yours is a great service to the students community. many students who are unable to go for tution is enriched from yr lecture. God will bless abundantly. thank u so much sir🙏🙏🙏
Sir last sum neega thapa potu irukiga, temperature 298k but neega 373k poty irukiga, ncert la mistake ah ilana neega theryama potutigala sir? Thank you so much sir❤neega ilana na nijama chemistry la kasta paduven🥺keep going sir😊
5:40 sir oru small confusion! Molar enthalpy means H/n right sir Here stoichiometric value is actually the number of moles! So… can’t we cancel our the coefficients and the n value and just mention enthalpy of reactant - product 😅 Pls explain
sir numerical sum la 2 questions kettrukanga but neenga oru question ku dhaan answer panninga amount of heat required at 298 K epdi kandupidikkanum sir pls sollunga
Don't consider about that question , actually that question make some tough feel in this numerical but nothing because water can evaporate even at very low temperature also so not only 298K even suppose below this temperature also water can evaporate .That heat of vaporization of water is 40.656 kJ mol-1, so already they bring it in this numerical.
#CHEMISTRYTEACH
th-cam.com/users/CHEMISTRYTEACHu
Sir last time I saw your vedio the day before my exam and got more marks ur explanation is awesome tmrw is my exam and now also I'm watching ur vedio
Sir concept easyaaa purithu but sums clear Ra puriyala so sums kaaka oru video upload panuga sir . It will be helpful for us in neet
yours is a great service to the students community. many students who are unable to go for tution is enriched from yr lecture. God will bless abundantly. thank u so much sir🙏🙏🙏
THANK YOU SOOOO MUCH FOR YOUR VIDEO. EASILY UNDERSTANDABLE LECTURE. GO AHEAD SIR NOTHING WILL STOP YOUR SUCCESS. GOD BLESS YOU SIR.
thanks for your valuable wishes
Crystal clear explanation, thank you sir🎉
Supero super..sir..keep rocking...
KEEP ROCKING SIR...👍👍👍
Sir etha Mari chemistry 11th &12 syllabus aa erukura ella lesson uu neega upload pana romba use full aa erukum sir🙏 pls this is my kind request
Wonderful explanation
Pls pls pls upload videos daily sir to complete the 11th portion 🙏
sure
Sir, I just got one doubt from all these videos. Should we also study the enthalpy values?
not must.
Respected Sir... Pls clear my doubt.....∆ng =no of moles in product -no of moles in reactant ... Appo epdi 1 vanduchu.....
As i like ur video and understands every concept clearly so Sir can u do example and excersise questions of 11 and 12 chem ncert for all chapters
will try
Sir last sum neega thapa potu irukiga, temperature 298k but neega 373k poty irukiga, ncert la mistake ah ilana neega theryama potutigala sir?
Thank you so much sir❤neega ilana na nijama chemistry la kasta paduven🥺keep going sir😊
Sir One kind request please upload videos on chapter organic chemistry class 11 cbse
sure. As soon as possible
@@CHEMISTRYTEACHu thank you sir
Yes pls
Please upload remaining parts of thermodynamics and i want equilibrium chapter also. Pls sir
sure
All lesson chemistry video upload pannugga sir tamil la
Will upload soon
@@CHEMISTRYTEACHu pls sir,soon paththathu,very very very soon ah upload pannuga
5:40 sir oru small confusion! Molar enthalpy means H/n right sir
Here stoichiometric value is actually the number of moles! So… can’t we cancel our the coefficients and the n value and just mention enthalpy of reactant - product 😅
Pls explain
Viewers may also visit 'Learner's Console ' for this chapter too 🙏
Sir ∆ng value product (1)-reactant(1)= 0 varatha sir
Sir will u plz start the equblirium lesson sir plzz🙏🙏
sure. will start may be after two videos
sir numerical sum la 2 questions kettrukanga but neenga oru question ku dhaan answer panninga amount of heat required at 298 K epdi kandupidikkanum sir pls sollunga
Don't consider about that question , actually that question make some tough feel in this numerical but nothing because water can evaporate even at very low temperature also so not only 298K even suppose below this temperature also water can evaporate .That heat of vaporization of water is 40.656 kJ mol-1, so already they bring it in this numerical.
Ok sir thank u so much for this clear explanation 🙏🙏👍 pls do for 12th std also sir
Super, sir can you pls tell good teacher like you in TH-cam for teach maths, physics bcs I study for crack in jee pls reply me sir
actually i dont know pa. but numerous channels available here for jee and neet
In the problem section, the change in the number of moles (delta n) is zero. I do not understand how it will be 1?
Sir please upload ionic equilibrium chapter🙏🙏
sir appona delta H and delta r subscript H are both same ?
sir can you please say conclusion for the problem sum sir !!😅😅
Sir but answer for that question is 41.53Kj as per ncert book
sir konjan thermodynamic dutha video podunga sir pls sir
sure
thank you sir romba super nadathuringa sir
sir book question konjam modify eruku
sir ir value vanthu konjam mari eruku ncert la
ok no problem but try to understand the concept is enough
Very nice explanation