@@Arijitgaming422 hmm vo mehh dekh chuka hun bahut accha padhaya hai sir ne full ncert + important examples aur sare concepts and formule cover kiye hai sir ne
Just a short trick for everyone.... To simplify iota to the power some big number like 70,90,123,1125 or anything just divide the power by 4 and the remainder will be your new iota's power 😊
ha sir 1:17:56 quection mere periodic test 1 and tution ki 3 exams me aaya hai trust me guys this is very important if anyone agree then please like so new students come to know this question's importance
1:39:15 the denominators are (2+5i) and (2-5i) so in the denominator by (a+b)(a-b)=a^2-b^2 so the denominator of the answer will be (2)^2-(5i)^2 which is 4+25 i.e., 29 therefore final answer should be -8/29
Sir at 1:42:32 , the question would be x²+ax+b=0 and the ans of that question is a)-4 , not 0 As the equation in the end is (b+a)i(2+a)=0+0i Therefore, a+2=0 ie a=-2 and similarly, b=2 Hence, a-b=-2-2=-4, which is the final answer
Homework question 43:27 Find multiplicative inverse of Under root of five +3¡ = 1/root 5 + 3¡ After Rationalise Answer will be Root 5-3i/14 z = Root 5/14-3i/14
*_Here are all the answers and corrections as per my solving_* ; 40:42 --> 307/442 + 599i/442 43:24 --> √5/14 - 3/14i 55:44 (Conjugate):- --> 63/25 + 16i/25 {Final Answer} 59:50 --> 1/√2 1:01:15 --> x = 3 y = -3 1:05:05 --> Part 2 Answer is 0 . (Imaginary part is 0) 1:39:14 --> The first answer should be -8/29 --> The second answer is 1/5 1:39:23 --> The answer is option (b) Y-axis ; as the value of x is 0 so we get , z = 0 + iy . 1:43:42 --> Option (b) 2 Could not solve the last Question....
This is the best video you can ever find on youtube for complex number I missed my school lectures due to some personal issues so I thought to watch it on youtube I was Ashu sir online student in class 10 so I knew him but never attended any of his lecture But after watching this video I am your fan sir It took me only 5 hours(as I first solve the answer by myself than watchs sir solutin,listening to him,doing ncert in middle) to understand this chapter But all my concepts are now clear Thank you so much sir My respect for you has increased a lot much higher📈📈📈📈📈📈📈📈📈📈📈 Thank you very much sir🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
1:42:20 Sir this question is Example 27 of Exemplar book, and it states that if 1- i, is a root of the equation x² + ax + b, where a, b belongs to R, then find the values of a and b.
Please tell that we take sign also int the root because value of complex part is -1/2 but when it comes under square root what we take -1/2^ or without sign 1/2^ Please reply soon I need your help
literally sir , its a awesome one shot , you cover all topics and most imp ques of ncert and pyqs ,thankuuu ssir , kl mera half yearly h its really helpful for me
sir ji question is not wrong, minus hi hoga, one root will be 1-i and one will be 1+i (since both roots will be conjugate of each other) so ans is -4 (A), 1:43:18
55:44 in the first step it is -4i instead of -2i therefore the ans is 63/25+16i/ 25
Yes bro even I also notice that 😢
Yes
Yes right 👍👍❤❤ i also notice
Yes bro 🙌....
Yes bro I also noticed
Vote for permutations and combinations super 👌 one shot 😊❤
Vote for Relation and functions onshot ❤
Ee karwa chuke hei
@@Arijitgaming422 hmm vo mehh dekh chuka hun bahut accha padhaya hai sir ne full ncert + important examples aur sare concepts and formule cover kiye hai sir ne
@@Sakshamtripathi. To fhir uska one shot kiyu??
To fir kyou@@Sakshamtripathi.
Bhai ye comment tb kiya tha jab maine dekha nhi tha vo@@vridhimehra6330
Just a short trick for everyone....
