vo acha marks de pass ho
Jaldi jaldi comments karo
Who want trigonometry first 😢
All the best 10thians😁
Thanks sir for posting helpful videos 😊 fav. Maths mentor❤
Sir hm ex 3.2 ke example 2 me 3 ko 3 se cut nahi kr sakte kya
Jisne like nahi kiya uske 90% confirm
Who notice in ex3.3 that ques 1 ans of part I is 19/5 value of x but sir write it 25-6/5 = 21/ 6
maine notice kiya
Kaun 100 💯 lana chahta hai
Tum 😂😂
PW is best platform in the field of education both in online and offline 🔥🙌💯
Your teaching type is vvvvvvery nice
Kon kon revise kr rha hai is video me🎉
Na bhai me to practice kar raha hu..
Mai bhi prectice kar raha joon
Ajjubhai app bhi tenth me 😭😭
Me
Exam is near
Nothing is clear
Because babua is hear 👍
Hard work Is never pay SADNESS 🥰🥰
Love you babua ❣️
300k ho gye☺️🎊🎉, Congratulations To Our Beloved😍 Pw Teachers❤And Uddanians🕊️
Is NCERT enough for basic maths
Nooo never ..you must do before 50 years paper
@@Stteller84😂😂
Sir basic maths walo ke liye ncert kafi h kyaa???
Best math teacher ❤😊
Sir aapko jitna thankyou bolu utana kaam h aapko pata h mujhe ya ch Kitna tough lag raha gha but aab aapse padhna ka baad ya ch mere liya kuch bhi nhi h 😅 thankyou thankyou so much sir love you so much sir ❤
1:49:02 answer is
Y is 50 and x is 500...
2:04:12 answer is y = 9 and x=7 so the fraction is 7/9....
Happy diwali jai shree ram🙏🙏🙏🙏🙏🙏 22 janaury ki hardik shubhkamnaayein🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉
2:7:41 superbbbbbb idea
thank youuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
soooooooooooooo Muchhhhhhhhhhhh SIR
Session 2024-25 10 th ke students attendence lagvaya ✋✋✋
1:33:04 I am getting X= -14 Y= 13 (By Elimination method) And By that My "M" is coming 5/-7
Legend are watching one day before exam legends?❌ failures 🔊
I am the legend 😂
Kon kon ajj dekh rha hai 😂
Take care too u sir ... Aapke alava hamra iss gola mai hai hi kon 😂 ❤
Kabhi Mera bhi comment viral hoga
As well as first comment 😂
2:04:26 maksad abdul
Exam is near
Nothing is clear
But don't fear
When pw is here
Love u all pw teachers🎉🎉
Maire comment b aik din viral. Hojayai ga .... Ruko.. jara sber kro
sir by mistake you write 3x+5y=1780 at 1.48.30 the right eq is 3x+5y=1750 😇😇😇😇😇😇😇😇😇😇😇😇😇😇😇😇😇😇😇
Love you sir for that type of teaching .
Sir the way you said "chpad ganju"😭😭😭😭😭
Just watching to see babua.. ❤
❤yes😊
@@Ayush2505r suiii.... 💀
Mera comment viral ho gya😊
Ritick sir 😎
Thank you so much
Hii
1:49:05 cost of one bat =500 rupees and cost of one ball=50 rupees
Sir 1:27:00 wale question ko simplify kr skte ha??
Sir apse padh ke maza hi aa jata ha ❤❤❤❤❤❤❤❤❤❤❤
Ex 3.2 Q-1(v) root 2 is missing Sir
2:52:44 fixed charge =X THAT IS ₹ 5
ADDITIONALCHARGE = Y THAT IS 3 ₹₹..
THNKUU ❤
Y = 15
@@swapniiiiiil no bro
Heyy
Thanks to PW I make my percentage in class 9 95.4
Sir please 🙏 after NCERT examplar also 🙏
Sir 3.5 , 3.6 exercise dlt ha kya app na one short ma is ka bhi questions cover karvaya ha..... Plzz can anyone answer
ye only 3 exercises
Board mein 95%+ lana hai mujhe
sabh samaj me aa raha hai sirrrrrrrr aap chinta mat karo😈
Thanks sir I am wait this video ❤❤❤❤🎉🎉🎉🎉😊😊😊😊😊😊🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻😇😇😇
sir kal meri exam hai.... me bohot confuse tha word problem se equations banane me but is video ne meri bohot help ki hai...... thank you sir
Sir case based study karne ki koi trick batao
Sir aap bahut acha padhate ho mein ise year hi aapki classes lgana shuru ki hi m ab 10th me hu ( 6 - May - 2024 )
Same maii bhi 10th maii huu iss year issi shame shuru Kara huu😊
2:26:02 wrong answer hai sir aapka😂😂