Iodoform test of acetone

The famous iodoform test is here. Carbonyl compounds having ketomethyl group gives yellow crystalline ppt of CHI3 with characteristic clinical smell. This is a wonderful reaction and very useful for distinguish purpose.

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[@insightsofchemistry-withsa9009]

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This video deserves more views

[@insightsofchemistry-withsa9009]

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[@harsh.sharma]

I wouldn't have wasted my class 11th if he were my Chem teacher....

[@mimimaitreyee8843]

I wish you were the chemistry teacher of my school...

[@Ashish-jn8hs]

Sir, your precision in choosing appropriate words, length of explanation and conducting the experiment is commendable. Fantastic video!

[@insightsofchemistry-withsa9009]

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[@mansilohia141]

Tomorrow is mh practical nd now I'm properly nd completely able to do mh best ..
Tq sir ❤️😇

[@listenyourinnervoice3425]

Thank you sir for amazing explanation... I wish we had a chemistry teacher like u in our school..

[@insightsofchemistry-withsa9009]

Thank you 👍😊

[@Anonymous-lf8dd]

Should the NaOH solution be conc. or dil. ?

[@insightsofchemistry-withsa9009]

Dilute.. But not very dilute.. Moderate concentration rather

[@eduardotomaslagosmolina5271]

I will try this variation as I failed to obtain a good yield using another technique.

[@vaishnavijadhav101]

thank you so much sir
for such a great explanation

[@s75swagatatripathi73]

Beautifully you have explained sir... Thank you sir 🙏🙏🙏

[@insightsofchemistry-withsa9009]

Thank you ☺️

[@angelicajoven3310]

Sir, can you explain the principle behind how/why did the acetone gave positive result in iodoform test? Thank you!

[@insightsofchemistry-withsa9009]

Any carbonyl compound having ketomethyl group (CH3CO-) gives positive response to iodoform test. For details, you have to see the mechanism.

[@vikrantsingh1469]

👍 nice 👍

[@fromandromeda4013]

Thank you for clear explanation

[@insightsofchemistry-withsa9009]

Welcome.. 👍

[@shamikhan267]

Thanks sir for such a great explanation

[@tpacman8712]

Thank u sir for such nice illustrations and explanation

[@insightsofchemistry-withsa9009]

Welcome.. 😊😊

[@happyrockstar5917]

Thank you sir for this beautiful chemical test❤️❤️❤️

[@insightsofchemistry-withsa9009]

Welcome.. 😊

[@jagdishsad7617]

Thanks

[@samimmedico]

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From Burdwan Al Ameen Mission..❤️

[@insightsofchemistry-withsa9009]

Thank you🙏🙏

[@manju4601]

Nice Explaination sir.... Everything is clear in this video...
There can't be any question for doubt!

[@insightsofchemistry-withsa9009]

Thank you... 🙂🙂

[@KashafNaeem.]

Ma Sha Allah sir awesome video keep it up

[@insightsofchemistry-withsa9009]

Thank you🙏

[@lakshmir2358]

don't use plastic gloves while heating. plain yellow was not visible

[@insightsofchemistry-withsa9009]

Thanks for the suggestions... Will try to follow it.. 🙂🙂

[@mathsknowledgevideointamil7728]

Thank you sir

[@jassalji4126]

Sir will u please clear my doubt that ......what is the need to make the solution alkaline ??

[@insightsofchemistry-withsa9009]

See the mechanism of haloform reaction. It is a base catalysed reaction. The acidic alpha hydrogen of acetone must be abstracted by a base and that is why alkaline medium is necessary.

[@jassalji4126]

@@insightsofchemistry-withsa9009 thanku sir now i understand that it is the first step for the propagation of reaction in which hydroxyl group will act as nucleophile and remove abstract a alpha hydrogen so that reaction can proceed further. Thanks sir for ur reply 😇

[@insightsofchemistry-withsa9009]

@@jassalji4126 for the first three steps OH will act as base and in the fourth step it will act as nucleophile to attack the carbonyl carbon and CX3(-) will be released as leaving group to give the haloform CHX3

[@rimpa9966]

Very nice Vedio sir. . Very useful

[@insightsofchemistry-withsa9009]

Thank you

[@pratikbagthariya7089]

Thanks 👍😌

[@RaviSingh-mt1rt]

Thank you sir

[@طريقالتوبه-س3غ]

What the adventage from NaOH add for synthesis idoform

[@طريقالتوبه-س3غ]

And calculate the yeild to idoform

[@saifhaameem4060]

Very nice explanation

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Thanks

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Veryy usefull vedio for practical

[@insightsofchemistry-withsa9009]

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[@aditi3782]

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[@insightsofchemistry-withsa9009]

Thank you... 😊

[@tabikhan6838]

What is normality of NaOH solution used here ??

[@insightsofchemistry-withsa9009]

It is 5(M) solution of NaOH

[@mimimaitreyee8843]

Sir you are just incredible...

[@insightsofchemistry-withsa9009]

Thank you 😊

[@SubhamSingh-cf2zj]

Best channel for practicals

[@insightsofchemistry-withsa9009]

Thank you