To simplify iota to the power some big number like 70,90,123,1125 or anything just divide the power by 4 and the remainder will be your new iota's power 😊
thanks buddy!!!
not all powers will be divisible by 4
We need only remainder@@Yappppyy
Because iota 4 ki value 1 hoti hai
Yes then the remaining will be iota's power@@Yappppyy
30:50 z= -242/27 -26i
40:56 z= 155/221 i + 205/442
43:32 z=√5/34 - 3/34i
55:44 z=63/25-16i/25
1:05:04 Im = 0
bhai 3rd wrong hai umder root5 /14+3/14 i
Bro your 43.52 sec question is wrong the denominator is 14 here 😊
Bhai tumhara 43:32 wala ans glt hai.. the correct answer is... √5/14 - 3i/14
bhai tumhara pehla answer bhi wrong hai , sahi answer yeh hai : 307/442 + 599i/442
Bhai 3rd wrong h
43:27 √5/8. - 3i/8
59:50 √2/2
1:01:16 x=3, y=-3
1:05:05 Im=0 Re=-1/3
1:39:18 -8/9 nhi hoga -8/29 hoga
1:39:37 x=0 so y-axis
1:50:23 (1+2b²+b²-a²+2ia+2abi)/2
Bhai bhai
First one is wrong u forgot to square 3
Yes
Second ans is also wrong..
30:37 2nd step is also wrong ..
is it only me that thinks ushank sir looks like ashu sir ... ???
Because they are brother's I guess🧐
Me too are they really brothers👾👾
No
@@kirandhanda6599 yes they are brothers❤
Brother from same mother😂
1:05:16
ii) ans ( Imaginary part will be 0)
ha sir 1:17:56 quection mere periodic test 1 and tution ki 3 exams me aaya hai
trust me guys this is very important
if anyone agree then please like so new students come to know this question's importance
1:39:15 the denominators are (2+5i) and (2-5i) so in the denominator by (a+b)(a-b)=a^2-b^2 so the denominator of the answer will be (2)^2-(5i)^2 which is 4+25 i.e., 29 therefore final answer should be -8/29
This one is actually correct sir ne square nhi liya
Ha
Any from arjuna🎉
Sir aap faf du plessis jaise lagte ho 😅
😂😂
Aaj mujhe pata chala m akela nhi hu😅🔥
Ha Bhai mujhe bhi lagta hai faf ke Bhai jaise hai sir
Mujhe bhi asa hi lgta hai bhai 😂😂😅😅
Hnn bhai shi bola 😂😂😂
1:39:37
z = x+iy
|x+iy-3| = |x+iy+3|
| ( x-3)+yi | = | (x+3)+iy) |
√(x-3)² + y² = √ (x+3)² + y²
Squaring both sides
x²+9-6x+y² = x²+9+6x+y²
-6x=6x
-6x-6x = 0
-12x = 0
x=0
z = 0+iy
Z lies in y axis
thank you so much
1:01:09 x=3, y=-3ans
Sir at 1:42:32 , the question would be x²+ax+b=0 and the ans of that question is a)-4 , not 0
As the equation in the end is (b+a)i(2+a)=0+0i
Therefore, a+2=0 ie a=-2 and similarly, b=2
Hence, a-b=-2-2=-4, which is the final answer
59:49 = 1/√2
1:01:20 = {y = -3} and { x = 3}
Homework question
43:27
Find multiplicative inverse of
Under root of five +3¡
= 1/root 5 + 3¡
After Rationalise
Answer will be
Root 5-3i/14
z = Root 5/14-3i/14
Bro wrong
correct😃😃😃
Wrong
Worng it's + bro
It's correct I think but if it's wrong ..... please tell the correct answer then..😊
59:38
Answer(ii)-1/√2
√2/2 is right
Time-30:55
Z=-242/27,-26i
Jiska same answer aaya h wo like kro 100 like target
40:58 Ans is 307/442 and 599i/442
43:32 Ans is √5/14 and -3i/14
1:05:05 Ans of Imaginary is 0
*_Here are all the answers and corrections as per my solving_* ;
40:42
--> 307/442 + 599i/442
43:24
--> √5/14 - 3/14i
55:44 (Conjugate):-
--> 63/25 + 16i/25 {Final Answer}
59:50
--> 1/√2
1:01:15
--> x = 3
y = -3
1:05:05
--> Part 2 Answer is 0 . (Imaginary part is 0)
1:39:14
--> The first answer should be -8/29
--> The second answer is 1/5
1:39:23
--> The answer is option (b) Y-axis
; as the value of x is 0 so we get ,
z = 0 + iy .
1:43:42
--> Option (b) 2
Could not solve the last Question....
SAME COULD NOT SOLVE IT STUCK IN EQUATION BRUHAA I THINK ITS WRONG
💀💀
(b+ia+iab)/(1+2b)
❤
in 1:39:23 can u tell me how you got that answer? like i did solved it! it came (i)^n only!
