No, most likely is because of the natural resonance of the secondary coil. There is a parasithic capacitance between the turns of any coil, and it happens that the resonant frequency of the secondary is around 1.3MHz. You see that is a narrow band where the secondary coil output is higher than the primary input. Maybe he can try to trace a Bode plot?
@@sebastian19745 Agreed. The phase change would also seem to indicate a resonance peak (as does the oscilloscope trace). I should have watched more closely.
Super nice you matched the color on the scope with the color of the wire.
Yes, I bought the scope to match the coil!
The higher secondary voltage may be due to "transformer action" if the winding count is higher there, than in the primary (drive) winding.
@@Ross-z1n Very likely. Wish I had a current probe. They can be expensive.
No, most likely is because of the natural resonance of the secondary coil. There is a parasithic capacitance between the turns of any coil, and it happens that the resonant frequency of the secondary is around 1.3MHz. You see that is a narrow band where the secondary coil output is higher than the primary input. Maybe he can try to trace a Bode plot?
@@sebastian19745 That's a good point. I forgot about that. Thanks.
@@sebastian19745 Agreed. The phase change would also seem to indicate a resonance peak (as does the oscilloscope trace).
I should have watched more closely.
@@Ross-z1n That is why I would like to see a transfer curve in amplitude and phase. The said Bode plot.
The phase change of the output is as expected.
@@franzliszt3195 It does not happen with the SMD inductors.
@@tsbrownie It has to, but could be small. Or phase change could be very flat over the frequencies of the AM band.