30:50 = (1/27-9)-26i
=(1-243/27)-26
ANS =(-242/27)-26i
1:13:45 yes sir aapne paid batch mai bhi bataya thaa
It will be 6+9i-4i-6i²/ 2-i+4i-2i² it is the 1st question of conjugate of a complex number
Sir you are a brilliant teacher for cbse i would recommend my juniors who are reading my comment for school exam
55:47
Answer is wrong
The correct answer is 63/25+16i/25
Thank you 🙏
No, the correct answer is 99/25 + 4i/5
same ans
@@notajitesh nope check ncert miscellaneous examples, ex-7
@@YushitRohida yeye i got it bro thnx
30:57 Z=-242/27-26i
1:16:25 sir prove me b/a= 2c/c2-1 hai but aapka answer c2+1 aaya hai❤
Brother/sister dekho:
a/bi = c2 + i2/ 2ci
a/bi = c2 - 1 / 2ci
Iska reciprocal ( ulta) kar do
b/a = 2c/ c2 -1
iota se iota kat gya h...
-1 hee hoga.
By mistake sir ne +1 likh diya h.
1:39:22
Answer is
Option(B) at y axis💕💕
Kaise
@@LOKESHPARMAR-d5x X=0 aarha mera toh😅 abhi kra just check bhi nhi kra toh syd ans b hii hoga
Any one from arjuna preparing for school exam 😂
Me
😅
One night before exam
Yes bhai Kal exam hai upr upr se revise krne aaya hu 😂 maths my weakest
Me
sir cojugate wala answer actually 63/25+16i/25 hoga ji
54:29 congujate 63/25 - 16i / 25 answer ❤
Wo hi to me sochu mera kaise glt aara h
1:39:40
Answer is option (B) y-axis
wonderful oneshot , truly informative yet interactive.. cheerful awesome, all concpts covered with miqs
This is the best video you can ever find on youtube for complex number
I missed my school lectures due to some personal issues so I thought to watch it on youtube
I was Ashu sir online student in class 10 so I knew him but never attended any of his lecture
But after watching this video I am your fan sir
It took me only 5 hours(as I first solve the answer by myself than watchs sir solutin,listening to him,doing ncert in middle) to understand this chapter
But all my concepts are now clear
Thank you so much sir
My respect for you has increased a lot much higher📈📈📈📈📈📈📈📈📈📈📈
Thank you very much sir🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
1:42:20 Sir this question is Example 27 of Exemplar book, and it states that if 1- i, is a root of the equation x² + ax + b, where a, b belongs to R, then find the values of a and b.
-2,2 then
If a-b then - 4
12:28 33/4, 3/4
13:42 5/8+0i
17:12 0+ i/256
19:17 (-6+√2)+(√3+2√6)i
Done ✅🤯
DO PRACTICE MORE IN MATHS IT WILL REALLY HELP YOU IN BOARDS OR IN ANY COMPETITION EXAM
THIS IS A VERY BENEFICIAL PLATFORM FOR MATHS 🙂✨
59:38 answer z =✓(1/2)²+i²=1/4-1=-3/4 ans
40:56 ans-307+599i/442
59:54 sir the answer is 1/√2
🎉✅
Please tell that we take sign also int the root because value of complex part is -1/2 but when it comes under square root what we take -1/2^ or without sign 1/2^
Please reply soon I need your help
@@virendrabahadursinghbaghel1113 because when we find modulus the negative sign changes to positive.
40:50
z= 127/90 +2i/5
43:20
z= √5/14 - 3i/14
59:48
|z| = 1/√2
1:01:14
x= 3, y= -3
1:05:08
0 because no imaginary part
1:16:20 sir here que proff and answer proff doesnot match please check there is mistake in last step
❤
Sir please check ✅
❤😊
2nd last step it will be 2(c^2 - 1) Instead of (c^2 +1)
1:21:11 Diljit Dosanjh Is Legend, He Is Everywhere 🥵💀
1:50:10 (b + ia) ans
Very very helpful ❤❤❤❤❤❤❤
59:31
Home work question
|z| = 1/√2
It's 1/√2
1:39:45 answer b 1:39:45
First question of conjugate is wrong!!!!!
when the bracket is opened it is written -2i instead of -4i
Yes
HW ques ncert wala
answer: 307+559i/442
40:59
307 nhi 312
@@rameshchander5253 nope its 307 only
@@rameshchander5253 bro its 307
307 + 599i / 844
@@sachi.00000 galat hai bro tera , sahi answer check kro
41:00 Sir the answer of this homework question is z = 307/442 - 599/442i
43:28 ans-√5/8-3i/8
sir best explaination that i get on youtube of this chapter, thank you so much sir.........♥
43:27
Home work question
(a+ib) = (√5/14 - 3i/14)
48:03 those who noticed
43:34 Sir the answer of this homework question is z = √5/14 - 3/14i
31:02 Sir LCM will be -242\27 and z = -242\27 - 26i
1:42:15 non-real roots occur in conjugate pair, so using sum and product of roots, b-a will be -4
1:39:02 me 25 aye ga denominator me apne 5 likha hai to answer aye ga -8/29
31:00
z= -(242/7) - 26i
literally sir , its a awesome one shot , you cover all topics and most imp ques of ncert and pyqs ,thankuuu ssir , kl mera half yearly h its really helpful for me
43:24 √5/14-3i/14
√5/4-3i/4
@@asfakahmed2339 gawar hai kya
Sir 1:16:56 ----~ question me denominator me c²-1 prove Krna tha but aapke answer me c²+1 aa rha hai ....😇
A complete example of quality education🗿
literally it is very much helpful sir for our exams .......Thankyou very much for this one shot.....🙏🙏💖💖
Sir One of the best One shot I seen in Class 11 class math topic ....Very nyc ❤❤❤❤ and u solve whole question so we can see where we mistake
Very nice lectures ❤
Good explanation
Thank you sir
Sir doubt bahut th.😢
Par,
Ab nahi ha😊
Dar sa lagta th😢
Par
Ab nahi ha😊
Thanks for this video sir❤
1:01:13 sir iska answer will be x=3 and y=-3
Big fan sir really faf du plessis
43:42 answer root 5/14-3/14i
56:28 Sir, the correct answer for this question is 63/25 + (16/25)i
1:50:50 THANKYOU SO MUCH SIR THIS LECTURE IS VERY HELPFUL FOR ME🥰🥰🥰🥰🥰
1:50:10 the answer is b+ia
Sir, u are amazing and i am watching ur video for the first time and i love it. I completely understand this chapter only in 1 lecture.
1:05:15 (ii) answer imaginary part is =0
Every one talk about ritiknsir and shobhit sir why not for Ushank sir he is also one of the best😢.
You are from which aps
Because he is not good looking
@@Sachin_Kalwaaar Teri maa ki
43:31 ka answer √5/14-3/14i
Sir aaj tak kissi ki video pe comment nhi kiya ye lecture dil se bohot ach lga to bss aap ke liye comment kr rha hu
Nice lecture sir..😊
Sir gajab solve karte hain aap
43:20 answer is
√5+3i/13+13
Glt
14 hoga
kaisa explain karo
1:01:14 x=-7 y=-3
Bhai Teri demand bahut jyada hai snf me😅
I think your ans is wrong
Right ans is 3,-3😅
loved it sir thank u so much
59:51 1/√2
You explained this chapter very well😊
Meri taraf se sir apke pairo me parnam 🙏🏼🙏🏼
Bhut acha Samjate ho app , ❤❤❤❤❤
really Best teacher ever.....
1:39:41 option b z lies in y axis or imaginary axis
56:40 2i*2=4i
sir ji question is not wrong, minus hi hoga, one root will be 1-i and one will be 1+i (since both roots will be conjugate of each other) so ans is -4 (A), 1:43:18
Vote for sequence and series super one shot ❤❤
Thank you so much Sir for the lecture ❤❤❤
Bro do u know tarun khandelwal sir
1:39:12 / 1:51:41 Sir don't get me wrong but in 2nd step there should be 29 instead of 9 , I guess in hurry you forgot 2.
1:01:19 .... X =3 and Y= -3
41:00
z = 307/442 +599i/442
@56.43 wrong ans.... right ans is 63-16i/25
@56.43 wrong ans.... right ans is 63-16i/25
1:07:05 Sir simply take modulas instead of conjucate
SIR 1:16:25 PE b/a = 2c/c square -1prove krna ha pr aapka answer b/a = 2c / c square +1 aa rha ha pls correct and explained it again sir
maybe question is wrong
Question is not wrong sir 2c square + i square common lena tha aur i square ki value -1 aa jayegi
43:27 The answer is √5/14-3i/14 ✅
the answer of multiplicative inverse is root5/14 - 3i/14
55:02 mistake in multiplying -2i and 2
yess